/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 For each of the following functi... [FREE SOLUTION] | 91Ó°ÊÓ

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For each of the following functions, state whether Rolle's Theorem applies for the given interval: (a) \(f(x)=\tan x, \quad x \in[0, \pi] ;\) (b) \(f(x)=x+3|x-1|, \quad x \in[0,2]\); (c) \(f(x)=x-9 x^{17}+8 x^{18}, \quad x \in[0,1] ;\) (d) \(f(x)=\sin x+\tan ^{-1} x, \quad x \in\left[0, \frac{1}{2} \pi\right]\).

Short Answer

Expert verified
Rolle's Theorem applies only to (c).

Step by step solution

01

Understand Rolle's Theorem

Rolle's Theorem states that if a function \( f \) is continuous on the closed interval \([a, b]\), differentiable on the open interval \((a, b)\), and \( f(a) = f(b) \), then there exists at least one \( c \) in \((a, b)\) such that \( f'(c) = 0 \). The key conditions are continuity, differentiability, and equal values at endpoints.
02

Analyze (a) \(f(x) = \tan x\) on \([0, \pi]\)

The function \( f(x) = \tan x \) is not continuous on the interval \([0, \pi]\) since it has vertical asymptotes at \(\frac{\pi}{2}\). As continuity is required, Rolle's Theorem does not apply here.
03

Analyze (b) \(f(x) = x + 3|x-1|\) on \([0, 2]\)

The function \( f(x) = x + 3|x-1| \) is continuous but not differentiable at \( x = 1 \) due to the absolute value function, which creates a corner point. Since differentiability is required, Rolle's Theorem does not apply.
04

Analyze (c) \(f(x) = x - 9x^{17} + 8x^{18}\) on \([0, 1]\)

The function is a polynomial, which is continuous and differentiable everywhere. Additionally, \( f(0) = 0\) and \( f(1) = 0 \). Therefore, all conditions of Rolle's Theorem are satisfied, and the theorem applies.
05

Analyze (d) \(f(x) = \sin x + \tan^{-1} x\) on \([0, \frac{1}{2}\pi]\)

The function \( f(x) = \sin x + \tan^{-1} x \) is continuous and differentiable on \([0, \frac{\pi}{2}]\). However, \( f(0) eq f(\frac{\pi}{2}) \) because \(\sin(0) + \tan^{-1}(0) = 0\) and \(\sin(\frac{\pi}{2}) + \tan^{-1}(\frac{\pi}{2})\) is non-zero. Therefore, the theorem does not apply.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Continuity in Calculus
In calculus, continuity is a crucial concept that serves as a foundation for many theorems, including Rolle's Theorem. A function is said to be continuous on an interval if, intuitively, you can draw it on a graph without lifting your pen. Mathematically, a function \( f(x) \) is continuous at a point \( x = a \) if three conditions are satisfied: the limit of \( f(x) \) as \( x \) approaches \( a \) exists, \( f(a) \) exists, and the limit equals \( f(a) \).

  • Continuous functions have no gaps, jumps, or asymptotes in their domain.
  • Understanding continuity allows us to predict the behavior of functions across intervals.
Rolle's Theorem requires that the function is continuous over a closed interval \([a, b]\). If even a single discontinuity exists within this interval, like the vertical asymptote present in the function \( f(x) = \tan x \) at \( x = \frac{\pi}{2} \), Rolle’s Theorem cannot be applied. Therefore, checking continuity is a vital first step when applying the theorem.
Differentiability
Differentiability refers to a function's capability to have a derivative at a certain point. If a function \( f(x) \) is differentiable at \( x = a \), it means that the function has a well-defined tangent at that point — visually, there are no sharp corners or vertical tangents.

Differentiability necessitates that a function be continuous at that point, but it is stronger because not all continuous functions are differentiable.

  • A function is differentiable on \((a, b)\) if it has derivatives at every point within that open interval.
  • This requirement prevents functions like \( f(x) = x + 3|x-1| \) on \([0, 2]\) from meeting Rolle's Theorem, as the absolute value results in a non-differentiable point at \( x = 1 \).
Assessing differentiability ensures ensuring a smooth curve between the selected endpoints, essential for Rolle's Theorem.
Polynomial Functions
Polynomial functions stand out as one of the most straightforward types to analyze within calculus because they possess favorable properties like continuity and differentiability everywhere on their domain. A polynomial function is a mathematical expression involving a sum of powers in one or more variables multiplied by coefficients.

