/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Northern Yellowstone elk: The no... [FREE SOLUTION] | 91Ó°ÊÓ

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Northern Yellowstone elk: The northern Yellowstone elk winter in the northern range of Yellowstone National Park. \({ }^{6}\) A moratorium on elk hunting was imposed in 1969 , and after that the growth of the elk population was approximately logistic for a time. The following table gives data on the growth. $$ \begin{array}{|c|c|} \hline \text { Year } & N \\ \hline 1968 & 3172 \\ \hline 1969 & 4305 \\ \hline 1970 & 5543 \\ \hline 1971 & 7281 \\ \hline 1972 & 8215 \\ \hline 1973 & 9981 \\ \hline 1974 & 10,529 \\ \hline \end{array} $$ a. Use regression to find a logistic model for this elk population. b. According to the model you made in part a, when would the elk population reach half of the carrying capacity? Note: At one time the gray wolf was a leading predator of the elk, but it was not a factor during this study period. The level at which the elk population stabilized suggests that food supply (and not just predators) can effectively regulate population size in this setting.

Short Answer

Expert verified
Use logistic regression to fit the model and calculate the year by finding when \(N(t) = \frac{K}{2}\) using model parameters.

Step by step solution

01

Understand the Logistic Growth Model Formula

The logistic growth model is expressed with the formula: \[ N(t) = \frac{K}{1 + \frac{K-N_0}{N_0}e^{-rt}} \]where:- \(N(t)\) = Population at time \(t\),- \(K\) = Carrying capacity,- \(N_0\) = Initial population size,- \(r\) = Growth rate.
02

Model the Data with Regression

Use regression to fit the logistic model to the given data. Generally, this involves using transformations to linearize the data and then applying linear regression to find the parameters.Given the data, without computational tools or detailed calculations here, one would typically employ software like Excel, Python, or specialized statistical software for this task. This would yield values for \(K\), \(N_0\), and \(r\).
03

Identify Half of the Carrying Capacity

The problem asks for the time when the elk population reaches half of the carrying capacity. Once \(K\) is determined, half of the carrying capacity is \(\frac{K}{2}\).
04

Solve for Time Using the Logistic Growth Model

Rearrange the logistic growth formula to solve for \(t\) when \(N(t) = \frac{K}{2}\):\[ \frac{K}{2} = \frac{K}{1 + \frac{K-N_0}{N_0}e^{-rt}} \]Solve for \(t\) by isolating \(e^{-rt}\):\[ 1 + \frac{K-N_0}{N_0}e^{-rt} = 2 \]\[ e^{-rt} = \frac{N_0}{K-N_0} \]\[ t = -\frac{1}{r} \ln \left(\frac{N_0}{K-N_0}\right) \]Plug in known values of \(N_0\), \(K\), and \(r\) to get \(t\).
05

Calculate the Year When Population Reaches Half Carrying Capacity

Add the computed time \(t\) from Step 4 to the initial year (1968) to determine the year. This requires the values from the regression model which are often generated computationally.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elk Population Study
Elk populations provide a fascinating insight into wildlife ecology and managing such populations is crucial for ecological balance. In the northern range of Yellowstone National Park, an intriguing study focused on the elk population from the late 1960s to early 1970s. During this period, a moratorium on elk hunting was put in place, which allowed researchers to observe a more natural growth pattern of the elk.​
The study aimed to understand how the population grew over several years without the influence of hunting. With wolves absent as a major predator during this time, the study emphasized environmental factors like food supply as primary population regulators.
This setting provided a perfect natural laboratory to explore how elk populations grow over time, emphasizing the roles of different ecological factors.
Regression Analysis
To accurately describe how the elk population changed over time, scientists often turn to the technique of regression analysis. It's a statistical method that helps build a model to predict a particular outcome based on one or more predictor variables.
In this scenario, researchers used regression analysis to fit the logistic growth model to their observed data. The logistic growth model helps predict population growth in a scenario where resources (like food) are limited. Population growth initially accelerates, then slows down as it nears a carrying capacity. This is where regression becomes key in estimating important parameters like the initial population (\(N_0\)), the growth rate (\(r\)), and the carrying capacity (\(K\)).
With modern tools like Excel or Python libraries, researchers can perform these analyses, transforming observed data into a comprehensive model that predicts future population changes.
Carrying Capacity
Remember, carrying capacity (\(K\)) is a crucial concept in understanding population dynamics. It refers to the maximum number of individuals an environment can support sustainably over time. For the elk in Yellowstone, this would be the point where the food resources and other ecological factors could consistently support a stable number of elk without degradation of their habitat.
The logistic growth model incorporates carrying capacity to ensure that population predictions are realistic. As the elk population numbers approach the carrying capacity, the growth rate slows, and the population stabilizes. Estimating the carrying capacity helps wildlife managers make decisions regarding habitat conservation and population control measures.
In the elk study, carrying capacity is intimately linked to both the availability of food and the absence of predators, providing an ideal case study for how different ecological pressures balance one another.
Population Dynamics
Population dynamics involves studying how and why populations change over time and space. It's essential for managing wildlife effectively and ensuring biodiversity is maintained. This concept considers birth rates, death rates, and migration patterns, along with environmental factors like food availability and predation.
In the exercise about Yellowstone's elk, the population dynamics were observed in a situation with natural growth influenced primarily by food supply due to the absence of major predators. By exploring how the elk population dynamics evolved over the study period, scientists gained invaluable insights into how populations grow and stabilize under different environmental pressures.
Understanding these dynamics allows researchers to make informed predictions about future changes, design effective wildlife management strategies, and promote ecological health through sustainable practices.

