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Free fall subject to air resistance: Gravity and air resistance contribute to the characteristics of a falling object. An average-size man will fall $$ S=968\left(e^{-0.18 t}-1\right)+176 t $$ feet in \(t\) seconds after the fall begins.a. Plot the graph of \(S\) versus \(t\) over the first \(5 \mathrm{sec}-\) onds of the fall. b. How far will the man fall in 3 seconds? c. Calculate \(\frac{d S}{d t}\) at 3 seconds into the fall and explain what the number you calculated means in practical terms.

Short Answer

Expert verified
The man falls approximately 504.7 feet in 3 seconds. The velocity at 3 seconds is around 65.1 feet per second, indicating the speed of the fall including air resistance.

Step by step solution

01

Understanding the Equation

The given equation for the distance fallen in terms of time is \( S(t) = 968 \left(e^{-0.18 t} - 1\right) + 176t \). This equation combines exponential decay \( e^{-0.18t} \), representing air resistance, and a linear component \( 176t \), representing constant acceleration due to gravity over time.
02

Plotting the Graph of S vs t

To plot the graph of \( S(t) \) from \( t = 0 \) to \( t = 5 \) seconds, compute \( S \) at several values of \( t \) (e.g., 0, 1, 2, 3, 4, 5), find the corresponding \( S(t) \) values, and plot these points on a graph. Use software or a calculator to assist in plotting the exponential and linear components accurately.
03

Calculate Distance at 3 Seconds

Plug \( t = 3 \) into the equation to find \( S(3) \). Calculate: \[ S(3) = 968 \left(e^{-0.18 imes 3} - 1\right) + 176 imes 3 \]. Compute \( e^{-0.54} \) using a calculator, substitute and solve for \( S(3) \).
04

Differentiate S(t) to Find Velocity

Differentiate the function \( S(t) \) with respect to \( t \) to find the velocity: \( \frac{dS}{dt} = \frac{d}{dt}[968 \left(e^{-0.18 t} - 1\right) + 176t] \). This gives: \[ \frac{dS}{dt} = 968(-0.18)e^{-0.18t} + 176 \].
05

Calculate Velocity at 3 Seconds

Substitute \( t = 3 \) into \( \frac{dS}{dt} \) to find the velocity at 3 seconds: \[ \frac{dS}{dt}|_{t=3} = 968(-0.18)e^{-0.54} + 176 \]. Compute the value to get the velocity at \( t = 3 \) seconds.
06

