/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 In the study of population genet... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In the study of population genetics, an important measure of inbreeding is the proportion of homozygous genotypes-that is, instances in which the two alleles carried at a particular site on an individual's chromosomes are both the same. For populations in which bloodrelated individuals mate, there is a higher than expected frequency of homozygous individuals. Examples of such populations include endangered or rare species, selectively bred breeds, and isolated populations. In general, the frequency of homozygous children from matings of blood-related parents is greater than that for children from unrelated parents. \(^{67}\) Measured over a large number of generations, the proportion of heterozygous genotypes-that is, nonhomozygous genotypes-changes by a constant factor \(\lambda_{1}\) from generation to generation. The factor \(\lambda_{1}\) is a number between 0 and 1 . If \(\lambda_{1}=0.75\), for example, then the proportion of heterozygous individuals in the population decreases by \(25 \%\) in each generation. In this case, after 10 generations the proportion of heterozygous individuals in the population decreases by \(94.37 \%\), since \(0.75^{10}=\) \(0.0563\), or \(5.63 \%\). In other words, \(94.37 \%\) of the population is homozygous. For specific types of matings, the proportion of heterozygous genotypes can be related to that of previous generations and is found from an equation. For matings between siblings, \(\lambda_{1}\) can be determined as the largest value of \(\lambda\) for which $$ \lambda^{2}=\frac{1}{2} \lambda+\frac{1}{4}. $$ This equation comes from carefully accounting for the genotypes for the present generation (the \(\lambda^{2}\) term) in terms of those of the previous two generations (represented by \(\lambda\) for the parents' generation and by the constant term for the grandparents' generation). a. Find both solutions to the quadratic equation above and identify which is \(\lambda_{1}\). (Use a horizontal span from \(-1\) to 1 in this exercise and the following two exercises.) b. After 5 generations what proportion of the population will be homozygous? c. After 20 generations what proportion of the population will be homozygous?

Short Answer

Expert verified
a. \( \lambda_1 = \frac{1 + \sqrt{5}}{4} \); b. Calculated proportion: \(1 - (\lambda_1^5)\); c. \(1 - (\lambda_1^{20})\).

Step by step solution

01

Solve the Quadratic Equation

Start by rewriting the quadratic equation \( \lambda^2 = \frac{1}{2} \lambda + \frac{1}{4} \) in standard form. This gives \( \lambda^2 - \frac{1}{2} \lambda - \frac{1}{4} = 0 \). To find the roots, use the quadratic formula: \[\lambda = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] Substituting \( a = 1 \), \( b = -\frac{1}{2} \), and \( c = -\frac{1}{4} \), calculate the roots.
02

Apply the Quadratic Formula

Plug the coefficients into the quadratic formula: \[\lambda = \frac{-(-\frac{1}{2}) \pm \sqrt{(-\frac{1}{2})^2 - 4 \times 1 \times (-\frac{1}{4})}}{2 \times 1} = \frac{\frac{1}{2} \pm \sqrt{\frac{1}{4} + 1}}{2}\] Simplify inside the square root: \[\lambda = \frac{\frac{1}{2} \pm \sqrt{\frac{5}{4}}}{2} = \frac{\frac{1}{2} \pm \frac{\sqrt{5}}{2}}{2}\] This gives \( \lambda = \frac{1 \pm \sqrt{5}}{4} \). Solve for both \( \lambda_1 \) and the other root.
03

Identify \(\lambda_1\)

Given that we need \( \lambda_1 \) to be the largest value between \(-1\) and \(1\), the relevant solution is \( \lambda_1 = \frac{1 + \sqrt{5}}{4} \). This value is greater than \( \frac{1 - \sqrt{5}}{4} \), and it's between \(0\) and \(1\).
04

Compute Homozygous Proportion After 5 Generations

The problem states that the homozygous population increases with each generation as the heterozygous proportion decreases by a factor of \( \lambda_1 \). Given 5 generations and initial heterozygosity of \(100\%\), calculate: \[\text{Heterozygous proportion after 5 generations} = \lambda_1^5\]\[\text{Homozygous proportion} = 1 - \lambda_1^5\] Substitute \( \lambda_1 = \frac{1 + \sqrt{5}}{4} \) to find the numerical answer.
05

