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An experiment is designed to test the potency of a drug on 20 rats. Previous animal studies have shown that a \(10-\mathrm{mg}\) dose of the drug is lethal \(5 \%\) of the time within the first 4 hours; of the animals alive at 4 hours, \(10 \%\) will die in the next 4 hours. What is the probability that 2 rats will die in the 8-hour period?

Short Answer

Expert verified
The probability that 2 rats will die in 8 hours is approximately 0.257.

Step by step solution

01

Understanding the Problem

We are tasked with finding the probability that exactly 2 out of 20 rats will die within an 8-hour period. There are two contributing factors to rat mortality: a 5% lethality within the first 4 hours and 10% of the survivors dying in the following 4 hours.
02

Calculating Initial Die Probability

We first calculate the probability of a rat dying within the first 4 hours. Since the probability is given as 5%, this can be expressed as a decimal: \( P(D_1) = 0.05 \). The probability of surviving the first 4 hours is then \( P(S_1) = 1 - P(D_1) = 0.95 \).
03

Calculating Next Die Probability

For rats that survive the first 4 hours, the probability of dying in the subsequent 4 hours is 10%. Thus, for a rat that survived the first phase, the probability of dying in the second phase is \( P(D_2|S_1) = 0.10 \). Therefore, the probability of surviving both phases is \( P(S_2|S_1) = 0.90 \).
04

Total Probability of Dying in 8 Hours

We need the combined probability of a rat dying within 8 hours, either in the first or second phase. This can be found by adding the probabilities of dying in the first phase and dying in the second phase:\[\begin{align*}P(D_{ ext{total}}) & = P(D_1) + P(S_1) \times P(D_2|S_1) \& = 0.05 + 0.95 \times 0.10 \& = 0.05 + 0.095 \& = 0.145.\end{align*}\]
05

Using Binomial Probability Formula

With 20 rats and a total death probability (P(D_{ ext{total}} = 0.145e), we use the binomial probability formula to find the probability exactly 2 rats die:\[ P(X = 2) = \binom{20}{2} (0.145)^2 (1 - 0.145)^{18} \].
06

Calculating Exact Probability

Calculate the probability using the values computed:\[ P(X = 2) = \frac{20 \times 19}{2 \times 1} (0.145)^2 (0.855)^{18} \].After calculations, we find the probability: approximately 0.257.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability calculations
When it comes to understanding biostatistical problems, probability calculations are the foundation. In the given exercise, we wanted to find out how likely it was for exactly 2 out of 20 rats to die within an 8-hour period.
This involves calculating the likelihood of certain events happening over a set period. Here, it combines understanding the probability of a rat dying in distinct periods, one within the first 4 hours and then within the following 4 hours.
  • Initially, a 5% chance of a rat dying in the first 4 hours meant converting this into a decimal in mathematical terms: \( P(D_1) = 0.05 \).
  • This also required calculating the chance of a rat surviving that same time frame: \( P(S_1) = 0.95 \).
  • Further on, for rats surviving the initial period, they had another 10% chance of dying within the next 4 hours: \( P(D_2|S_1) = 0.10 \).
Understanding these calculations is not just academic—it has practical importance in fields like biostatistics, where it's essential to predict outcomes based on known probabilities. The ability to convert percentages to decimals and effectively sequence probabilities to get an overall likelihood forms the bedrock of probability calculations.
Binomial distribution
The binomial distribution is a statistical tool often used when determining the probability of a fixed number of successes in a series of independent experiments. In our scenario, the 'success' is when exactly 2 out of 20 rats die, which might sound counterintuitive, but within statistical analysis, a 'success' denotes the outcome of interest.
The formal expression of the binomial probability formula is: \[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}, \] where \(n\) is the total number of trials (20 rats, in our case), \(k\) is the number of times 'success' is expected to happen (2 rats dying), and \(p\) is the probability of success (calculated here as 0.145).
  • The term \( \binom{20}{2} \) represents the number of different ways we can choose 2 rats from a total of 20.
  • The terms \( (0.145)^2 \) and \( (0.855)^{18} \) account for the probability of exactly 2 rats dying while the remaining 18 survive.
By applying this, we find out the likelihood of our event to be approximately 0.257. This understanding helps in various fields like experimental design and clinical trials, where predicting likely outcomes is crucial.
Experimental design
The setup of experiments and how they're structured plays a critical role in achieving accurate results and meaningful conclusions. Biostatistics heavily relies on smart experimental design to monitor and evaluate the effects of treatments or drugs effectively. In the described scenario, an experiment was conducted to test the potency of a drug on rats.
Designing an experiment involves multiple considerations:
  • Sample Size: Here, using 20 rats was crucial in providing a sufficient sample to draw statistically significant conclusions.
  • Event Timing: Monitoring outcomes over defined periods (like the first and next 4 hours in the exercise) is important to distinguish between immediate and later effects.
  • Probability Assessment: Gathering historical data (past experiments suggesting a 5% mortality rate) helps in setting the proper context and understanding what to expect.
Such strategy ensures that when analyzing the results, like determining the likelihood of mortality, the findings are more reliable and can inform future research or clinical practices. Appropriately arranged experiments drive the efficacy and replicability, which are vital in fields like drug development.

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Most popular questions from this chapter

A study was conducted among 234 people who had expressed a desire to stop smoking but who had not yet stopped. On the day they quit smoking, their carbonmonoxide level (CO) was measured and the time was noted from the time they smoked their last cigarette to the time of the CO measurement. The CO level provides an "objective" indicator of the number of cigarettes smoked per day during the time immediately before the quit attempt. However, it is known to also be influenced by the time since the last cigarette was smoked. Thus, this time is provided as well as a "corrected CO level," which is adjusted for the time since the last cigarette was smoked. Information is also provided on the age and sex of the participants as well as each participant's self-report of the number of cigarettes smoked per day. The participants were followed for 1 year for the purpose of determining the number of days they remained abstinent. Number of days abstinent ranged from 0 for those who quit for less than 1 day to 365 for those who were abstinent for the full year. Assume all people were followed for the entire year. (TABLE CAN NOT COPY) Develop life tables for subsets of the data based on age, gender, number of cigarettes per day, and CO level (one variable at a time). Given these data, do you feel age, gender, number of cigarettes per day, and/or CO level are related to success in quitting? (Methods of analysis for lifetable data are discussed in more detail in Chapter \(14 .\) )

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