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The transition matrix for a Markov process is given by $$ T=\begin{array}{l} \text { State } 1 \\ \text { State } 2 \end{array} \quad\left[\begin{array}{ll} .6 & .2 \\ .4 & .8 \end{array}\right] $$ and the initial-state distribution vector is given by $$ X_{0}=\begin{array}{l} \text { State 1 } \\ \text { State 2 } \end{array}\left[\begin{array}{l} .5 \\ .5 \end{array}\right] $$ Find \(T X_{0}\) and interpret your result with the aid of a tree diagram.

Short Answer

Expert verified
To find \(T X_{0}\), we square matrix T and multiply it with the initial state distribution vector \(X_{0}\). Performing the matrix multiplication, we have: \[ \begin{array}{l} Entry~1 = 0.6 \times 0.5 + 0.2 \times 0.5 = 0.4 \\ Entry~2 = 0.4 \times 0.5 + 0.8 \times 0.5 = 0.6 \end{array} \] So, \(T X_{0} = [0.4, 0.6]^T\). These values signify the probability of being in each corresponding state after the first transition. The tree diagram would show that both States 1 and 2 have a 0.5 chance of being the initial state and that after one transition, there is a 0.4 probability of being in State 1 and a 0.6 probability chance of being in State 2.

Step by step solution

01

Set up the multiplication

To multiply matrix T by vector X0, we have: $$ T X_{0} = \left[\begin{array}{ll} .6 & .2 \\ .4 & .8 \end{array}\right] \left[\begin{array}{l} .5 \\ .5 \end{array}\right] $$
02

Perform the multiplication

By performing the matrix multiplication, we calculate the elements of the resulting vector: $$ \mathrm{Entry}~1 = 0.6\cdot0.5 + 0.2\cdot0.5 \\ \mathrm{Entry}~2 = 0.4\cdot0.5 + 0.8\cdot0.5 $$ After calculating, we get the resulting vector: $$ T X_{0} = \left[\begin{array}{l} .4 \\ .6 \end{array}\right] $$
03

Interpret the result with a tree diagram

The resulting vector can be interpreted using a tree diagram, where each level of the tree represents the transition from one state to another. ``` Initial state (X0) --> First transition (T X0) State 1 (0.5) => State 1 (0.4) => State 2 (0.6) State 2 (0.5) => State 1 (0.4) => State 2 (0.6) ``` From the tree diagram and the resulting vector, we can see that after the first transition, there is a 0.4 probability of being in State 1 and a 0.6 probability of being in State 2, regardless of the initial state.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transition Matrix
A transition matrix is the heart of a Markov process, representing the probabilities of moving from one state to another. In essence, it's a tabular representation of the transitions probabilities between states in a stochastic process.

Illustratively, if we consider states as possible conditions or positions an entity can be in, the transition matrix provides the likelihood of moving from one condition to the next. With rows and columns that correspond to the states, each element in the matrix, usually denoted as T_{ij}, is the probability of transitioning from state i to state j.

To put into context using our exercise, the given transition matrix T contains probabilities that encapsulate switching between State 1 and State 2. If the system is currently in State 1, there is a 60% chance it will remain there, and a 40% probability it will move to State 2, and vice versa.
State Distribution Vector
The state distribution vector X_0 in a Markov process displays the initial probability distribution across the states. It's a way to express the starting conditions of your system at time zero before any transitions have occurred.

Each entry in this vector corresponds to the likelihood that the system is in a particular state at the starting point. For our exercise, the initial-state distribution vector has an equal probability of 0.5 or 50% for being in either State 1 or State 2 at the outset.

Understanding the state distribution vector is crucial; it's the starting line of our stochastic race, showing us where the probabilities are initially concentrated.
Matrix Multiplication
Matrix multiplication is a foundational operation in many mathematical computations, including in our case for computing the next state distribution in a Markov process.

To multiply a matrix by a vector, as shown in our exercise, every element of the resulting vector is a sum of products: each entry in the corresponding row of the matrix is multiplied by the corresponding entry in the vector, and then these products are summed to yield an entry in the resulting vector.

In the provided step-by-step solution, multiplying the transition matrix T by the state distribution vector X_0, we obtain the predicted distribution of the states after one transition. The act of matrix multiplication transforms our initial probabilities through the filter of transitional behaviors, embodied in T, to provide a new distribution vector.
Tree Diagram
To understand the dynamics of Markov processes beyond just calculations, tree diagrams emerge as a powerful visual tool. They help clarify the transitions between states by outlining each possible path the process can take.

A tree diagram starts with a node that branches out into several other nodes, each representing a state the system can transition to, with the probabilities written along the branches. It gains complexity with each step representing subsequent transitions, expanding like the branches of a tree.

In the exercise, the tree diagram presents a visual interpretation of the process after the first transition, simplifying the understanding of how probabilities split from the initial states to the subsequent ones. It depicts that regardless of starting in State 1 or State 2, after one transition, the probability of being in State 1 is 0.4 and in State 2 is 0.6.

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Most popular questions from this chapter

Brady's, a conventional department store, and ValueMart, a discount department store, are each considering opening new stores at one of two possible sites: the Civic Center and North Shore Plaza. The strategies available to the management of each store are given in the following payoff matrix, where each entry represents the amounts (in hundreds of thousands of dollars) either gained or lost by one business from or to the other as a result of the sites selected. a. Show that the game is strictly determined. b. What is the value of the game? c. Determine the best strategy for the management of each store (that is, determine the ideal locations for each store).

Determine the maximin and minimax strategies for each two-person, zero-sum matrix game. $$ \left[\begin{array}{rrr} -1 & 1 & 2 \\ 3 & 1 & 1 \\ -1 & 1 & 2 \\ 3 & 2 & -1 \end{array}\right] $$

Determine whether the two-person, zero-sum matrix game is strictly determined. If a game is strictly determined, a. Find the saddle point(s) of the game. b. Find the optimal strategy for each player. c. Find the value of the game. d. Determine whether the game favors one player over the other. $$ \left[\begin{array}{rrr} 1 & 3 & 2 \\ -1 & 4 & -6 \end{array}\right] $$

In a certain species of roses, a plant with genotype (genetic makeup) \(A A\) has red flowers, a plant with genotype \(A a\) has pink flowers, and a plant with genotype aa has white flowers, where \(A\) is the dominant gene and \(a\) is the recessive gene for color. If a plant with one genotype is crossed with another plant, then the color of the offspring's flowers is determined by the genotype of the parent plants. If a plant of each genotype is crossed with a pink-flowered plant, then the transition matrix used to determine the color of the offspring's flowers is given by $$ \left[\begin{array}{lll} \frac{1}{2} & \frac{1}{4} & 0 \\ \frac{1}{2} & \frac{1}{2} & \frac{1}{2} \\ 0 & \frac{1}{4} & \frac{1}{2} \end{array}\right] $$ If the offspring of each generation are crossed only with pink-flowered plants, in the long run what percentage of the plants will have red flowers? Pink flowers? White flowers?

Find \(X_{2}\) (the probability distribution of the system after two observations) for the distribution vector \(X_{0}\) and the transition matrix \(T\). \(X_{0}=\left[\begin{array}{l}.25 \\ .40 \\ .35\end{array}\right], T=\left[\begin{array}{ccc}.1 & .1 & .3 \\ .8 & .7 & .2 \\ .1 & .2 & .5\end{array}\right]\)

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