Chapter 6: Problem 29
Solve the following problem for a modified wave equation:
$$
\begin{aligned}
&u_{x x}=u_{t t}+2 u_{t}, 0
Short Answer
Expert verified
The solution is \( u(x,t) = e^{-t}(\sin x + \sin 3x) \).
Step by step solution
01
Analyze the Boundary and Initial Conditions
We need to solve the equation \( u_{xx} = u_{tt} + 2u_t \) with boundary conditions \( u(0,t) = u(\pi,t) = 0 \) and initial conditions \( u(x,0) = \sin x + \sin 3x \) and \( u_t(x,0) = 0 \). The boundary conditions suggest a separation of variables method with sine functions.
02
Utilize Separation of Variables
Assume a solution in the form \( u(x,t) = X(x)T(t) \). Substituting into the wave equation, we get \( X''(x)T(t) = X(x)(T''(t) + 2T'(t)) \). Dividing through by \( X(x)T(t) \) and separating variables, we have \[ \frac{X''(x)}{X(x)} = \frac{T''(t) + 2T'(t)}{T(t)} = -\lambda. \] This suggests two separate ordinary differential equations for \( X(x) \) and \( T(t) \).
03
Solve the Spatial Part
The spatial part is \( X''(x) + \lambda X(x) = 0 \) with boundary conditions \( X(0) = X(\pi) = 0 \). This is a standard boundary problem whose solutions are \( X_n(x) = \sin(nx) \), where \( \lambda = n^2 \), \( n = 1, 2, 3, \ldots \).
04
Solve the Temporal Part
The temporal part is \( T''(t) + 2T'(t) + (n^2)T(t) = 0 \). This is a homogeneous linear second-order differential equation. Assume a solution \( T(t) = e^{rt} \), giving a characteristic equation \( r^2 + 2r + n^2 = 0 \). Solving for \( r \), we get \( r = -1 \pm \sqrt{1-n^2} \).
05
Consider General Solution and Initial Conditions
The general solution is \( u(x,t) = \sum_{n=1}^\infty ( A_n e^{(-1 + \sqrt{1-n^2})t} + B_n e^{(-1 - \sqrt{1-n^2})t} ) \sin(nx) \). Apply initial conditions: \( u(x,0) = \sin(x) + \sin(3x) \) and \( u_t(x,0) = 0 \). Express \( u(x,0) \) as a series and determine coefficients \( A_n \) and \( B_n \) from these conditions.
06
Determine Coefficients
From initial conditions \( u(x,0) = \sin(x) + \sin(3x) \), compare with the series form to find \( A_1 + B_1 = 1 \), \( A_3 + B_3 = 1 \), and \( A_n = B_n = 0 \) for \( n eq 1, 3 \). Using \( u_t(x,0) = 0 \), we find \(-A_n(1-\sqrt{1-n^2}) - B_n(1+\sqrt{1-n^2}) = 0 \), which implies a relation between \( A_n \) and \( B_n \). Combining these, we find \( A_n = B_n = 0 \) for other terms.
07
Construct Final Solution
Substitute values into the general solution to get \[ u(x,t) = \left( e^{(-1 + \sqrt{1-1^2})t} + e^{(-1 - \sqrt{1-1^2})t} \right)\sin(x) + \left( e^{(-1 + \sqrt{1-3^2})t} + e^{(-1 - \sqrt{1-3^2})t} \right)\sin(3x). \] Simplifying, \( u(x,t) = e^{-t}\cos(\sqrt{1-1^2}t)\sin(x) + e^{-t}\cos(\sqrt{1-3^2}t)\sin(3x) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Wave Equation
The wave equation is a quintessential partial differential equation that describes the distribution of waves, such as sound or light, through different mediums. In its simplest form, the classic wave equation is given by: \[ u_{tt} = c^2 u_{xx} \] where \( u \) represents the wave function, \( t \) is time, \( x \) is spatial dimension, and \( c \) is the speed of the wave. For the exercise at hand, the modified wave equation is:\[ u_{xx} = u_{tt} + 2u_t \] which adds a damping term \( 2u_t \). This term accounts for energy loss in the wave as it propagates, a scenario often encountered in real-world situations. Here, the challenge is to observe how this modifying term alters the behavior of the solution compared to the classical wave equation, particularly in a bounded domain.
Boundary Conditions
Boundary conditions are essential for solving differential equations as they provide additional information that specifies a unique solution. In one-dimensional wave equations, boundary conditions usually specify the behavior of the wave at the spatial edges. For our problem, the boundary conditions are specified as:
- \( u(0, t) = 0 \)
- \( u(\pi, t) = 0 \)
Separation of Variables
Separation of variables is a powerful mathematical technique used to simplify the process of solving partial differential equations. The idea is to assume that the solution can be expressed as a product of functions, each a function of a single variable. For our wave equation, we propose:\[ u(x, t) = X(x)T(t) \]Substituting this form into the wave equation allows us to separate the functions and form two ordinary differential equations:
- \( X''(x) = -\lambda X(x) \)
- \( T''(t) + 2T'(t) = -\lambda T(t) \)
Initial Conditions
Initial conditions are specific requirements given at the starting point of the time variable, specifically \( t = 0 \), which help determine the unique solution to our differential equation. In this exercise, the initial conditions are:
- \( u(x, 0) = \sin x + \sin 3x \)
- \( u_t(x, 0) = 0 \)