Chapter 10: Problem 7
Let \((X,\|\cdot\|)\) be a Banach space. Define a function \(f\) on \(X\) by \(f(x)=0\) for \(x \in B_{X}\) and \(f(x)=+\infty\) otherwise. Calculate the conjugate function \(f^{*}\) to \(f\).
Short Answer
Expert verified
The conjugate function is \[ f^{*}(y) = ||y|| \].
Step by step solution
01
Define the Conjugate Function
The conjugate function of a function 饾憮, denoted by 饾憮^鈭, is defined as follows: \[ f^{*}(y) = \text{sup}_{x eq 0} (\text{鉄▆y,x\text{鉄﹠ - f(x)) \]
02
Evaluate f(x) for x in B_X
Given that 饾憮(饾懃)=0 when 饾懃 鈭 B_{饾悧}, we get the supremum of \[ \text{sup}_{x eq 0} (\text{鉄▆y,x\text{鉄﹠ - 0) = \text{sup}_{x eq 0} \text{鉄▆y,x\text{鉄﹠ \]and recognize that in this context, 鉄潙,饾懃鉄 means the inner product or duality product.
03
Consider x outside B_X
Given 饾憮(饾懃)=+鈭 for 饾懃 鈭 B_{饾悧}, the supremum expression would become\[ \text{sup}_{x eq 0} (\text{鉄▆y,x\text{鉄﹠ - +鈭) = -鈭 \]which doesn鈥檛 contribute to the supremum.
04
Evaluate Supremum in B_X
Since for 饾懃 鈭 B_{饾悧}, we know that ||饾懃|| 鈮 1, we consider \[ \text{sup}_{||x|| eq 1} \text{鉄▆y,x\text{鉄﹠ \]because both 鉄潙,饾懃鉄 and ||饾懃|| are well-behaved within B_{饾悧}.
05
Determine Bound of 鉄潙,饾懃鉄
Using the fact that ||饾懃|| 鈮 1 and properties of the dual norm, we obtain\[ \text{鉄▆y,x\text{鉄﹠ \text{ 鈮 } ||饾懄|| ||饾懃|| \text{ 鈮 } ||饾懄|| \] and thus obtain \[ \text{sup}_{||x|| eq 1} \text{鉄▆y,x\text{鉄﹠ \text{ = ||y||} \].
06
Conclude the Conjugate Function
Combining our findings from all the steps, we conclude that \[ f^{*}(y) = \begin{cases} ||饾懄|| & if \text{ } y \text{ belongs to X} \ -鈭 & otherwise \text{ } \text{y does not belong to or defined in B岬猒{X}} ot \belongs \text{X} \end{cases} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
conjugate functions
The concept of a conjugate function, also known as the Fenchel conjugate or Legendre-Fenchel transform, is crucial in functional analysis and optimization. Given a function 饾憮, its conjugate function, denoted by 饾憮^{*}, is defined as:
\[ f^{*}(y) = \text{sup}_{x} ( \text{鉄▆y,x\text{鉄﹠ - f(x) ) \]
Here, 鉄潙,饾懃鉄 represents the duality product, essentially the inner product in this context. Conjugate functions serve to transform a given function into another that reveals dual relationships and optimizes constraints.
In solving the exercise, our function 饾憮 is piecewise:
\[ f^{*}(y) = \text{sup}_{x} ( \text{鉄▆y,x\text{鉄﹠ - f(x) ) \]
Here, 鉄潙,饾懃鉄 represents the duality product, essentially the inner product in this context. Conjugate functions serve to transform a given function into another that reveals dual relationships and optimizes constraints.
In solving the exercise, our function 饾憮 is piecewise:
- \( f(x) = 0 \) for \( x \text{ in } B_X\)
- \( f(x) = +\text{鈭瀩 \) otherwise
duality product
The duality product is a mutual relationship between elements of a Banach space and its dual space. It generalizes the concept of a dot product or inner product.
In this context, the duality product 鉄潙,饾懃鉄 is used in expressing the conjugate function:\[ f^{*}(y) = \text{sup}_{x} ( \text{鉄▆y,x\text{鉄﹠ - f(x) ) \]
When calculating \( f^{*}(y) \), 鉄潙,饾懃鉄 represents the contribution of elements from the dual space 饾憣 acting on elements from the original space 饾憢. Thus, when 饾憮(饾懃) is zero inside the unit ball \( B_X \), the supremum of 鉄潙,饾懃鉄 minus zero reduces to simply 鉄潙,饾懃鉄.
For \( x \) outside of \( B_X \), the function 饾憮 is defined as \( +\text{鈭瀩 \), thus making the expression for the supremum \( -\text{鈭瀩 \), which does not affect the calculation. Understanding duality product helps anchor the transformation from primal to dual problems, bending the concepts in geometric and algebraic ways.
In this context, the duality product 鉄潙,饾懃鉄 is used in expressing the conjugate function:\[ f^{*}(y) = \text{sup}_{x} ( \text{鉄▆y,x\text{鉄﹠ - f(x) ) \]
When calculating \( f^{*}(y) \), 鉄潙,饾懃鉄 represents the contribution of elements from the dual space 饾憣 acting on elements from the original space 饾憢. Thus, when 饾憮(饾懃) is zero inside the unit ball \( B_X \), the supremum of 鉄潙,饾懃鉄 minus zero reduces to simply 鉄潙,饾懃鉄.
For \( x \) outside of \( B_X \), the function 饾憮 is defined as \( +\text{鈭瀩 \), thus making the expression for the supremum \( -\text{鈭瀩 \), which does not affect the calculation. Understanding duality product helps anchor the transformation from primal to dual problems, bending the concepts in geometric and algebraic ways.
supremum
The term supremum refers to the least upper bound of a set or function. In our case, calculating the conjugate function involves finding the supremum of \( \text{鉄▆y,x\text{鉄﹠ \) subject to certain conditions.
The supremum operation is formalized as:
\[ \text{sup}_{x} ( \text{鉄▆y,x\text{鉄﹠ - f(x) ) \]
For \( x \text{ in } B_X\), where \( f(x) = 0 \), this simplifies to:
\[ \text{sup}_{x \text{ in } B_X} \text{鉄▆y,x\text{鉄﹠ \]
Given \( ||饾懃|| \text{ 鈮 } 1 \) within \( B_X \), the maximum value, subjected to the properties of inner products and norms, is given by \( ||饾懄|| \). This takes into account that the norm fully scales the supremum.
Identifying the supremum effectively helps in determining the conjugate function; it's an essential step to ensure the solution adheres to the maximum constraints imposed by the original function's definition.
The supremum operation is formalized as:
\[ \text{sup}_{x} ( \text{鉄▆y,x\text{鉄﹠ - f(x) ) \]
For \( x \text{ in } B_X\), where \( f(x) = 0 \), this simplifies to:
\[ \text{sup}_{x \text{ in } B_X} \text{鉄▆y,x\text{鉄﹠ \]
Given \( ||饾懃|| \text{ 鈮 } 1 \) within \( B_X \), the maximum value, subjected to the properties of inner products and norms, is given by \( ||饾懄|| \). This takes into account that the norm fully scales the supremum.
Identifying the supremum effectively helps in determining the conjugate function; it's an essential step to ensure the solution adheres to the maximum constraints imposed by the original function's definition.