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Determine the maximin and minimax strategies for each two-person, zero-sum matrix game. $$ \left[\begin{array}{rr} -1 & 3 \\ 2 & 5 \end{array}\right] $$

Short Answer

Expert verified
The maximin strategy for player 1 is to play row 2, and the minimax strategy for player 2 is to play column 1. The saddle point exists at position (2, 1), and the value of the game is 2.

Step by step solution

01

Identify Maximin Values for Player 1 (Row Player)

To find the maximin values for player 1, we need to determine the maximum of the minimum values in each row. In other words, we'll find the minimum value in each row and then select the row with the highest of these minimum values. Row 1 minimum: \(\min(-1, 3) = -1\) Row 2 minimum: \(\min(2, 5) = 2\) Maximin value for player 1: \(\max(-1, 2) = 2\) The maximin value for player 1 occurs in the second row, so the maximin strategy for player 1 is playing row 2.
02

Identify Minimax Values for Player 2 (Column Player)

To find the minimax values for player 2, we need to determine the minimum of the maximum values in each column. In other words, we'll find the maximum value in each column and then select the column with the lowest of these maximum values. Column 1 maximum: \(\max(-1, 2) = 2\) Column 2 maximum: \(\max(3, 5) = 5\) Minimax value for player 2: \(\min(2, 5) = 2\) The minimax value for player 2 occurs in the first column, so the minimax strategy for player 2 is playing column 1.
03

Check for Saddle Point

We'll check if there's a saddle point, which is a value that is both a maximin value for player 1 and a minimax value for player 2. If the saddle point exists, then we can determine the value of the game and the optimal strategies for both players. In this case, the maximin value for player 1 is 2, and the minimax value for player 2 is also 2. Since these values are equal, the saddle point exists at position (2, 1). Thus, the optimal strategy for player 1 is to play row 2 and the optimal strategy for player 2 is to play column 1. The value of the game is 2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Maximin Strategy
In a zero-sum game, a key approach for a player is to employ a maximin strategy. This is a defensive strategy used by a player to minimize their maximum possible loss, which can be quite useful when facing uncertainty about an opponent's moves. In essence, player 1, the row player, looks at the worst-case scenario payoff in each of their strategic options, which corresponds to the smallest number in each row of the payoff matrix.

To determine their maximin strategy, player 1 finds the minimum value for each of their possible moves (rows) and then chooses the move that has the highest of these minimal values. For example, in our exercise:
  • Row 1's minimum value is \( -1 \)
  • Row 2's minimum value is \( 2 \)
Then, player 1 chooses the higher value between the two, which in this case is \( 2 \) from Row 2. This approach ensures that, regardless of what the opponent does, the player secures the best of the worst-case outcomes.
Minimax Strategy
Conversely, the minimax strategy is adopted by the opposing player (player 2 or the column player) in the game, which acts as an offensive strategy mirroring the concept of the maximin. Player 2 seeks to maximize the minimum gain that can be secured, indicative of the best worst-case outcome from their viewpoint.

To apply this strategy, player 2 looks at the maximum values they could force the opponent to receive within each of their strategic moves (columns) and then select the move that gives them the least benefit. In the given exercise:
  • Column 1's maximum value is \( 2 \)
  • Column 2's maximum value is \( 5 \)
Out of these, player 2 will prefer to give player 1 the lower payment, hence they'll choose the \( 2 \) from Column 1. It guarantees the least advantage to the opponent, which, in turn, is the best outcome for player 2 under the assumption that player 1 is using their maximin strategy.
Saddle Point
A saddle point in the context of zero-sum games is a position on the payoff matrix where the strategies of both players intersect at the same value, reflecting the optimal decision for both. It presents a stable solution as it represents a scenario where neither player can benefit by unilaterally changing their strategy.

Finding a saddle point involves checking if the maximin value for player 1 matches the minimax value for player 2. If such a point exists, the payoff represented by that point is the value of the game. In other words, both players have optimized their strategies such that any deviation would only lead to equal or less favorable outcomes.

In our exercise, the value \( 2 \) serves as a saddle point found at the intersection of Row 2 and Column 1. This indicates that the optimal strategy for player 1 is to play Row 2 and for player 2 is to play Column 1, with the game's value being \( 2 \). This equality of maximin and minimax values ratifies the presence of a saddle point and, consequently, the most strategic moves both players can make.

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Most popular questions from this chapter

Find the expected payoff \(E\) of each game whose payoff matrix and strategies \(P\) and \(Q\) (for the row and column players, respectively) are given. \(\left[\begin{array}{rr}-1 & 4 \\ 3 & -2\end{array}\right], P=\left[\begin{array}{ll}.8 & .2\end{array}\right], Q=\left[\begin{array}{l}.6 \\\ .4\end{array}\right]\)

A psychologist conducts an experiment in which a mouse is placed in a T-maze, where it has a choice at the T-junction of turning left and receiving a reward (cheese) or turning right and receiving a mild electric shock (see accompanying figure). At the end of each trial, a record is kept of the mouse's response. It is observed that the mouse is as likely to turn left (state 1\()\) as right (state 2) during the first trial. In subsequent trials, however, the observation is made that if the mouse had turned left in the previous trial, then on the next trial the probability that it will turn left is 8 , whereas the probability that it will turn right is .2. If the mouse had turned right in the previous trial, then the probability that it will turn right on the next trial is \(.1\), whereas the probability that it will turn left is \(.9\). a. Using a tree diagram, describe the transitions between states and the probabilities associated with these transitions. b. Represent the transition probabilities obtained in part (a) in terms of a matrix. c. What is the initial-state probability vector? d. Use the results of parts (b) and (c) to find the probability that a mouse will turn left on the second trial.

Find the steady-state vector for the transition matrix. $$ \left[\begin{array}{lll} .1 & .2 & .3 \\ .1 & .2 & .3 \\ .8 & .6 & .4 \end{array}\right] $$

Find the optimal strategies, \(P\) and \(Q\), for the row and column players, respectively. Also compute the expected payoff \(E\) of each matrix game and determine which player it favors, if any, if the row and column players use their optimal strategies. \(\left[\begin{array}{rr}2 & 5 \\ -2 & 4\end{array}\right]\)

Find the steady-state vector for the transition matrix. $$ \left[\begin{array}{ll} \frac{4}{5} & \frac{3}{5} \\ \frac{1}{5} & \frac{2}{5} \end{array}\right] $$

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