  • They are differentiable and continuous everywhere over the real number line.
  • The polynomial function \( f(x) = x - 9x^{17} + 8x^{18} \) on \([0, 1]\) is both continuous and differentiable over its domain, enabling Rolle's Theorem to hold as \( f(0) = f(1) = 0 \).
This reliability of polynomial functions makes them ideal candidates for the application of Rolle's Theorem, provided they meet the theorem's endpoint condition.
Interval Analysis
Interval analysis involves inspecting the behavior of functions over specified intervals — either closed \([a, b]\) or open \((a, b)\).

To apply Rolle's Theorem, a function must satisfy its conditions over a specific closed interval \([a, b]\), meaning that you must thoroughly check both endpoint values \( f(a) \) and \( f(b) \).

  • If \( f(a) eq f(b) \), as in \( f(x) = \sin x + \tan^{-1} x \) over \([0, \frac{\pi}{2}]\), then Rolle's Theorem cannot be applied.
  • It's crucial to verify these intervals for both continuity and differentiability, ensuring that the theorem's conditions are wholly fulfilled.
Proper interval analysis helps identify whether all the criteria for Rolle's Theorem are met, which is essential for a valid conclusion.

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Most popular questions from this chapter

By applying Cauchy's Mean Value Theorem to the functions $$ f(x)=x^{3}+x^{2} \sin x \text { and } g(x)=x \cos x-\sin x \text { on }[0, \pi] $$ prove that the equation \(3 x=\left(\pi^{2}-2\right) \sin x-x \cos x\) has at least one root in \((0, \pi)\).

Find the derivative of each of the following functions: (a) \(f(x)=\sinh \left(x^{2}\right), x \in \mathbb{R}\); (b) \(f(x)=\sin (\sinh 2 x), x \in \mathbb{R}\); (c) \(f(x)=\sin \left(\frac{\cos 2 x}{x^{2}}\right), x \in(0, \infty)\).

Find the derivative of each of the following functions (a) \(f(x)=\sinh x, x \in \mathbb{R}\); (b) \(f(x)=\cosh x, x \in \mathbb{R}\); (c) \(f(x)=\tanh x, x \in \mathbb{R}\).

Prove that the following limits exist, and evaluate them. (a) \(\lim _{x \rightarrow 0} \frac{\sinh 2 x}{\sin 3 x}\); (b) \(\lim _{x \rightarrow 0} \frac{(1+x)^{\frac{1}{5}}-(1-x)^{\frac{1}{5}}}{(1+2 x)^{\frac{2}{3}}-(1-2 x)^{2}}\) (c) \(\lim _{x \rightarrow 0} \frac{\sin \left(x^{2}+\sin x^{2}\right)}{1-\cos 4 x}\); (d) \(\lim _{x \rightarrow 0} \frac{\sin x-x \cos x}{x^{3}}\).

Determine whether the function $$ f(x)= \begin{cases}-x^{2}, & -2 \leq x<0 \\ x^{4}, & 0 \leq x<1 \\ x^{3}, & 1 \leq x \leq 2 \\ 0, & x>2\end{cases} $$ is differentiable at the points \(c=-2,0,1\) and 2, and determine the corresponding derivatives when they exist. Hint: \(\quad\) Sketch the graph \(y=f(x)\) first. Remarks Just as with continuity, the definition of differentiability involves a function These remarks are analogous \(f\) defined on a set in \(\mathbb{R}\), the domain \(A\) (say), that maps \(A\) to another set in \(\mathbb{R}\), to similar remarks for the codomain \(B\) (say). Sub-section 4.1.1. 1\. Let \(f\) and \(g\) be functions defined on open intervals \(I\) and \(J\), respectively, where \(I \supseteq J ;\) and let \(f(x)=g(x)\) on \(J .\) Technically \(g\) is a different function from \(f\). However, if \(f\) is differentiable at an interior point \(c\) of \(J\), it is a simple matter of some definition checking to verify that \(g\) too is differentiable at \(c .\) Similarly, if \(f\) is non- differentiable at \(c, g\) too is nondifferentiable at \(c\). 2\. The underlying point here is that differentiability at a point is a local property. It is only the behaviour of the function near that point that determines whether it is differentiable at the point.

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