Compute Homozygous Proportion After 20 Generations

Using the same approach as in Step 4, compute the heterozygous proportion after 20 generations: \[\text{Heterozygous proportion after 20 generations} = \lambda_1^{20}\]\[\text{Homozygous proportion} = 1 - \lambda_1^{20}\] Again substitute \( \lambda_1 = \frac{1 + \sqrt{5}}{4} \) to find the numerical result.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inbreeding
Inbreeding refers to the mating of closely related individuals within a population, leading to a higher frequency of homozygous genotypes. This happens because these individuals are more likely to inherit the same alleles from common ancestors. Inbreeding is common in certain populations such as those that are isolated, endangered, or selectively bred.

The main concern with inbreeding is the loss of genetic diversity. A high frequency of homozygous individuals can lead to the expression of deleterious recessive traits. These are traits that can result in reduced fitness, survival, and reproduction of individuals. Inbreeding might be seen as a negative factor in natural populations but could be advantageous in selective breeding where specific traits are desirable.

It's crucial to monitor inbreeding levels in conservation and breeding programs to ensure the long-term survival of species. Methods like pedigree analysis and genome-wide assessments help quantify inbreeding and potentially harmful allelic combinations.
Homozygous Genotypes
A genotype refers to the genetic makeup of an organism, particularly with regard to a particular trait or set of traits. Homozygous genotypes are when the two alleles at a given locus on a chromosome are identical.

Homozygosity is important because it can influence whether certain traits are expressed or suppressed. For example, in the case of a recessive disease allele, an individual will only express the disease if they are homozygous for that allele.

In genetics, homozygous genotypes can lead to traits becoming fixed within a population, particularly if inbreeding is prevalent. This may reduce genetic diversity over time. However, in some breeding scenarios, achieving homozygosity for specific alleles can help establish permanent traits within a strain or lineage.

Recognizing homozygosity is essential for understanding inheritance patterns, disease risk factors, and the genetic health of populations.
Quadratic Equation
Quadratic equations are fundamental in population genetics for modeling various phenomena. In this instance, the equation \( \lambda^2 = \frac{1}{2} \lambda + \frac{1}{4} \) is derived from genetic principles.

A quadratic equation is typically in the form \( ax^2 + bx + c = 0 \). Solving it involves finding values of \( x \) that satisfy the equation. These solutions often reveal crucial properties about the system in question, such as the factor by which genetic traits are passed onto future generations.

The quadratic formula \[ \lambda = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] is used to solve these equations. By substituting the specific coefficients \( a = 1 \), \( b = -\frac{1}{2} \), and \( c = -\frac{1}{4} \), you can determine the values of \( \lambda \). In genetic problems, \( \lambda \) often represents a change factor in time, dictating how frequencies of genetic traits will be affected over generations.
Heterozygous Proportion
Heterozygous individuals have two different alleles at a particular locus. In population genetics, heterozygosity is a measure of genetic variation. It signifies the proportion of individuals carrying two different alleles for a particular trait.

The proportion of heterozygous individuals decreases in inbred populations, as shown by the factor \( \lambda_1 \). This factor illustrates the rate at which indicators of genetic diversity diminish each generation. If \( \lambda_1 \) is less than 1, the heterozygous proportion decreases over time. For instance, if \( \lambda_1 = 0.75 \), the heterozygous proportion decreases by 25% every generation.

