Chapter 3: Problem 3
Let \(f \in G(\mathbb{R})\). Determine the Fourier transform of (a) \(f(-x)\) (b) \(f\left(x-x_{0}\right), x_{0}\) is a real constant (c) \(f(x) e^{i \omega_{0} x}, \omega_{0}\) is a real constant (d) \(f(x) \sin \omega_{0} x\) (e) \(f(x) \cos \omega_{0} x\) (f) \(e^{i x} f(3 x)\) (g) \(f(2 x)\)
Short Answer
Step by step solution
Fourier Transform of Negative Argument
Fourier Transform of a Shifted Function
Fourier Transform of a Modulated Function
Fourier Transform of Function Sine Modulation
Fourier Transform of Function Cosine Modulation
Fourier Transform of a Scaled and Modulated Function
Fourier Transform of a Scaled Function
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Shifted Function
Imagine the function is shifted by a constant \(x_0\). Mathematically, this is represented as \(f(x-x_0)\). The core idea here is that this shift results in multiplying the Fourier Transform of the original function by a complex exponential factor. The new Fourier Transform becomes \(e^{-i\xi x_0} \mathcal{F}\{f(x)\}\). This means that shifting the function in the time domain results in a phase shift in the frequency domain.
- This is an essential property when dealing with real-world signals being time-shifted, like audio signals or control systems.
- The phase shift depends directly on the amount of shift and the frequency component.
Modulated Function
The Fourier Transform of the modulated function \(f(x) e^{i\omega_0 x}\) translates into shifting the frequency components by \(\omega_0\). It looks like \(\mathcal{F}\{f(x)\}(\xi - \omega_0)\). This means modulation in the time domain leads to a frequency shift in the frequency domain.
- This property is widely used in signal processing, such as amplitude modulation (AM) in radio broadcasting or in analytical work with different frequencies.
- Modulation affects the position of the spectrum without altering its shape.
Scaling in Fourier Transform
When you scale a function, it results in adjusting both the frequency components and the amplitude in a specific way. Suppose we scale the function by \(2\), resulting in \(f(2x)\). The Fourier Transform becomes \(\frac{1}{2} \mathcal{F}\{f(x)\}\left(\frac{\xi}{2}\right)\). The scaling of the input results in a compression or expansion of the frequency domain.
- The frequencies become compressed or expanded by the scaling factor.
- The amplitude is inversely scaled, balancing the overall energy of the signal.
Sine and Cosine Modulation
Let's start with sine modulation: Represent sine as \(\frac{e^{i\omega_0 x} - e^{-i\omega_0 x}}{2i}\). The Fourier transform of \(f(x)\sin(\omega_0 x)\) uses the properties of sine's imaginary components, ultimately leading to a combination using the shifts \(\mathcal{F}\{f(x)\}(\xi-\omega_0)\) and \(\mathcal{F}\{f(x)\}(\xi+\omega_0)\).
Now, for cosine modulation: Express cosine as \(\frac{e^{i\omega_0 x} + e^{-i\omega_0 x}}{2}\), leading to a similar resultant form. In this scenario, the resulting Fourier transform has terms added together rather than subtracted, creating a direct correspondence to shifted frequency components.
- Sine modulation results in imaginary outputs, beneficial in specific analytic applications.
- Cosine modulation leads to real outputs, widely used in signal processing.