/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Earth's umbra: Earth has a shado... [FREE SOLUTION] | 91Ó°ÊÓ

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Earth's umbra: Earth has a shadow in space, just as people do on a sunny day. The darkest part \({ }^{1}\) of that shadow is a conical region in space known as the umbra. A representation of Earth's umbra is shown in Figure 3.39. Earth has a radius of about 3960 miles, and the umbra ends at a point about 860,000 miles from Earth. The moon is about 239,000 miles from Earth and has a radius of about 1100 miles. Consider a point on the opposite side of Earth from the sun and at a distance from Earth equal to the moon's distance from Earth. What is the radius of the umbra at that point? Can the moon fit inside Earth's umbra? What celestial event occurs when this happens?

Short Answer

Expert verified
The umbra radius at the moon's distance is approximately 2860 miles. Yes, the moon can fit inside the Earth's umbra, causing a lunar eclipse.

Step by step solution

01

Understand the Umbra

The umbra is the darkest part of Earth's shadow in space. It is conical, starting from the Earth and extending into space, tapering off until it ends, in this case, 860,000 miles from Earth.
02

Distance of Interest

We are interested in a particular point on the umbra, 239,000 miles from Earth, which equals the distance from Earth to the Moon.
03

Calculate the Umbra at the Moon's Distance

The formula to find the radius of umbra at a certain distance is given by similar triangles since the shadow forms a right triangle with the conical part starting from the edge of Earth. The relationship is: \( R_{umbra} = R_{Earth} \times \frac{L_{umbra} - D}{L_{umbra}} \), where \( R_{Earth} = 3960 \) miles, \( L_{umbra} = 860,000 \) miles, and \( D = 239,000 \) miles.
04

Compute the Umbra Radius

Substitute the values into the formula: \( R_{umbra} = 3960 \times \frac{860,000 - 239,000}{860,000} \approx 3960 \times \frac{621,000}{860,000} \approx 3960 \times 0.722 \approx 2860 \) miles.
05

Compare the Umbra Radius to Moon's Radius

The radius of the moon is 1100 miles, and we found the radius of the umbra at that distance to be approximately 2860 miles.
06

Conclusion on the Moon's Fit

Since the moon's radius (1100 miles) is much less than the umbra radius at 239,000 miles (2860 miles), the moon can indeed fit inside Earth's umbra.
07

Identify the Celestial Event

When the moon fits fully inside the Earth's umbra, a lunar eclipse occurs, as the Earth blocks sunlight from reaching the moon.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Earth's Shadow
Earth's shadow, like any shadow, is the region created when Earth obstructs sunlight. This shadow extends into space and contains two main parts: the umbra and the penumbra. The umbra is the core of the shadow, where sunlight is entirely blocked, resulting in complete darkness within this region. It forms a cone-shaped shadow projecting behind the Earth.

The dimensions of this shadow are significant, reaching into the space far beyond the Earth's immediate orbit. For instance, in the original exercise, the umbra reaches up to 860,000 miles away from the Earth. Understanding the structure and behavior of Earth's shadow is crucial for studying various celestial events, like eclipses.
Lunar Eclipse
A lunar eclipse is a fascinating celestial event that occurs when the moon passes into Earth's shadow, specifically the umbra. During this event, the Earth is positioned directly between the sun and the moon. This alignment causes the Earth's umbra to cover the moon entirely or partially.

When the moon is completely within the umbra, a total lunar eclipse occurs, causing the moon to appear reddish due to the Earth's atmosphere filtering and refracting sunlight. This phenomenon is often called a "blood moon." Partial or penumbral eclipses occur when only a portion of the moon enters the umbra or penumbra, respectively.
Similar Triangles
The concept of similar triangles is a cornerstone in geometric calculations often used in celestial observations. Similar triangles occur when two or more triangles have the same shape but differing sizes. This similarity allows for the calculation of unknown dimensions, using proportional relationships.

In the context of Earth's umbra, the formula for calculating the radius of the umbra at a particular distance from the Earth involves applying similar triangles. The relationship is described by the formula:
  • \( R_{umbra} = R_{Earth} \times \frac{L_{umbra} - D}{L_{umbra}} \)
where:
  • \( R_{Earth} \) is the radius of the Earth,
  • \( L_{umbra} \) is the length of the umbra,
  • \( D \) is the distance from the Earth to the point of interest.
This formula helps in predicting if celestial bodies, like the moon, fit within the shadow, allowing for accurate planning of observations.
Celestial Events
Celestial events are natural phenomena occurring in the universe, often involving various astronomical objects. These events are integral to understanding our place in space. They range from meteor showers, solar and lunar eclipses, planetary transits, to more distant phenomena like supernova explosions and galactic collisions.

Lunar and solar eclipses are some of the most observed celestial events. During a solar eclipse, the moon passes between the Earth and the sun, casting a shadow on Earth. Conversely, a lunar eclipse involves the Earth casting its shadow over the moon. These events allow astronomers to study celestial mechanics, the interaction between celestial bodies in space, and even the characteristics of atmospheres. Observing these events deepens our understanding of the universe and helps predict future occurrences, enhancing both science and entertainment for space enthusiasts.

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Most popular questions from this chapter

Budget constraints: Your family likes to eat fruit, but because of budget constraints, you spend only \(\$ 5\) each week on fruit. Your two choices are apples and grapes. Apples cost \(\$ 0.50\) per pound, and grapes cost \(\$ 1\) per pound. Let \(a\) denote the number of pounds of apples you buy and \(g\) the number of pounds of grapes. Because of your budget, it is possible to express \(g\) as a linear function of the variable \(a\). To find the linear formula, we need to find its slope and initial value. a. If you buy one more pound of apples, how much less money do you have available to spend on grapes? Then how many fewer pounds of grapes can you buy? b. Use your answer to part a to find the slope of \(g\) as a linear function of \(a\). (Hint: Remember that the slope is the change in the function that results from increasing the variable by 1. Should the slope of \(g\) be positive or negative?) c. To find the initial value of \(g\), determine how many pounds of grapes you can buy if you buy no apples. d. Use your answers to parts \(b\) and \(c\) to find \(a\) formula for \(g\) as a linear function of \(a\).

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Getting Celsius from Fahrenheit: Water freezes at 0 degrees Celsius, which is the same as 32 degrees Fahrenheit. Also water boils at 100 degrees Celsius, which is the same as 212 degrees Fahrenheit. a. Use the freezing and boiling points of water to find a formula expressing Celsius temperature \(C\) as a linear function of the Fahrenheit temperature \(F\). b. What is the slope of the function you found in part a? Explain its meaning in practical terms. c. In Example 3.5 we showed that \(F=1.8 C+32\). Solve this equation for \(C\) and compare the answer with that obtained in part a.

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