Calculating the change in heterozygosity aids in predicting future genetic configurations of populations. This understanding helps in creating strategies for preserving genetic diversity, especially in small or isolated groups where genetic drift and inbreeding are pronounced. It is a critical index for ensuring population viability.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One of the two tables below shows data that can be modeled by a linear function, and the other shows data that can be modeled by a quadratic function. Identify which table shows the linear data and which table shows the quadratic data, and find a formula for each model. $$ \begin{aligned} &\begin{array}{|l|c|c|c|c|c|} \hline x & 0 & 1 & 2 & 3 & 4 \\ \hline f(x) & 10 & 17 & 26 & 37 & 50 \\ \hline \end{array}\\\ &\text { Table A } \end{aligned} $$ $$ \begin{aligned} &\begin{array}{|l|c|c|c|c|c|} \hline x & 0 & 1 & 2 & 3 & 4 \\ \hline g(x) & 10 & 17 & 24 & 31 & 38 \\ \hline \end{array}\\\ &\text { Table B } \end{aligned} $$

One possible substitute for the logistic model of population growth is the Gompertz model, according to which Rate of growth \(=r N \ln \left(\frac{K}{N}\right)\). For simplicity in this problem we take \(r=1\), so this reduces to Rate of growth \(=N \ln \left(\frac{K}{N}\right)\) a. Let \(K=10\), and make a graph of the rate of growth versus \(N\) for the Gompertz model. b. Use the graph you obtained in part a to determine for what value of \(N\) the growth rate reaches its maximum. This is the optimum yield level under the Gompertz model with \(K=10\). c. Under the logistic model the optimum yield level is \(K / 2\). What do you think is the optimum yield level in terms of \(K\) under the Gompertz model? (Hint: Repeat the procedure in parts a and \(\mathrm{b}\) using different values of \(K\), such as \(K=1\) and \(K=100\). Try to find a pattern.)

The side of a cylindrical can full of water springs a leak, and the water begins to stream out. (See Figure 5.106.) The depth \(H\), in inches, of water remaining in the can is a function of the distance \(D\) in inches (measured from the base of the can) at which the stream of water strikes the ground. Here is a table of values of \(D\) and \(H\) : $$ \begin{array}{|c|c|} \hline \begin{array}{c} \text { Distance } D \\ \text { in inches } \end{array} & \begin{array}{c} \text { Depth } H \\ \text { in inches } \end{array} \\ \hline 0 & 1.00 \\ \hline 1 & 1.25 \\ \hline 2 & 2.00 \\ \hline 3 & 3.25 \\ \hline 4 & 5.00 \\ \hline \end{array} $$ a. Show that \(H\) can be modeled as a quadratic function of \(D\). b. Find the formula for \(H\) as a quadratic function of \(D\). c. When the depth is 4 inches, how far from the base of the can will the water stream strike the ground? d. When the water stream strikes the ground 5 inches from the base of the can, what is the depth of water in the can?

The life expectancy \(E\) of a main-sequence star \({ }^{12}\) depends on its mass \(M\). The relation is given by $$ E=M^{-2.5}, $$ where \(M\) is solar masses and \(E\) is solar lifetimes. The sun is thought to be at the middle of its life, with a total life expectancy of about 10 billion years. Thus the value \(E=1\) corresponds to a life expectancy of 10 billion years. a. Does a more massive star have a longer or a shorter life expectancy than a less massive star? b. Spica is a main-sequence star that is about \(7.3\) solar masses. What is the life expectancy of Spica? c. Express using functional notation the life expectancy of a main-sequence star with mass equal to \(0.5\) solar mass, and then calculate that value. d. Vega is a main-sequence star that is expected to live about \(6.36\) billion years. What is the mass of Vega? e. If one main-sequence star is twice as massive as another, how do their life expectancies compare?

The headway \(h\) is the average time between vehicles. On a highway carrying an average of 500 vehicles per hour, the probability \(P\) that the headway is at least \(t\) seconds is given \(^{45}\) by $$ P=0.87^{t} . $$ a. What is the limiting value of \(P\) ? Explain what this means in practical terms. b. The headway \(h\) can be calculated as the quotient of the spacing \(f\), in feet, which is the average distance between vehicles, and the average speed \(v\), in feet per second, of traffic. Thus the probability that spacing is at least \(f\) feet is the same as the probability that the headway is at least \(f / v\) seconds. Use function composition to find a formula for the probability \(Q\) that the spacing is at least \(f\) feet. Note: Your formula will involve both \(f\) and \(v\). c. If the average speed is 88 feet per second \((60\) miles per hour), what is the probability that the spacing between two vehicles is at least 40 feet?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.