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The standard deviation of daily iron intake in the larger population of \(9-\) to 11 -year-old boys was \(5.56 \mathrm{mg}\). We want to test whether the standard deviation from the low-income group is comparable to that of the general population. State the hypotheses that we can use to answer this question.

Short Answer

Expert verified
Compare the low-income group standard deviation to 5.56 mg.

Step by step solution

01

Understanding the Problem

We have a population of 9- to 11-year-old boys with a known standard deviation of daily iron intake, which is \(5.56\, \text{mg}\). We want to test if the standard deviation for a low-income group of the same age range is comparable to this general population.
02

Define the Null Hypothesis

The null hypothesis \(H_0\) is a statement that assumes no effect or no difference. Here, it assumes that the standard deviation of daily iron intake in the low-income group is equal to that of the general population. Thus, we state: \(H_0: \sigma = 5.56\, \text{mg}\).
03

Define the Alternative Hypothesis

The alternative hypothesis \(H_a\) is what we want to prove. It suggests that there is a significant difference between the standard deviation of the low-income group and the general population. Therefore, we state: \(H_a: \sigma eq 5.56\, \text{mg}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Standard deviation is a measure of how spread out the numbers in a data set are. In our context, it tells us how much daily iron intake varies among 9- to 11-year-old boys. For example, a low standard deviation means that most values are close to the mean or average intake, while a high standard deviation indicates more variation. Standard deviation is essential when comparing different groups, like in our exercise, where we're interested in whether a low-income group's standard deviation diverges from the larger population. To calculate standard deviation, you first find the mean of the data set. Then, measure how far each data point is from this mean, square those differences, and finally average them to get the variance. The square root of this variance is the standard deviation. In formula form, it's expressed as \( \sigma = \sqrt{\frac{1}{N} \sum_{i=1}^{N} (x_i - \mu)^2} \), where \( \sigma \) is standard deviation, \( x_i \) is each value, \( \mu \) is the mean, and \( N \) is the number of data points.
Null Hypothesis
The null hypothesis (often denoted as \( H_0 \)) is a statement that suggests there is no effect or no difference in the situation or population being studied. In our exercise, the null hypothesis implies that the standard deviation of daily iron intake in the low-income group is the same as that of the general population of 9- to 11-year-old boys. This means \( H_0: \sigma = 5.56\, \text{mg} \). The main purpose of the null hypothesis is to provide a baseline or default position that the observed data will be tested against. When performing hypothesis testing, if the data provides enough evidence to reject the null hypothesis, we can consider that there might be an effect or difference. If not, the null hypothesis remains plausible.
Alternative Hypothesis
The alternative hypothesis (denoted as \( H_a \)) proposes a contrary proposition to the null hypothesis. It is essentially what researchers aim to prove or verify through their analysis. In our context, the alternative hypothesis suggests that the standard deviation of iron intake in the low-income group is not equal to that of the general population. Therefore, it is expressed as \( H_a: \sigma eq 5.56\, \text{mg} \).Hypothesis testing involves using statistical evidence to make a decision about which hypothesis is more likely to be true. If the data collected shows a significant difference from what is expected under the null hypothesis, we may reject \( H_0 \) in favor of \( H_a \). The alternative hypothesis thus represents the possibility of true variability or effect that researchers suspect or wish to confirm.

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Most popular questions from this chapter

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