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An interesting system of equations: What happens when you try to solve the following system of equations? Can you explain what is going on? $$ \begin{aligned} &x+y=1 \\ &x+y=2 \end{aligned} $$

Short Answer

Expert verified
The system is inconsistent; there are no solutions because the equations represent parallel lines.

Step by step solution

01

Identify the Equations

The system consists of two linear equations: \(x+y=1\) and \(x+y=2\).
02

Compare the Equations

Both equations have the same left-hand side, \(x + y\), but their right-hand sides are different (1 in the first equation and 2 in the second).
03

Analyze for Consistency

For two linear equations to have a solution, they must intersect at a common point. However, since the only difference is the constants on the right, the equations represent parallel lines. Here, since parallel lines never meet, there is no intersection point.
04

Conclude on the Solution

Since the lines are parallel and distinct, this system of equations is inconsistent, meaning there is no set of values for \(x\) and \(y\) that satisfy both equations simultaneously.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Equations
Let's start with the basics. A linear equation is a kind of equation where each term is either a constant or the product of a constant and a single variable. When graphed, a linear equation forms a straight line. The standard form of a linear equation in two variables is usually written as \( ax + by = c \), where \( a \), \( b \), and \( c \) are constants and \( x \) and \( y \) are variables.
In the system given, both equations—\( x+y=1 \) and \( x+y=2 \)—are linear equations. Each expresses a relation between the variables \( x \) and \( y \), and how the sum of these variables equals to a constant. These equations can be rewritten in slope-intercept form \( y = -x + c \), showing their constant relationship to each other and their respective constants.
Linear equations allow us to explore a wide range of relationships and can model many real-world situations. Understanding them is a crucial foundational skill in algebra.
Parallel Lines
Parallel lines are lines in the same plane that never meet; in simpler terms, they have the same slope but different intercepts.
The concept of parallel lines is important when working with linear equations and systems. If we take our example equations, \( x+y=1 \) and \( x+y=2 \), we can rearrange them to uncover their slopes: \( y = -x + 1 \) and \( y = -x + 2 \).
- Since both lines have the same slope of \(-1\), they are parallel.- Despite looking similar, having different intercepts means they will never meet or intersect.In geometry, two lines that are not vertical are parallel if and only if they have the same slope. This subtle detail can have big implications, as discussed in the next section.
Inconsistent System
An inconsistent system of equations is a set of equations with no common solution.
In the case of our example, since the equations represent parallel lines, no single point lies on both lines simultaneously. This makes the system inconsistent, as parallel lines do not intersect.
When we try to solve an inconsistent system algebraically, like solving \( x+y=1 \) and \( x+y=2 \) together, we'll eventually reach a contradiction, such as \( 1 = 2 \), which isn't possible. - This contradiction indicates the inconsistency.- It's an indicator that there are no points \((x, y)\) satisfying both equations simultaneously.Recognizing and understanding inconsistent systems is important, especially in fields that rely on systems of equations for problem-solving, ensuring accurate and reliable results.

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Most popular questions from this chapter

American dollars and British pounds: Assume that at the current exchange rate, the British pound is worth \(\$ 2.06\) in American dollars. You have some dollar bills and several British pound coins. There are 17 items altogether, which have a total value of \(\$ 30.78\) in American dollars. How many American dollars and how many British pound coins do you have?

Energy cost of running: Physiologists have studied the steady-state oxygen consumption (measured per unit of mass) in a running animal as a function of its velocity (i.e., its speed). They have determined that the relationship is approximately linear, at least over an appropriate range of velocities. The table on the following page gives the velocity \(v\), in kilometers per hour, and the oxygen consumption \(E\), in milliliters of oxygen per gram per hour, for the rhea, a large, flightless South American bird. \({ }^{27}\) (For comparison, 10 kilometers per hour is about \(6.2\) miles per hour.) $$ \begin{array}{|c|c|} \hline \text { Velocity } v & \text { Oxygen consumption } E \\ \hline 2 & 1.0 \\ \hline 5 & 2.1 \\ \hline 10 & 4.0 \\ \hline 12 & 4.3 \\ \hline \end{array} $$ a. Find the equation of the regression line for \(E\) in terms of \(v\). b. The slope of the linear function giving oxygen consumption in terms of velocity is called the cost of transport for the animal, since it measures the energy required to move a unit mass by 1 unit distance. What is the cost of transport for the rhea? c. Physiologists have determined the general approximate formula \(C=8.5 \mathrm{~W}^{-0.40}\) for the cost of transport \(C\) of an animal weighing \(W\) grams. If the rhea weighs 22,000 grams, is its cost of transport from part b higher or lower than what the general formula would predict? Is the rhea a more or a less efficient runner than a typical animal its size? d. What would your equation from part a lead you to estimate for the oxygen consumption of a rhea at rest? Would you expect that estimate to be higher or lower than the actual level of oxygen consumption of a rhea at rest?

An order for bulbs: You have space in your garden for 55 small flowering bulbs. Crocus bulbs cost \(\$ 0.35\) each and daffodil bulbs cost \(\$ 0.75\) each. Your budget allows you to spend \(\$ 25.65\) on bulbs. How many crocus bulbs and how many daffodil bulbs can you buy?

Another interesting system of equations: What happens when you try to solve the following system of equations? Can you explain what is going on? $$ \begin{gathered} x+2 y=3 \\ -2 x-4 y=-6 \end{gathered} $$

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