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The IQs of students at Wilson Elementary School were measured recently and found to be normally distributed with a mean of 100 and a standard deviation of 15 . What is the probability that a student selected at random will have an \(\mathrm{IQ}\) a. Of 140 or higher? b. Of 120 or higher? c. Between 100 and 120 ? d. Of 90 or less?

Short Answer

Expert verified
The probabilities for the given IQ ranges are as follows: a. The probability of a student having an IQ of 140 or higher is approximately 0.0038 or 0.38%. b. The probability of a student having an IQ of 120 or higher is approximately 0.092 or 9.2%. c. The probability of a student having an IQ between 100 and 120 is approximately 0.408 or 40.8%. d. The probability of a student having an IQ of 90 or less is approximately 0.2525 or 25.25%.

Step by step solution

01

1. Calculate the z-score for IQ 140

Plug in X = 140 into the z-score formula: \(Z = \cfrac{140 - 100}{15}\) Z ≈ 2.67
02

2. Find the probability from the z-table

Using the z-table, we find the probability corresponding to z = 2.67: P(Z ≥ 2.67) ≈ 0.0038 The probability of a student having an IQ of 140 or higher is approximately 0.0038 or 0.38%. #b. Probability of IQ 120 or higher#
03

1. Calculate the z-score for IQ 120

Plug in X = 120 into the z-score formula: \(Z = \cfrac{120 - 100}{15}\) Z ≈ 1.33
04

2. Find the probability from the z-table

Using the z-table, we find the probability corresponding to z = 1.33: P(Z ≥ 1.33) ≈ 0.092 The probability of a student having an IQ of 120 or higher is approximately 0.092 or 9.2%. #c. Probability of IQ between 100 and 120#
05

1. Calculate the probabilities for IQ 100 and 120

Since IQ 100 is the mean, it has a z-score of 0, and we already calculated the z-score for IQ 120 to be 1.33.
06

2. Find the probability from the z-table

Using the z-table, we find the probability corresponding to z = 1.33: P(0 ≤ Z ≤ 1.33) ≈ 0.408 The probability of a student having an IQ between 100 and 120 is approximately 0.408 or 40.8%. #d. Probability of IQ 90 or less#
07

1. Calculate the z-score for IQ 90

Plug in X = 90 into the z-score formula: \(Z = \cfrac{90 - 100}{15}\) Z ≈ -0.67
08

2. Find the probability from the z-table

Using the z-table, we find the probability corresponding to z = -0.67: P(Z ≤ -0.67) ≈ 0.2525 The probability of a student having an IQ of 90 or less is approximately 0.2525 or 25.25%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability refers to the likelihood of an event occurring. It ranges from 0 to 1, where 0 means the event will not happen, and 1 means it is certain to happen. When dealing with a normal distribution, probability helps us determine how likely it is for a particular outcome to occur under a defined set of circumstances. For example, in the context of IQ scores at Wilson Elementary, we calculate the probability of students having scores at certain values or ranges based on the normal distribution of those scores. Bullet points can help simplify these probabilities:
  • P(Z ≥ 2.67) ≈ 0.0038 for IQ of 140 or higher.
  • P(Z ≥ 1.33) ≈ 0.092 for IQ of 120 or higher.
  • P(0 ≤ Z ≤ 1.33) ≈ 0.408 for IQ between 100 and 120.
  • P(Z ≤ -0.67) ≈ 0.2525 for IQ of 90 or less.
Calculating probability with normal distribution involves using z-scores and referencing standard statistical tables.
Z-score
A z-score is a crucial statistical measurement that indicates how many standard deviations an element is from the mean of its distribution. In simpler terms, it shows the position of a score in relation to the average. For example, if a z-score is 0, this means the score is exactly at the mean.The formula for computing a z-score is: \[Z = \frac{X - \text{mean}}{ ext{standard deviation}}\]where:
  • \(X\) is the value you are examining.
  • \(\text{mean}\) is the average of the distribution.
  • \(\text{standard deviation}\) measures the dispersion of the dataset.
This calculation allows us to convert individual data points into their statistical relevance within the dataset. In the IQ example:
  • For an IQ of 140, the z-score is approximately 2.67.
  • For an IQ of 120, the z-score is approximately 1.33.
  • For an IQ of 90, the z-score is approximately -0.67.
Standard Deviation
Standard deviation is a statistical measurement that describes the dispersion or spread of data around the mean. A smaller standard deviation indicates that data points are close to the mean, while a larger standard deviation shows a spread-out distribution. In a normal distribution, which is symmetrical, the standard deviation helps us understand the variance of an entire dataset around the mean.
  • A standard deviation allows us to determine z-scores, which are then used to calculate probabilities.
  • It computes how much the data points differ from the average value.
In the Wilson Elementary IQ example, the standard deviation is 15. This value is critical in determining how typical or atypical a particular IQ score is. It tells us about the variation from an average IQ score of 100.
Mean
The mean is a statistical term that refers to the average value in a dataset. To find the mean, you sum up all the data values and then divide by the number of values. In a normal distribution, the mean determines the center of the dataset, with the distribution extending equally on either side. For IQ scores at Wilson Elementary, the mean is 100. This average score is the point around which the scores are spread. It is crucial because:
  • It serves as a reference point for calculating z-scores.
  • The entire normal distribution is symmetrical around this mean.
  • Every standard deviation calculated is in reference to this central point.
Understanding the mean helps in interpreting the dataset and determines how the standard deviation is calculated, which is pivotal for further statistical analysis like probability assessments.

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