Chapter 6: Problem 4
For each of the following functions, state whether Rolle's Theorem applies for the given interval: (a) \(f(x)=\tan x, \quad x \in[0, \pi] ;\) (b) \(f(x)=x+3|x-1|, \quad x \in[0,2]\); (c) \(f(x)=x-9 x^{17}+8 x^{18}, \quad x \in[0,1] ;\) (d) \(f(x)=\sin x+\tan ^{-1} x, \quad x \in\left[0, \frac{1}{2} \pi\right]\).
Short Answer
Step by step solution
Understand Rolle's Theorem
Analyze (a) \(f(x) = \tan x\) on \([0, \pi]\)
Analyze (b) \(f(x) = x + 3|x-1|\) on \([0, 2]\)
Analyze (c) \(f(x) = x - 9x^{17} + 8x^{18}\) on \([0, 1]\)
Analyze (d) \(f(x) = \sin x + \tan^{-1} x\) on \([0, \frac{1}{2}\pi]\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Continuity in Calculus
- Continuous functions have no gaps, jumps, or asymptotes in their domain.
- Understanding continuity allows us to predict the behavior of functions across intervals.
Differentiability
Differentiability necessitates that a function be continuous at that point, but it is stronger because not all continuous functions are differentiable.
- A function is differentiable on \((a, b)\) if it has derivatives at every point within that open interval.
- This requirement prevents functions like \( f(x) = x + 3|x-1| \) on \([0, 2]\) from meeting Rolle's Theorem, as the absolute value results in a non-differentiable point at \( x = 1 \).
Polynomial Functions
- They are differentiable and continuous everywhere over the real number line.
- The polynomial function \( f(x) = x - 9x^{17} + 8x^{18} \) on \([0, 1]\) is both continuous and differentiable over its domain, enabling Rolle's Theorem to hold as \( f(0) = f(1) = 0 \).
Interval Analysis
To apply Rolle's Theorem, a function must satisfy its conditions over a specific closed interval \([a, b]\), meaning that you must thoroughly check both endpoint values \( f(a) \) and \( f(b) \).
- If \( f(a) eq f(b) \), as in \( f(x) = \sin x + \tan^{-1} x \) over \([0, \frac{\pi}{2}]\), then Rolle's Theorem cannot be applied.
- It's crucial to verify these intervals for both continuity and differentiability, ensuring that the theorem's conditions are wholly fulfilled.