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Here is a model for the number of students enrolled in U.S. public high schools as a function of time since 1965 : $$ N=-0.02 t^{2}+0.44 t+11.65 . $$ In this formula \(N\) is the enrollment in millions of students, \(t\) is the time in years since 1965 , and the model is applicable from 1965 to \(1985 .\) a. Calculate \(N(7)\) and explain in practical terms what it means. b. In what year was the enrollment the largest? What was the largest enrollment? c. Find the average yearly rate of change in enrollment from 1965 to 1985 . Is the result misleading, considering your answer to part b?

Short Answer

Expert verified
a. In 1972, 13.75 million students were enrolled. b. The largest enrollment was 14.07 million in 1976. c. The average rate was 0.07 million per year, it misleads.

Step by step solution

01

Calculate N for t=7

First, substitute 7 into the model equation for t.\[N = -0.02(7)^2 + 0.44(7) + 11.65\]Calculate each term separately:- \(-0.02(7)^2 = -0.02 imes 49 = -0.98\)- \(0.44 imes 7 = 3.08\)- Constant term is 11.65.Now add them together:\[N = -0.98 + 3.08 + 11.65 = 13.75\]
02

Interpret N(7)

The calculated value means that in 1972 (since 7 years after 1965 is 1972), there were approximately 13.75 million students enrolled in U.S. public high schools.
03

Find the year with maximum enrollment

The enrollment reaches its peak where the quadratic function has its vertex. For the quadratic equation \(ax^2 + bx + c\), the vertex occurs at \(t = -\frac{b}{2a}\).Substitute \(a = -0.02\) and \(b = 0.44\):\[t = -\frac{0.44}{2 imes -0.02} = \frac{0.44}{0.04} = 11\]Hence, the highest enrollment was 11 years after 1965, which is in 1976.
04

Calculate the largest enrollment

Substitute \(t = 11\) back into the formula to find the largest enrollment:\[N = -0.02(11)^2 + 0.44(11) + 11.65\]Calculate each term:- \(-0.02(11)^2 = -0.02 imes 121 = -2.42\)- \(0.44 imes 11 = 4.84\)Add these to the constant term:\[N = -2.42 + 4.84 + 11.65 = 14.07\]The largest enrollment was 14.07 million.
05

Calculate average yearly rate of change

Calculate the rate of change over the 20-year period from 1965 to 1985:\[\text{Average rate} = \frac{N(20) - N(0)}{20}\]First, find \(N(20)\) and \(N(0)\):- \(N(0):\) \[N = 11.65\]- \(N(20):\)\[N = -0.02(20)^2 + 0.44(20) + 11.65 = 13.05\]Average rate:\[\text{Average rate} = \frac{13.05 - 11.65}{20} = \frac{1.4}{20} = 0.07\]The average yearly rate is 0.07 million, or 70,000 students per year.
06

Consider rate of change and enrollment peak

The positive average rate suggests increasing enrollment over the 20 years, yet the highest enrollment occurred in 1976, with a decline afterward. Thus, the average rate does not fully capture the enrollment trend, as it reached and passed a peak.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Modeling Enrollment
When trying to model enrollment in educational institutions, quadratic functions can be immensely useful. In this scenario, we look at a quadratic equation that models the enrollment of U.S. public high school students over a period. This function uses the variable \( t \), which represents the number of years since 1965, to predict student enrollment numbers. The equation given is: \[ N = -0.02t^2 + 0.44t + 11.65 \] where \( N \) is the number of students in millions.

Each term in the equation plays a specific role:
  • The term \(-0.02t^2\) indicates that the model is quadratic and demonstrates how enrollment might slow down or decline following a certain trend or time period.
  • The middle term \(0.44t\) suggests an initial increase in enrollment over time and contributes to the upward slope seen at the start of the given time frame.
  • The constant term \(11.65\) represents the initial enrollment figure in millions for the year 1965.
By substituting different values of \( t \) into the equation, we can predict enrollment figures for any year between 1965 and 1985. This model is a valuable tool for understanding historical trends in educational demographics.
Rate of Change
The rate of change is a crucial metric in understanding how enrollment figures transform over time. In the context of a quadratic enrollment function, the rate of change gives insight into how quickly, and in which direction, the number of students is altering year by year.

To calculate the average yearly rate of change over a specified period, say from 1965 to 1985, we determine the difference in enrollment at the start and end of the period and divide by the total number of years. Specifically, for this model:
\[\text{Average rate} = \frac{N(20) - N(0)}{20}\] - \( N(0) \) is the enrollment at the start, 1965, calculated as 11.65 million students.- \( N(20) \) is the enrollment at the end, 1985, which we find to be 13.05 million students.
The average would be \((13.05 - 11.65) / 20 = 0.07\) million students per year, or 70,000 students per year.

Even though the average rate is positive, indicating growth over the whole period, one must be careful not to overlook nuances like the early peaks and later declines captured in the quadratic nature and vertex of the parabola.
Vertex of a Parabola
In the context of quadratic functions, the vertex of the parabola represents a significant point in time. It marks the peak (maximum) or the lowest point (minimum) of the curve. For enrollment data modeled by a parabolic function, the vertex often indicates the period of highest enrollment.

In our model, the form \( ax^2 + bx + c \), reveals that the year with the highest enrollment, or the vertex, can be found using the formula: \[t = -\frac{b}{2a}\].
Substituting the values from our equation, where \( a = -0.02 \) and \( b = 0.44 \), we find:
\[t = -\frac{0.44}{2 \times -0.02} = 11\]
This means that 11 years after 1965, in 1976, the enrollment peaked. At this point, the vertex gives us the highest number of students enrolled, calculated as approximately 14.07 million students.

Understanding the vertex helps accentuate important trends within the overall timeframe, which might be less obvious when only looking at average changes. It is a critical tool for noticing shifts in trends and can influence educational policy and planning.

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