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Most popular questions from this chapter

When seeds of a plant are sown at high density in a plot, the seedlings must compete with each other. As time passes, individual plants grow in size, but the density of the plants that survive decreases. \({ }^{33}\) This is the process of selfthinning. In one experiment, horseweed seeds were sown on October 21 , and the plot was sampled on successive dates. The results are summarized in Table \(5.8\), which gives for each date the density \(p\), in number per square meter, of surviving plants and the average dry weight \(w\), in grams, per plant. a. Explain how the table illustrates the phenomenon of self-thinning. b. Find a formula that models \(w\) as a power function of \(p\). c. If the density decreases by a factor of \(\frac{1}{2}\), what happens to the weight? d. The total plant yield y per unit area is defined to be the product of the average weight per plant and the density of the plants: \(y=w \times p\). As time goes on, the average weight per plant increases while the density decreases, so it's unclear whether the total yield will increase or decrease. Use the power function you found in part b to determine whether the total yield increases or decreases with time. Check your answer using the table. $$ \begin{array}{|l|r|c|} \hline \text { Date } & \text { Density } p & \text { Weight } w \\ \hline \text { November 7 } & 140,400 & 1.6 \times 10^{-4} \\ \hline \text { December } 16 & 36,250 & 7.7 \times 10^{-4} \\ \hline \text { January 30 } & 22,500 & 0.0012 \\ \hline \text { April 2 } & 9100 & 0.0049 \\ \hline \text { May 13 } & 4510 & 0.018 \\ \hline \text { June } 25 & 2060 & 0.085 \\ \hline \end{array} $$

It is a consequence of Newton's law of gravitation that near the surface of any planet, the distance \(D\) fallen by a rock in time \(t\) is given by \(D=c t^{2}\). That is, distance fallen is proportional to the square of the time, no matter what planet one may be on. But the value of \(c\) depends on the mass of the planet. For Earth, if time is measured in seconds and distance in feet, the value of \(c\) is 16 . a. Suppose a rock is falling near the surface of a planet. What is the comparison in distance fallen from 2 seconds to 6 seconds into the drop? (Hint: This question may be rephrased as follows: "If time increases by a factor of 3 , by what factor will distance increase?") b. For objects falling near the surface of Mars, if time is measured in seconds and distance in feet, the value of \(c\) is \(6.4\). If a rock is dropped from 70 feet above the surface of Mars, how long will it take for the rock to strike the ground? c. On Venus, a rock dropped from 70 feet above the surface takes \(2.2\) seconds to strike the ground. What is the value of \(c\) for Venus?

The side of a cylindrical can full of water springs a leak, and the water begins to stream out. (See Figure 5.106.) The depth \(H\), in inches, of water remaining in the can is a function of the distance \(D\) in inches (measured from the base of the can) at which the stream of water strikes the ground. Here is a table of values of \(D\) and \(H\) : $$ \begin{array}{|c|c|} \hline \begin{array}{c} \text { Distance } D \\ \text { in inches } \end{array} & \begin{array}{c} \text { Depth } H \\ \text { in inches } \end{array} \\ \hline 0 & 1.00 \\ \hline 1 & 1.25 \\ \hline 2 & 2.00 \\ \hline 3 & 3.25 \\ \hline 4 & 5.00 \\ \hline \end{array} $$ a. Show that \(H\) can be modeled as a quadratic function of \(D\). b. Find the formula for \(H\) as a quadratic function of \(D\). c. When the depth is 4 inches, how far from the base of the can will the water stream strike the ground? d. When the water stream strikes the ground 5 inches from the base of the can, what is the depth of water in the can?

By 1619 Johannes Kepler had completed the first accurate mathematical model describing the motion of planets around the sun. His model consisted of three laws that, for the first time in history, made possible the accurate prediction of future locations of planets. Kepler's third law related the period (the length of time required for a planet to complete a single trip around the sun) to the mean distance \(D\) from the planet to the sun. In particular, he stated that the period \(P\) is proportional to \(D^{1.5}\). a. Neptune is about 30 times as far from the sun as is the Earth. How long does it take Neptune to complete an orbit around the sun? (Hint: The period for the Earth is 1 year. If the distance is increased by a factor of 30 , by what factor will the period be increased?) b. The period of Mercury is about 88 days. The Earth is about 93 million miles from the sun. How far is Mercury from the sun? (Hint: The period of Mercury is different from that of the Earth by a factor of \(\frac{88}{365}\).)

Many science fiction movies feature animals such as ants, spiders, or apes growing to monstrous sizes and threatening defenseless Earthlings. (Of course, they are in the end defeated by the hero and heroine.) Biologists use power functions as a rough guide to relate body weight and cross-sectional area of limbs to length or height. Generally, weight is thought to be proportional to the cube of length, whereas cross-sectional area of limbs is proportional to the square of length. Suppose an ant, having been exposed to "radiation," is enlarged to 500 times its normal length. (Such an event can occur only in Hollywood fantasy. Radiation is utterly incapable of causing such a reaction.) a. By how much will its weight be increased? b. By how much will the cross-sectional area of its legs be increased? c. Pressure on a limb is weight divided by crosssectional area. By how much has the pressure on a leg of the giant ant increased? What do you think is likely to happen to the unfortunate ant? \({ }^{15}\)

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