/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Linear and exponential data: One... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Linear and exponential data: One of the following two tables shows linear data, and the other shows exponential data. Identify which is which, and find models for both. $$ \begin{aligned} &\begin{array}{|c|c|c|c|} \hline t & f(t) & t & f(t) \\ \hline 0 & 6.70 & 3 & 10.46 \\ \hline 1 & 7.77 & 4 & 12.13 \\ \hline 2 & 9.02 & 5 & 14.07 \\ \hline \end{array}\\\ &\text { Table A }\\\ &\begin{array}{|c|c|c|c|} \hline t & g(t) & t & g(t) \\ \hline 0 & 5.80 & 3 & 10.99 \\ \hline 1 & 7.53 & 4 & 12.72 \\ \hline 2 & 9.26 & 5 & 14.45 \\ \hline \end{array} \end{aligned} $$

Short Answer

Expert verified
Table A is exponential with model \( f(t) = 6.70 \cdot 1.16^t \); Table B is linear with \( g(t) = 1.73t + 5.80 \).

Step by step solution

01

Analyzing Differences in Table A

Calculate the differences in consecutive values of \( f(t) \) for Table A. \[ f(1) - f(0) = 7.77 - 6.70 = 1.07 \] \[ f(2) - f(1) = 9.02 - 7.77 = 1.25 \] \[ f(3) - f(2) = 10.46 - 9.02 = 1.44 \] \[ f(4) - f(3) = 12.13 - 10.46 = 1.67 \] \[ f(5) - f(4) = 14.07 - 12.13 = 1.94 \]The differences in Table A are not constant, suggesting exponential growth.
02

Analyzing Differences in Table B

Calculate the differences in consecutive values of \( g(t) \) for Table B. \[ g(1) - g(0) = 7.53 - 5.80 = 1.73 \] \[ g(2) - g(1) = 9.26 - 7.53 = 1.73 \] \[ g(3) - g(2) = 10.99 - 9.26 = 1.73 \] \[ g(4) - g(3) = 12.72 - 10.99 = 1.73 \] \[ g(5) - g(4) = 14.45 - 12.72 = 1.73 \]The differences in Table B are constant, indicating linear growth.
03

Determining the Linear Model for Table B

Since Table B shows linear growth with a constant change of 1.73, the linear model is of the form: \[ g(t) = mt + b \]Here, \( m = 1.73 \) (the common difference).Using \( g(0) = 5.80 \), the equation becomes:\[ g(t) = 1.73t + 5.80 \]
04

Determining the Exponential Model for Table A

For Table A, establish a ratio between consecutive terms: \[ \frac{f(1)}{f(0)} = \frac{7.77}{6.70} \approx 1.16 \] \[ \frac{f(2)}{f(1)} = \frac{9.02}{7.77} \approx 1.16 \] Thus, the sequence shows a multiplicative pattern. Assuming an exponential model:\[ f(t) = a \cdot r^t \] Using \( f(0) = 6.70 \) and calculated ratio \( r = 1.16 \), this model is:\[ f(t) = 6.70 \cdot 1.16^t \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Data
Linear data is characterized by a constant rate of change. When you plot linear data on a graph, the points form a straight line. This kind of data relationship can be described using a linear function, which follows the form \( y = mx + b \). Here, \( m \) represents the slope, or the rate of change, and \( b \) represents the y-intercept, or the value of \( y \) when \( x \) is zero.

In terms of real-world applications, linear data is often used in scenarios where changes occur at a consistent rate over time. For example, if you're observing a car moving at a constant speed, the relationship between time and distance is linear.

In the exercise, Table B’s data provided a constant difference of 1.73 between consecutive terms, which managed to confirm that it is linear data. This constant difference is the clue that allows us to model it with a linear function \( g(t) = 1.73t + 5.80 \). The slope \( 1.73 \) indicates a steady increase per unit of \( t \), perfectly capturing the essence of linear growth.
Exponential Data
Exponential data differs significantly from linear data. It is characterized by a rate of change that becomes progressively larger at each step. If you graph exponential data, the curve becomes steeper over time, reflecting rapid increase or decrease.

Exponential functions take the form \( y = a \times r^x \), where \( a \) is the initial amount, \( r \) is the growth (or decay) rate, and \( x \) represents time or another independent variable. This characteristic enables exponential functions to model growth processes where the quantity grows or shrinks in multiplicative steps.

Table A illustrates exponential growth because the quotient of consecutive values constantly approximates 1.16, indicating multiplicative rather than additive changes. The exponential model for Table A, \( f(t) = 6.70 \times 1.16^t \), shows how each subsequent value is approximately 16% larger than the one before, demonstrating exponential growth clearly.
Mathematical Modeling
Mathematical modeling involves creating a mathematical representation of a real-world situation. Models are crucial for predicting future data points or understanding underlying relationships within the data. Depending on the nature of the data, different types of models, such as linear and exponential, are used.

