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Show that the nonlinear operator \(\varphi\) from \(L_{2}[0,1]\) into \(L_{2}[0,1]\) defined by \(\varphi(x): t \mapsto \sin (x(t))\) is everywhere Gâteaux but nowhere Fréchet differentiable.

Short Answer

Expert verified
The operator \( \varphi(x) = \sin(x(t)) \) is Gâteaux differentiable in every direction but not Fréchet differentiable due to the nonlinearity of sine function.

Step by step solution

01

Understanding the operators

First, recall that a Gâteaux differentiable operator is one that has a directional derivative in every direction, while a Fréchet differentiable operator is one that has a linear approximation. A function can be Gâteaux differentiable without being Fréchet differentiable if it does not have a uniform linear approximation.
02

Define the Operator and Set up Requirements

Given the operator \( \varphi(x): t \mapsto \sin (x(t)) \), we need to check if it is Gâteaux differentiable in every direction and if it is nowhere Fréchet differentiable. Begin by writing the definition of Gâteaux and Fréchet differentiability.
03

Gâteaux Differentiability

For Gâteaux differentiability, compute the directional derivative of \( \varphi \). For any function \( x \in L_{2}[0,1] \) and direction \( h \in L_{2}[0,1] \), evaluate the limit: \( \varphi_x'(h) = \lim_{\varepsilon \to 0} \frac{ \varphi(x + \varepsilon h)(t) - \varphi(x)(t) }{ \varepsilon } = \lim_{\varepsilon \to 0} \frac{ \sin(x(t) + \varepsilon h(t)) - \sin(x(t)) }{ \varepsilon } = h(t) \cos(x(t)) \). Since this limit exists for all directions \( h \in L_{2}[0,1] \), the operator is Gâteaux differentiable.
04

Non-existence of Fréchet Differentiability

For Fréchet differentiability, \( \varphi \) must have a linear operator \L\ that serves as a good approximation. To find such a linear approximation: \( \| \varphi(x+h) - \varphi(x) - Lh \|_2 = o(\| h \|_2) \). If we let \( Lh = h(t) \cos(x(t)) \, \varphi(x+h)(t) - \varphi(x)(t) - Lh = \sin(x(t) + h(t)) - \sin(x(t)) - h(t) \cos(x(t)) \, using \sin(A+B) = \sin A \cos B + \cos A \sin B \,, \sin(x + h) - \sin(x) - h \cos(x) = (because of non-linearity of h's derivative\). \Thus \( \varphi \) is not Fréchet differentiable.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gâteaux Differentiability
Understanding the concept of Gâteaux differentiability is key in functional analysis. When we say an operator is Gâteaux differentiable, we mean it has a directional derivative in any direction within the normed vector space. To explain further, imagine a function that changes as you nudge it in various directions. If the rate of this change can be calculated consistently in any direction, then the function is Gâteaux differentiable.

Consider the operator \(\textbackslash\textbackslash)varphi(x): t \mapsto \sin(x(t)) \) from the exercise. To check if it's Gâteaux differentiable, we compute the directional derivative for any function \(\textbackslash\textbackslash)x \in L_{2}[0,1] \) and direction \(\textbackslash\textbackslash)h \in L_{2}[0,1] \). The derivative is given by the limit:

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Most popular questions from this chapter

\(\mathbf{}\) Let \(p \in(1, \infty) .\) Show that the norm of \(L_{p}[0,1]\) is Gâteaux differentiable and calculate its Gâteaux derivative. Hint: By the standard rules (use the monotonicity in the differential quotient), we get \(\|\cdot\|_{x}^{\prime}(h)=\|x\|^{1-p} \int|x(t)|^{p-1} \operatorname{sign}(x(t)) h(t) d t\). The convergence of the integral follows from Hölder's inequality.

Show that a finite lower semicontinuous convex function \(f\) that is defined on a whole Banach space must be continuous.

([Mon2]) Let \(X\) be a Banach space. The drop defined by \(x \in X \backslash B_{X}\) is the set \(D\left(x, B_{X}\right)=\operatorname{conv}\left(\\{x\\} \cup B_{X}\right) .\) The Banach space \(X\) is said to have the drop property if, given any closed set \(S \subset X\) such that \(S \cap B_{X}=\emptyset\), there exists \(s \in S\) such that \(D\left(s, B_{X}\right) \cap S=\\{x\\}\) (i) Let \(X\) be a Banach space. Show that, given a closed set \(A \subset X\) such that \(\operatorname{dist}\left(A, B_{X}\right)>0\), there exists \(a \in A\) such that \(D\left(a, B_{X}\right) \cap A=\\{a\\}\) ([Dan]). (ii) Prove that \(X\) has the drop property if and only if \(X\) is reflexive and has the Kadec property (that is, norm and weak convergent sequences in \(S_{X}\) are the same).

Let \(X\) be a Banach space. We say that \(X\) has the Kadec-Klee property if the weak and norm topologies coincide on \(S_{X}\). We say that \(X^{*}\) has the \(w^{*}\) -Kadec-Klee property if the \(w^{*}\) - and norm topologies coincide on \(S_{X^{*}}\) (i) Let \(X\) be a locally uniformly rotund space. Show that \(X\) has the KadecKlee property. (ii) Let \(X\) be a Banach space such that the dual norm of \(X^{*}\) is LUR. Show that \(X^{*}\) has the \(w^{*}\) -Kadec-Klee property.

Let || \cdot || be an LUR norm on a separable Banach space \(X .\) Show that the set \(S\) of all elements in \(X^{*}\) that attain their norm is dense and \(G_{\delta}\) in \(X^{*}\)

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