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Let \(S=\\{1,2,3,4,5,6\\}, E=\\{2,4,6\\}\) \(\boldsymbol{F}=\\{1,3,5\\}\), and \(\boldsymbol{G}=\\{5,6\\}\). Find the event \((E \cup F \cup G)^{c}\).

Short Answer

Expert verified
The complement of the union \((E \cup F \cup G)^{c} = \emptyset\).

Step by step solution

01

1. Finding the Union of \(E, F,\) and \(G\)

To find the union of the three sets \(E, F\), and \(G\), we need to include all unique elements found in any of the sets. Here are the given sets: \(E = \{2, 4, 6\}\) \(F = \{1, 3, 5\}\) \(G = \{5, 6\}\) Now, let's combine all elements and eliminate any duplicates: \(E \cup F \cup G = \{1, 2, 3, 4, 5, 6\}\)
02

2. Finding the Complement of the Union \((E \cup F \cup G)^{c}\)

To find the complement of the union \((E \cup F \cup G)^{c}\), we need to include all elements in the sample space set \(S\) that are not included in the union set. Below is the given sample space: \(S = \{1, 2, 3, 4, 5, 6\}\) We can see that the union set \((E \cup F \cup G)\) is equal to the sample space \(S\). As a result, the complement set is an empty set because there are no elements in \(S\) that are not in \((E \cup F \cup G)\). So, the complement of the union \((E \cup F \cup G)^{c} = \emptyset\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Union of Sets
The concept of the union of sets is akin to bringing together different groups and finding what they all share collectively, but without repeating any members. When we perform a union, designated by the symbol \(\bigcup\), we're essentially combining all the unique elements from each set involved.

For example, in the exercise where we have sets \(E = \{2, 4, 6\}\), \(F = \{1, 3, 5\}\), and \(G = \{5, 6\}\), their union \(E \bigcup F \bigcup G\) includes every distinct number from these sets, which results in \(\{1, 2, 3, 4, 5, 6\}\). As you can notice, even though the number 5 appears in both sets \(F\) and \(G\), it is only counted once in the union set. This elimination of duplicates is a fundamental rule in forming the union of sets.
Complement of a Set
Imagine you have a complete set, let's call it a 'universal set', which contains all the possible elements under consideration. The complement of a set, symbolized by a superscript \(c\), is a way of finding out what's not included in a particular subset of this universal set. It's like looking at a puzzle and figuring out which pieces are missing to complete the picture.

In our exercise, the universal set is \(S = \{1, 2, 3, 4, 5, 6\}\), and after finding the union \((E \bigcup F \bigcup G)\), we discovered it's exactly the same as the universal set \(S\). Therefore, when we look for the complement \((E \bigcup F \bigcup G)^c\), we're searching for elements in \(S\) not found in the union. In this case, since the union covers all of \(S\), the complement is an empty set, represented by \(\emptyset\). This signifies that there are no pieces missing; our puzzle is complete.
Finite Mathematics
Finite mathematics covers a host of topics, but it's primarily known for dealing with objects that you can count using whole numbers. It doesn't concern itself with the notion of infinity; everything has a limit or an end. Within the realm of set theory in finite mathematics, understanding how sets interact through union and complement operations is key.

Set operations like these provide a foundation for various aspects of finite mathematics, including probability, statistics, and even discrete math. The exercise demonstrates how finite set operations work in practice, as we discovered the outcome of a union followed by a complement within a finite set \(S\). With these building blocks, finite mathematics can tackle more complex problems, all while remaining in the realm of the countable and the tangible.

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Most popular questions from this chapter

If a certain disease is present, then a blood test will reveal it \(95 \%\) of the time. But the test will also indicate the presence of the disease \(2 \%\) of the time when in fact the person tested is free of that disease; that is, the test gives a false positive \(2 \%\) of the time. If \(0.3 \%\) of the general population actually has the disease, what is the probability that a person chosen at random from the population has the disease given that he or she tested positive?

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Let \(E\) be any cvent in a sample space \(S .\) a. Are \(E\) and \(S\) independent? Explain your answer. b. Are \(E\) and \(\varnothing\) independent? Explain your answer.

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If a 5-card poker hand is dealt from a well-shuffled deck of 52 cards, what is the probability of being dealt the given hand? A flush (but not a straight flush)

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