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An experiment consists of randomly selecting one of three coins, tossing it, and observing the outcome-heads or tails. The first coin is a two-headed coin, the second is a biased coin such that \(P(\mathrm{H})=.75\), and the third is a fair coin. a. What is the probability that the coin that is tossed will show heads? b. If the coin selected shows heads, what is the probability that this coin is the fair coin?

Short Answer

Expert verified
a. The probability that the tossed coin will show heads is \(\frac{4}{6}\). b. If the coin selected shows heads, the probability that this coin is the fair coin is \(\frac{1}{4}\).

Step by step solution

01

Define the Events and Probabilities

We begin by defining the events: A1: Selecting the two-headed coin A2: Selecting the biased coin A3: Selecting the fair coin H: Tossing a coin and getting heads The probabilities of selecting each coin are equal and can be defined as follows: P(A1) = P(A2) = P(A3) = 1/3
02

Find the Probabilities of Getting Heads

We need to find the probabilities of getting heads given that we selected each coin. P(H|A1) = 1 (As this is a two-headed coin) P(H|A2) = 0.75 (As given in the problem) P(H|A3) = 0.5 (As this is a fair coin)
03

a. Calculate the Total Probability of Getting Heads

To find the total probability of getting heads after tossing the coin, we can use the Law of Total Probability. This law states that the probability of an event (H) can be calculated by summing the probabilities of each possible cause (A1, A2, or A3) and the probability of the event (H) given that cause. P(H) = P(H|A1)P(A1) + P(H|A2)P(A2) + P(H|A3)P(A3) Now, substituting the given probabilities, we get: P(H) = (1)(1/3) + (0.75)(1/3) + (0.5)(1/3) P(H) = 1/3 + 1/4 + 1/6 P(H) = 4/6 #Answer_a#: The probability that the tossed coin will show heads is 4/6.
04

b. Calculate the probability that the coin showing heads is the fair coin

Now we need to find the probability that the coin showing heads is the fair coin. For this, we can use Bayes' theorem. Bayes' theorem states that the conditional probability P(A3|H) can be found using the following formula: P(A3|H) = P(H|A3)P(A3) / P(H) We have already calculated P(H) in step a, and we know P(H|A3) and P(A3) from step 1. Now, we substitute these values into the formula: P(A3|H) = (0.5)(1/3) / (4/6) Simplify the expression: P(A3|H) = (0.5)(1/3) / (2/3) P(A3|H) = 1/4 #Answer_b#: If the coin selected shows heads, the probability that this coin is the fair coin is 1/4.

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