In the exercise, mathematical modeling is employed to identify and represent the patterns observed in the tables. For linear relationships, the data fits into a simple line equation indicating a steady rate of change. For exponential relationships, the model captures rapid growth or decay.

Mathematical models are powerful tools. They simplify real-world situations into equations, allowing us to make predictions, understand trends, and identify significant factors affecting various phenomena. Teaching the principles of mathematical modeling equips students with the ability to solve complex issues using logical and clear approaches.
Functions
Functions are mathematical expressions that describe the relationship between two sets of numbers or variables. In simple terms, a function indicates how one quantity depends on another.

Functions are typically written in the form \( f(x) \), illustrating how the value of \( f \) (the dependent variable) changes as \( x \) (the independent variable) changes. Crucial to both linear and exponential data modeling, functions make it possible to predict values not explicitly found in the data set.

For example, in the exercise, the linear function \( g(t) = 1.73t + 5.80 \) describes a straightforward, consistent increase in \( g(t) \) with each increment of \( t \). The exponential function \( f(t) = 6.70 \times 1.16^t \), on the other hand, represents a continuous growth rate, showing how subtle variations in the ratio lead to a significant difference over time.

Understanding functions is fundamental for interpreting different types of data and provides the foundation for further studies in mathematics and its applications in the real world.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Growth in length: In the fishery sciences it is important to determine the length of a fish as a function of its age. One common approach, the von Bertalanffy model, uses a decreasing exponential function of age to describe the growth in length yet to be attained; in other words, the difference between the maximum length and the current length is supposed to decay exponentially with age. The following table shows the length L, in inches, at age t, in years, of the North Sea sole.16 $$ \begin{array}{|c|c|c|c|} \hline t=\text { age } & L=\text { length } & t=\text { age } & L=\text { length } \\ \hline 1 & 3.7 & 5 & 12.7 \\ \hline 2 & 7.5 & 6 & 13.5 \\ \hline 3 & 10.0 & 7 & 14.0 \\ \hline 4 & 11.5 & 8 & 14.4 \\ \hline \end{array} $$ The maximum length attained by the sole is 14.8 inches. a. Make a table showing, for each age, the difference D between the maximum length and the actual length L of the sole. b. Find the exponential function that approximates D. c. Find a formula expressing the length L of a sole as a function of its age t. d. Draw a graph of L against t. e. If a sole is 11 inches long, how old is it? f. Calculate L(9) and explain in practical terms what your answer means.

. The half-life of U239: Uranium 239 is an unstable isotope of uranium that decays rapidly. In order to determine the rate of decay, 1 gram of U239 was placed in a container, and the amount remaining was measured at 1-minute intervals and recorded in the table below $$ \begin{array}{|c|c|} \hline \begin{array}{c} \text { Time } \\ \text { in minutes } \end{array} & \begin{array}{c} \text { Grams } \\ \text { remaining } \end{array} \\ \hline 0 & 1 \\ \hline 1 & 0.971 \\ \hline 2 & 0.943 \\ \hline 3 & 0.916 \\ \hline 4 & 0.889 \\ \hline 5 & 0.863 \\ \hline \end{array} $$ a. Show that these are exponential data and find an exponential model. (For this problem, round all your answers to three decimal places.) b. What is the percentage decay rate each minute? What does this number mean in practical terms? c. Use functional notation to express the amount remaining after 10 minutes and then calculate that value. d. What is the half-life of U239?

Age of haddock: The age \(T\), in years, of a haddock can be thought of as a function of its length \(L\), in centimeters. One common model uses the natural logarithm: $$ T=19-5 \ln (53-L) $$ a. Draw a graph of age versus length. Include lengths between 25 and 50 centimeters. b. Express using functional notation the age of a haddock that is 35 centimeters long, and then calculate that value. c. How long is a haddock that is 10 years old?

Reaction time: For certain decisions, the time it takes to respond is a logarithmic function of the number of choices faced. \({ }^{32}\) One model is $$ R=0.17+0.44 \log N, $$ where \(R\) is the reaction time in seconds and \(N\) is the number of choices. a. Draw a graph of \(R\) versus \(N\). Include values of \(N\) from 1 to 10 choices. b. Express using functional notation the reaction time if there are seven choices, and then calculate that time. c. If the reaction time is to be at most \(0.5\) second, how many choices can there be? d. If the number of choices increases by a factor of 10 , what happens to the reaction time? e. Explain in practical terms what the concavity of the graph means.

A savings account: You initially invest \(\$ 500\) in a savings account that pays a yearly interest rate of \(4 \%\). a. Write a formula for an exponential function giving the balance in your account as a function of the time since your initial investment. b. What monthly interest rate best represents this account? Round your answer to three decimal places. c. Calculate the decade growth factor. d. Use the formula you found in part a to determine how long it will take for the account to reach \(\$ 740\). Explain how this is consistent with your answer to part \(\mathrm{c}\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.