Chapter 3: Problem 1
Show that \(f(\gamma)=\gamma^{n}\) is analytic in the whole plane for any integer \(n \geqslant 0\) whereas \(f(\gamma)=\gamma^{*}=a-i b\), is not analytic in any nonempty region.
Short Answer
Expert verified
\(\gamma^n\) is analytic everywhere; \(\gamma^*\) is not analytic anywhere.
Step by step solution
01
Define Analytic Function
A function is analytic at a point if it is differentiable in a neighborhood of that point. For entire analyticity, the function must be differentiable everywhere on the complex plane.
02
Show Differentiability of \(\gamma^n\)
The function \(f(\gamma)=\gamma^n\) can be differentiated as follows: its derivative is \(f'(\gamma) = n\gamma^{n-1}\). This derivative exists and is continuous for all \(\gamma\) on the complex plane.
03
Conclude Analyticity of \(\gamma^n\)
Since \(f'(\gamma) = n\gamma^{n-1}\) is differentiable everywhere on the complex plane, \(f(\gamma) = \gamma^n\) is analytic across the entire complex plane, fulfilling the criteria for an entire function.
04
Consider \(\gamma^*\) and the Definition
The conjugate function \(f(\gamma) = \gamma^*\) where \(\gamma = a + ib\) and \(\gamma^* = a - ib\), needs to be checked for differentiability. A function is differentiable at a point if it satisfies the Cauchy-Riemann equations.
05
Apply Cauchy-Riemann Equations to \(\gamma^*\)
The Cauchy-Riemann conditions require \(\frac{\partial u}{\partial a} = \frac{\partial v}{\partial b}\) and \(\frac{\partial u}{\partial b} = -\frac{\partial v}{\partial a}\), where the real and imaginary parts of \(f\) are \(u = a\), \(v = -b\). Here, \(\frac{\partial u}{\partial a} = 1\), \(\frac{\partial v}{\partial b} = -1\), \(\frac{\partial u}{\partial b} = 0\), and \(\frac{\partial v}{\partial a} = 0\). These conditions do not satisfy the Cauchy-Riemann equations.
06
Conclude Non-Analyticity of \(\gamma^*\)
Since the Cauchy-Riemann equations are not satisfied at any point, \(f(\gamma) = \gamma^*\) is not differentiable at any point, meaning it is not analytic in any non-empty region.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiability
Differentiability in the complex plane is a bit different from differentiability in real calculus. Here, a function is considered differentiable at a point if the derivative exists at that point and is defined as a limit. The uniqueness of the complex plane requires that this limit should be the same regardless of the path taken to approach the point. For example, polynomials like \(f(\gamma) = \gamma^n\), where n is a non-negative integer, are differentiable everywhere on the complex plane. This is because their derivatives \(n\gamma^{n-1}\) exist across all \(\gamma\) and their behavior is predictable and continuous. In contrast, a function needs to pass the Cauchy-Riemann test to check its differentiability, especially for non-polynomial functions. Differentiability across the entire complex plane is one of the requirements for a function to be analytic, often referred to as 'entire' when it holds throughout the plane.
Cauchy-Riemann equations
The Cauchy-Riemann equations serve as a crucial criterion for determining whether a function of a complex variable is differentiable at a point. They relate the partial derivatives of the real and imaginary parts of a function, typically expressed as \(f(u + iv) = u + iv\), into two sets of equations: \(\frac{\partial u}{\partial a} = \frac{\partial v}{\partial b}\) and \(\frac{\partial u}{\partial b} = -\frac{\partial v}{\partial a}\). For example, when evaluating the conjugate function \(f(\gamma) = \gamma^* = a - ib\), if the equations are not fulfilled, then the function is not differentiable at that point.
- If \(\frac{\partial u}{\partial a} = 1\) and \(\frac{\partial v}{\partial b} = -1\) do not match, the function fails Cauchy-Riemann.
- Similarly, with \(\frac{\partial u}{\partial b} = 0\) and \(\frac{\partial v}{\partial a} = 0\), we cannot find consistency in the equations.
Complex Plane
The complex plane is a mathematical concept that extends the idea of the one-dimensional number line to two dimensions by representing complex numbers. On this plane, every complex number \(\gamma = a + ib\) is a point where \(a\) and \(b\) correspond to the coordinates on the horizontal (real) and vertical (imaginary) axes respectively. Functions that are analytic, like polynomials of \(\gamma\) such as \(\gamma^n\), behave nicely across the complex plane because they fulfill conditions of differentiability everywhere.However, some functions, like the conjugate \(\gamma^* = a - ib\), behave differently. They might look simple but checking their behavior for analytic properties reveals the importance of properties like differentiability and the Cauchy-Riemann equations. The complex plane allows extensive visualization, helping grasp how these formulas map into different outputs and their behavior under transformation, becoming an indispensable tool for mathematical analysis.