/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Determine which of the sequences... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine which of the sequences are geometric progressions. For each geometric progression, find the seventh term and the sum of the first seven terms. $$ 1,-\frac{1}{2}, \frac{1}{4},-\frac{1}{8}, \ldots $$

Short Answer

Expert verified
The given sequence is a geometric progression with a common ratio of \(-\frac{1}{2}\). The seventh term is \(\frac{1}{64}\), and the sum of the first seven terms is \(\frac{129}{192}\).

Step by step solution

01

To check if the given sequence is a geometric progression, we need to verify if the ratio between consecutive terms is constant. We can calculate the ratio by dividing the second term by the first term, the third term by the second term, and so on, and then check if the values obtained are the same. #Step 2: Calculate the common ratio#

Let's calculate the ratio between consecutive terms: \(r_1 = \frac{-\frac{1}{2}}{1} = -\frac{1}{2}\) \(r_2 = \frac{\frac{1}{4}}{-\frac{1}{2}} = -\frac{1}{2}\) \(r_3 = \frac{-\frac{1}{8}}{\frac{1}{4}} = -\frac{1}{2}\) The ratios are the same, so the given sequence is a geometric progression with a common ratio (r) of -1/2. #Step 3: Find the seventh term#
02

To find the seventh term (a_7) of the geometric progression, we'll use the formula: \(a_n = a_1r^{n-1}\) where a_1 is the first term, r is the common ratio, and n is the term being sought (in this case, n = 7). \(a_7 = 1\cdot (-\frac{1}{2})^{7-1}\) #Step 4: Calculate the seventh term#

Now, we plug in values to find a_7: \(a_7 = 1\cdot (-\frac{1}{2})^{6}\) \(a_7 = 1\cdot (\frac{1}{64})\) \(a_7 = \frac{1}{64}\) So, the seventh term of the geometric progression is 1/64. #Step 5: Calculate the sum of the first seven terms#
03

To calculate the sum (S) of the first seven terms of the geometric progression, we will use the formula: \(S_n = \frac{a_1(r^n-1)}{r-1}\) where a_1 is the first term, r is the common ratio, and n is the number of terms (in this case, n=7). #Step 6: Evaluate the sum of the first seven terms#

Now, let's plug in our values: \(S_7 = \frac{1\cdot((-\frac{1}{2})^7 - 1)}{-\frac{1}{2}-1}\) \(S_7 = \frac{1\cdot(-\frac{1}{128} - 1)}{-\frac{3}{2}}\) \(S_7 = \frac{-\frac{129}{128}}{-\frac{3}{2}}\) \(S_7 = \frac{129}{128} \cdot \frac{2}{3}\) \(S_7 = \frac{129}{192}\) Hence, the sum of the first seven terms of this geometric progression is 129/192.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Common Ratio
A geometric progression is known for its constant ratio between consecutive terms. This constant factor is called the common ratio, and it is essential in determining the nature of the sequence. To verify if a sequence is a geometric progression, we can find the ratio between consecutive terms.

In our example sequence: 1, -\(\frac{1}{2}\), \(\frac{1}{4}\), -\(\frac{1}{8}\), ... , we calculate:
  • First ratio: \(\frac{-\frac{1}{2}}{1} = -\frac{1}{2}\)
  • Second ratio: \(\frac{\frac{1}{4}}{-\frac{1}{2}} = -\frac{1}{2}\)
  • Third ratio: \(\frac{-\frac{1}{8}}{\frac{1}{4}} = -\frac{1}{2}\)
These identical ratios confirm that the sequence is indeed a geometric progression, with a common ratio of \(-\frac{1}{2}\). Recognizing this common ratio helps us understand the growth or decay pattern in sequence of numbers.
Finding the Seventh Term
To find a specific term in a geometric progression, we use a simple formula involving the common ratio. The formula is:

\[a_n = a_1r^{n-1}\]
where
  • \(a_1\) represents the first term,
  • \(r\) is the common ratio,
  • \(n\) is the position of the term we want to find.
In this scenario, the first term \(a_1\) is 1, the common ratio \(r\) is \(-\frac{1}{2}\), and we need to find the seventh term, so \(n = 7\).

Plugging in these values:

\[a_7 = 1\cdot(-\frac{1}{2})^{7-1} = \frac{1}{64}\]
This calculation shows that the seventh term in this particular sequence is \(\frac{1}{64}\). This formula is handy because it allows us to directly find any term in the sequence without listing all preceding terms.
Calculating the Sum of Terms
The sum of terms in a geometric progression provides valuable information about the overall pattern and trend of the sequence. For a finite number of terms, the sum is calculated using the formula:

\[S_n = \frac{a_1(r^n - 1)}{r - 1}\]
where
  • \(a_1\) is the first term,
  • \(r\) is the common ratio,
  • \(n\) is the total number of terms we are summing.
In this example, the task is to find the sum of the first seven terms with \(a_1 = 1\), \(r = -\frac{1}{2}\), and \(n = 7\).

Substitute these into the formula:

\[S_7 = \frac{1((-\frac{1}{2})^7 - 1)}{-\frac{1}{2} - 1} = \frac{129}{192}\]
This computation reveals that the sum of the first seven terms of the series is \(\frac{129}{192}\). Knowing this sum helps in understanding the collective behavior of the terms, particularly useful in financial calculations and scientific measurements.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A state lottery commission pays the winner of the "Million Dollar" lottery 20 installments of \(\$ 50,000 /\) year. The commission makes the first payment of \(\$ 50,000\) immediately and the other \(n=19\) payments at the end of each of the next 19 yr. Determine how much money the commission should have in the bank initially to guarantee the payments, assuming that the balance on deposit with the bank earns interest at the rate of \(8 \% /\) year compounded vearly.

The Betzes have leased an auto for 2 yr at \(\$ 450 /\) month. If money is worth \(9 \%\) /year compounded monthly, what is the equivalent cash payment (present value) of this annuity?

The Kwans are planning to buy a house 4 yr from now. Housing experts in their area have estimated that the cost of a home will increase at a rate of 5\%lyear during that period. If this economic prediction holds true, how much can the Kwans expect to pay for a house that currently costs \(\$ 210,000 ?\)

Maxwell started a home theater business in \(2005 .\) The revenue of his company for that year was \(\$ 240,000\). The revenue grew by \(20 \%\) in 2006 and by \(30 \%\) in 2007. Maxwell projected that the revenue growth for his company in the next 3 yr will be at least \(25 \% /\) year. How much does Maxwell expect his minimum revenue to be for \(2010 ?\)

Juan is contemplating buying a zero coupon bond that matures in \(10 \mathrm{yr}\) and has a face value of \(\$ 10,000\). If the bond yields a return of \(5.25 \%\) lyear, how much should Juan pay for the bond?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.