Interpret the Velocity

The calculated velocity at \( t = 3 \) represents the instantaneous rate of change of the distance with respect to time, or how fast the man is falling at 3 seconds. It indicates the speed of the fall at that specific moment, incorporating both gravity and air resistance effects.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions, like the one observed in the equation \( S = 968(e^{-0.18t} - 1) + 176t \), often model natural processes such as cooling, population growth, or forces like air resistance. Here, the term \( e^{-0.18t} \) exhibits exponential decay, indicating how the resistance slows the falling object over time. The exponential function is a mathematical representation of scenarios where a constant percentage of change occurs over equal time intervals.
- **Exponential Decay**: This is when the quantity decreases at a rate proportional to its current value, characterized by a negative exponent as seen in \( e^{-0.18t} \). - **Air Resistance Model**: In this context, \( e^{-0.18t} \) reflects the decaying influence of air resistance on the man, slowing him more as time progresses.
By understanding exponential functions, students can model and predict behaviors in complex situations like falling with air resistance, blending calculus with practical physics.
Velocity Calculation
Calculating velocity is essential in understanding motion dynamics, especially in physics problems involving falling objects. Velocity is the rate of change of distance concerning time, denoted mathematically by the derivative. In this exercise, we model velocity by differentiating the distance equation \( S(t) = 968(e^{-0.18t} - 1) + 176t \).
  • **Differentiation**: To find the velocity, take the derivative of \( S(t) \) with respect to \( t \), yielding \( \frac{dS}{dt} = 968(-0.18)e^{-0.18t} + 176 \).
  • **Velocity Interpretation**: When evaluated at \( t = 3 \) seconds, this provides the velocity at that specific moment in time. Using calculus, students can appreciate how velocity changes dynamically with both linear forces like gravity and resistive forces like air drag.
By understanding the change in distance over time, students can connect theoretical calculus with real-world movement scenarios.
Air Resistance
Air resistance, a type of frictional force, acts opposite to the motion of objects through the air and significantly impacts how they fall. Objects falling through a fluid (e.g., air) experience a force that exponentially decreases speed over time, modeled by the term \( e^{-0.18t} \) in our exercise.
- **Impact on Falling Objects**: This force is directly tied to the velocity and surface area of the object, working more intensely the faster the object moves.- **Practical Observations**: In scenarios like sky diving or parachuting, air resistance becomes a crucial consideration. It not only slows down descent but also influences the shape and duration of the fall.
Understanding air resistance through math models allows predictions on how different objects behave when dropped from heights, highlighting calculus's role in solving practical physics problems.
Graphing Functions
Graphing functions is a practical way to visualize mathematical relationships, aiding comprehension and illustrating physical phenomena. In this case, graphing the function \( S(t) = 968(e^{-0.18t} - 1) + 176t \) over the first 5 seconds provides insight into the interplay of gravity and air resistance.
  • **Creating the Graph**: By calculating \( S \) for various \( t \) values from 0 to 5, plotted points reveal the object's displacement over time acutely.
  • **Insights from Graphs**: The curve typically depicts an initial steep rise as gravity predominates, before leveling off as air resistance balances the forces. This visualization facilitates understanding of how initial rapid changes in distance slow over time due to resistance.
Graphing not only helps in reinforcing learned concepts but also provides clear, visual methods for interpreting and predicting object movement in creative and scientifically rigorous ways.

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Most popular questions from this chapter

Radioactive decay: The amount remaining \(A\), in grams, of a radioactive substance is a function of time \(t\), measured in days since the experiment began. The equation of change for \(A\) is $$ \frac{d A}{d t}=-0.05 A $$ a. What is the exponential growth rate for \(A\) ? b. If initially there are 3 grams of the substance, find a formula for \(A\). c. What is the half-life of this radioactive substance?

Other models of drag due to air resistance: When some objects move at high speeds, air resistance has a more pronounced effect. For such objects, retardation due to air resistance is often modeled as being proportional to the square of velocity or to even higher powers of velocity. a. Arifle bullet fired downward has an initial velocity of 2100 feet per second. If we use the model that gives air resistance as the square of velocity, then the equation of change for the downward velocity \(V\), in feet per second, of a rifle bullet is $$ \frac{d V}{d t}=32-r V^{2} . $$ If the terminal velocity for a bullet is 1600 feet per second, find the drag coefficient \(r\). b. A meteor may enter the Earth's atmosphere at a velocity as high as 90,000 feet per second. If the downward velocity \(V\), in feet per second, of a meteor in the Earth's atmosphere is governed by the equation of change $$ \frac{d V}{d t}=32-2 \times 10^{-18} V^{4}, $$ how fast will it be traveling when it strikes the ground, assuming that it has reached terminal velocity?

The acceleration due to gravity: From the time of Galileo, physicists have known that near the surface of the Earth, gravity imparts a constant acceleration of 32 feet per second per second. Explain how this shows that if air resistance is ignored, velocity for a falling object is a linear function of time.

Eagles: In an effort to restore the population of bald eagles, ecologists introduce a breeding group into a protected area. Let \(N=N(t)\) denote the population of bald eagles at time \(t\). Over time, you observe the following information about \(\frac{d N}{d t}\). \- Initially, \(\frac{d N}{d t}\) is a small positive number. \- A few years later, \(\frac{d N}{d t}\) is a much larger positive number. \- Many years later, \(\frac{d N}{d t}\) is positive but near zero. Make a possible graph of \(N(t)\).

An investment: You open an account by investing \(\$ 250\) with a financial institution that advertises an APR of \(5.25 \%\), with continuous compounding. What account balance would you expect 1 year after making your initial investment?

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