Chapter 3: Problem 12
Let \(A \in \mathcal{B}(X, Y) .\) For \(f \in Y^{*}\), define $$ \left(A^{*} f\right)(x)=f(A x), \quad f \in Y^{*}, x \in X $$ Show that \(A^{*} f \in X^{*}\) for all \(f \in Y^{*}\), and \(A^{*} \in \mathcal{B}\left(Y^{*}, X^{*}\right)\).
Short Answer
Expert verified
The operator \(A^*\) maps each \(f \, \in Y^*\) to a bounded linear functional on \(X\) and is a bounded linear operator from \(Y^*\) to \(X^*\).
Step by step solution
01
- Understand the Given
We start with the definitions. Given is a continuous linear operator \(A \in \mathcal{B}(X, Y)\). Also, we have \(f \in Y^*\), where \(Y^*\) is the dual space of \(Y\). We define the operator \(A^*\) by \((A^* f)(x) = f(A x)\).
02
- Prove Linearity of \(A^* f\)
To show that \(A^* f \, \in X^*\), we need to check if \(A^* f\) is linear. Let \(x_1, x_2 \, \in X\) and \(c_1, c_2\) be constants. Then,\[(A^* f)(c_1 x_1 + c_2 x_2) = f(A (c_1 x_1 + c_2 x_2)) = f(c_1 A x_1 + c_2 A x_2).\]Using the linearity of \(f\), this equals\[c_1 f(A x_1) + c_2 f(A x_2) = c_1 (A^* f)(x_1) + c_2 (A^* f)(x_2).\]Hence, \(A^* f\) is linear.
03
- Prove Boundedness of \(A^* f\)
To show that \(A^* f\) is bounded, we need to find a constant \(C\) such that \(|(A^* f)(x)| \leq C \|x\|\) for all \(x \, \in X\). Since \(f \, \in Y^*\) is bounded, there exists \(M > 0\) such that \(|f(y)| \leq M \|y\|\) for all \(y \, \in Y\).Thus,\[ |(A^* f)(x)| = |f(A x)| \leq M \|A x\|. \]Since \(A\) is bounded, there exists \(K > 0\) such that \(\|A x\| \leq K \|x\|\) for all \(x \, \in X\). Therefore,\[ |(A^* f)(x)| \leq M K \|x\|. \]This shows \(A^* f\) is bounded and therefore \(A^* f \in X^*\).
04
- Show \(A^* \in \mathcal{B}(Y^*, X^*)\)
We must show that \(A^*\) is a bounded linear operator from \(Y^*\) to \(X^*\). From the previous steps, we have established that \(A^*\) maps each \(f \, \in Y^*\) to a bounded linear functional on \(X\), i.e., an element of \(X^*\).Next, we need to prove the boundedness of \(A^*\). For this, we want to show there exists a constant \(C' > 0\) such that \(\|A^* f\| \leq C' \|f\|\) for all \(f \, \in Y^*\). Recall:\[ \|A^* f\| = \sup_{\|x\| = 1} |(A^* f)(x)| = \sup_{\|x\| = 1} |f(A x)|. \]Since \(f\) is bounded, we have \(\|f\| = \sup_{\|y\| = 1} |f(y)| \). Given \( \|A x\| \leq K \|x\| \), we get\[ \|A^* f\| = \sup_{\|x\| = 1} |f(A x)| \leq \sup_{\|x\| = 1} \|f\| \cdot \|A x\| \leq \|f\| \cdot K = K \|f\|. \]Thus, \(\|A^*\| \leq K\), and \(A^*\) is bounded.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Bounded Linear Operator
A bounded linear operator is a fundamental concept in functional analysis. It is a linear operator that maps between two normed vector spaces and satisfies a specific boundedness condition. Here's what you need to know:
An operator \(A: X \rightarrow Y\) is called linear if for any two vectors \(x_1, x_2 \in X\) and any scalar constants \(c_1, c_2\), the operator satisfies the equation \(A(c_1 x_1 + c_2 x_2) = c_1 A x_1 + c_2 A x_2\).
Additionally, the operator is bounded if there exists a constant \(C \ge 0\) such that for all \(x \in X\), the inequality \(otag\|A x\| \le C \|x\|\) holds. This means the operator does not stretch the vectors too much.
Important points to remember:
An operator \(A: X \rightarrow Y\) is called linear if for any two vectors \(x_1, x_2 \in X\) and any scalar constants \(c_1, c_2\), the operator satisfies the equation \(A(c_1 x_1 + c_2 x_2) = c_1 A x_1 + c_2 A x_2\).
Additionally, the operator is bounded if there exists a constant \(C \ge 0\) such that for all \(x \in X\), the inequality \(otag\|A x\| \le C \|x\|\) holds. This means the operator does not stretch the vectors too much.
Important points to remember:
- Linearity ensures the operator maintains the structure of vector addition and scalar multiplication.
- Boundedness ensures the operator does not distort vectors excessively.
Dual Space
The concept of a dual space is integral to functional analysis. The dual space \(Y^*\) of a normed vector space \(Y\) consists of all bounded linear functionals on \(Y\). Here's a breakdown:
A functional \(f \in Y^*\) is a mapping \(f: Y \rightarrow \mathbb{R}\) or \(\mathbb{C}\) (depending on whether the field is real or complex), that satisfies two conditions:
Applications of dual spaces include:
A functional \(f \in Y^*\) is a mapping \(f: Y \rightarrow \mathbb{R}\) or \(\mathbb{C}\) (depending on whether the field is real or complex), that satisfies two conditions:
- Linearity: \(f(c_1 y_1 + c_2 y_2) = c_1 f(y_1) + c_2 f(y_2)\) for all \(y_1, y_2 \in Y\) and scalars \(c_1, c_2\).
- Boundedness: There exists a constant \(M \ge 0\) such that \(|f(y)| \le M \|y\|\) for all \(y \in Y\).
Applications of dual spaces include:
- Optimization and minimization problems.
- Hypothetical reasoning about properties of spaces (like reflexivity).
Functional Analysis
Functional analysis is the study of vector spaces endowed with some kind of limit-related structure and the linear operators acting upon these spaces. Key elements of functional analysis include normed spaces, Banach spaces, and Hilbert spaces.
Some core concepts you should know:
Some real-world applications include:
Some core concepts you should know:
- Normed Spaces: These are vector spaces with a norm, a function assigning a positive length or size to each vector, denoted as \(\|x\|\).
- Banach Spaces: Complete normed vector spaces, where every Cauchy sequence converges within the space.
- Hilbert Spaces: Complete inner-product spaces, which generalize Euclidean space and ensure the geometry of vectors can be studied using inner products.
Some real-world applications include:
- Quantum mechanics, where states and observables are studied within the framework of Hilbert spaces.
- Signal processing and data science, where functional spaces assist in analyzing functions and signals.