Chapter 12: Problem 15
Find a noncompact \(T \in S(H)\) such that \(T^{2}=0\). Can such an operator be normal?
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Chapter 12: Problem 15
Find a noncompact \(T \in S(H)\) such that \(T^{2}=0\). Can such an operator be normal?
These are the key concepts you need to understand to accurately answer the question.
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Suppose \(U \in S(H)\) is unitary, and \(\varepsilon>0\). Prove that scalars \(\alpha_{9}, \ldots, \alpha_{*}\) can be chosen so that $$ \left.\| U^{-1}-\alpha_{0} I-\alpha_{1} U-\cdots-\alpha_{4} U^{*}\right]<\varepsilon $$ if \(a(U)\) is a proper subset of the unit circle, but that this norm is never less than 1 if \(\sigma(U)\). covers the whole circle. Note: That \(\sigma(U)\) lies on the unit circle is contained in Theorem \(12.26\) but can be proved in a much more elementary way. Find such a proof.
Suppose \(N \in \mathscr{B}(H)\) is normal, and \(T \in B B(H)\) is invertible. Prove that \(T N T^{-1}\) is normal if and only if \(N\) commutes with \(T^{*} T\).
Does every normal \(T \in \mathscr{F}(H)\) have a square root in \(\Omega B(H) ?\) What can you say about the cardinality of the set of all square roots of \(T\) ? Can it happen that two square roots of the same \(T\) do not commute? Can this happen when \(T=I ?\)
Let \(H^{*}\) be the dual space of \(H ;\) define \(\phi: H^{*} \rightarrow H\) by $$ y^{*}(x)=\left(x, \psi y^{*}\right) \quad\left(x \in H_{v} y^{*} \in H^{*}\right) $$ (See Theorem 12.5.) Prove that \(H^{*}\) is a Hilbert space, relative to the inner product $$ \left[x^{4}, y^{*}\right]=\left(\phi y^{*}, \psi x^{*}\right) $$ If \(\phi: H^{* *} \rightarrow H^{*}\) satisfics \(z^{* *}\left(y^{*}\right)=\left[y^{*}, \frac{\left.\phi z^{* *}\right]} \text { for all } y^{*} \in H^{*\right.\), and \(z^{* *}\) e \(H^{* *}\), prove that \psi\phi is an isomorphism of \(H^{* *}\) onto \(H\) whose existence implies that \(H\) is reflexive.
Suppose \(E\) is a resolution of the identity, as in Section 12.17, and prove that for all \(x \in H, y \in H\), and \(\omega \in M\).
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