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Growing child: A certain girl grew steadily between the ages of 3 and 12 years, gaining \(5 \frac{1}{2}\) pounds each year. Let \(W\) be the girl's weight, in pounds, as a function of her age \(t\), in years, between the ages of \(t=3\) and \(t=12\). a. Is \(W\) a linear function or an exponential function? Be sure to explain your reasoning. b. Write an equation of change for \(W\). c. Given that the girl weighed 30 pounds at age 3 , find a formula for \(W\).

Short Answer

Expert verified
a. Linear, because weight increases by a constant amount. b. \(W(t) = 5.5t + C\). c. \(W(t) = 5.5t + 13.5\).

Step by step solution

01

Identify the Type of Function

To determine if the function is linear or exponential, we examine the relationship between weight \(W\) and age \(t\). Since the girl gains a constant amount of weight (\(5 \frac{1}{2}\) pounds) each year, the change in weight is consistent. This indicates a linear function because exponential functions involve a constant percentage change, not a constant absolute change.
02

Write the Equation of Change

For a linear function, the equation can be expressed in the form \(W = W_0 + rt\), where \(r\) is the rate of change. Given the girl gains \(5 \frac{1}{2}\) pounds each year, the rate of change \(r\) is \(5.5\). The equation of change for \(W\) is \(W(t) = 5.5t + C\), where \(C\) is a constant.
03

Determine the Initial Condition

The problem states that the girl weighed 30 pounds at age 3. This provides the initial condition necessary to find the constant \(C\). Substituting into the equation \(W(3) = 5.5 \cdot 3 + C\), we get \(30 = 16.5 + C\).
04

Solve for the Constant

Solve for \(C\) by subtracting \(16.5\) from both sides: \(C = 30 - 16.5 = 13.5\). This gives us the complete formula for \(W\): \(W = 5.5t + 13.5\).
05

Formulate the Final Equation

Substitute the constant back into the linear equation: \(W = 5.5t + 13.5\). This equation models the girl's weight as a function of her age.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Weight as a Function of Age
The concept of weight as a function of age can be illustrated through the growth pattern of a child. In the given exercise, we observe a young girl who steadily gains weight over time. Her weight increase by a specific amount each year can be described using a linear function. This is because a linear function, unlike an exponential function, shows a predictable, constant change over time. Each year, the girl gains exactly \(5 \frac{1}{2}\) pounds, representing a straightforward connection between age and weight.

Functionally, when we talk about weight \(W\) as a function of age \(t\), it essentially means that for every input of age, there is a singular output of weight. It allows you to predict how much the girl weighs at a specific age, given her uniform growth pattern. Such a perspective makes it easier to understand how linear models can effectively describe certain real-life phenomena, such as growth rates, that occur linearly.
Rate of Change
In the context of linear functions, the rate of change is a fundamental concept that describes how one quantity changes with respect to another. For the girl's weight, the rate of change is \(5 \frac{1}{2}\) pounds per year. This means that every year, irrespective of her starting weight, she consistently gains the same amount of weight.

The rate of change is represented as \(r\) in the equation of a linear function. It provides a constant value that is multiplied by the independent variable, in this case, age \(t\). Understanding the rate of change allows us to see the linear progression of weight over time. Without this constant, we'd lack a clear description of how the dependent variable (weight) is adjusted as the independent variable (age) increases.

This simple and predictable nature of linear change is what distinguishes it from exponential change, which involves multiplication factors and results in curved graphs. Linear changes, like the girl's weight gain, reflect constant increments, easily visualized as straight lines on a graph.
Equation of Change
The equation of change for a linear function is essentially the formula that models the relationship between two variables. In this scenario, we derive this equation based on the details provided about the girl's growth. The linear function is expressed in the form \(W(t) = rt + C\), where \(r\) is the rate of change and \(C\) is the y-intercept, or initial condition.

To construct the equation of change, it’s crucial to determine both the rate of change and the initial condition. The exercise specifies that the girl’s weight at age 3 was 30 pounds, which serves as the background for finding the constant \(C\). Using the formula \(W(t) = 5.5t + C\) and knowing \(W(3) = 30\), we solve for \(C\) and find it to be 13.5.

This gives us the complete equation \(W(t) = 5.5t + 13.5\). Here, \(W(t)\) expresses weight as a function of age, showing that for any year \(t\) within the given range, the girl’s weight can be easily calculated. This equation of change is not only vital for predicting future weights but also enhancing our understanding of linear relationships by providing a clear mathematical representation of such processes.

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Most popular questions from this chapter

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