/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Determine whether the statement ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. If at least one of the coefficients \(a_{1}, a_{2}, \ldots, a_{n}\) of the objective function \(P=a_{1} x_{1}+a_{2} x_{2}+\cdots+a_{n} x_{n}\) is positive, then \((0,0, \ldots, 0)\) cannot be the optimal solution of the standard (maximization) linear programming problem.

Short Answer

Expert verified
The statement is true because in a standard maximization linear programming problem, having at least one positive coefficient in the objective function will cause the objective function to increase when the corresponding variable increases. This means that starting from the point \((0, 0, ..., 0)\), we can always find at least one direction (by increasing the variable with a positive coefficient) that will increase the objective function's value, given that this movement stays within the feasible region.

Step by step solution

01

Analyze the statement

We're given a standard maximization linear programming problem: Objective function: \(P = a_1x_1 + a_2x_2 + \cdots + a_nx_n\) We want to maximize P subject to some constraints (inequalities). The statement suggests that if at least one of the coefficients \((a_1, a_2, ..., a_n)\) is positive, then the optimal solution can't be at the point where all the variables are equal to zero \((0, 0, ..., 0)\). We will test this statement.
02

Look for counterexamples or validate the statement

Let's suppose we have a linear programming problem with the following setup: Objective function: \(P = x_1 + x_2\) Constraints: \(x_1 \geq 1\) \(x_2 \geq 1\) We are supposed to find the solution that maximizes the value of P, and at least one of the coefficients is positive. If we look at these constraints, we can see that the point \((0, 0)\) is not a feasible solution, as it doesn't satisfy the constraints. We'll try another example to test the statement: Objective function: \(P = -x_1 + x_2\) Constraints: \(x_1 \leq 1\) \(x_2 \geq 1\) In this case, the all-zero point is not an optimal solution because the constraints do not allow it. Also, it's crucial to note that even at the point \((1,1)\), which lies within the feasible region, it is still not an optimal solution, as increasing \(x_2\) will increase the value of P. Since we haven't found any counterexamples yet, we can conclude the statement is true.
03

Explanation of why the statement is true

The statement is true because, in a standard maximization linear programming problem, having at least one positive coefficient in the objective function will cause the objective function to increase when the corresponding variable increases. This means that starting from the point \((0, 0, ..., 0)\), we can always find at least one direction (by increasing the variable with a positive coefficient) that will increase the objective function's value, given that this movement stays within the feasible region. In conclusion, the statement is true: If at least one of the coefficients \(a_{1}, a_{2}, \ldots, a_{n}\) of the objective function \(P=a_{1} x_{1}+a_{2} x_{2}+\cdots+a_{n} x_{n}\) is positive, then the all-zero solution \((0,0, \ldots, 0)\) cannot be the optimal solution of the standard (maximization) linear programming problem.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Steinwelt Piano manufactures uprights and consoles in two plants, plant I and plant II. The output of plant I is at most \(300 /\) month, whereas the output of plant II is at most \(250 /\) month. These pianos are shipped to three warehouses that serve as distribution centers for the company. To fill current and projected orders, warehouse A requires a minimum of 200 pianos/month, warehouse B requires at least 150 pianos/month, and warehouse \(\mathrm{C}\) requires at least 200 pianos/month. The shipping cost of each piano from plant I to warehouse A, warehouse \(\mathrm{B}\), and warehouse \(\mathrm{C}\) is \(\$ 60, \$ 60\), and \(\$ 80\), respectively, and the shipping cost of each piano from plant II to warehouse A, warehouse B, and warehouse \(\mathrm{C}\) is \(\$ 80, \$ 70\), and \(\$ 50\), respectively. Use the method of this section to determine the shipping schedule that will enable Steinwelt to meet the warehouses' requirements while keeping the shipping costs to a minimum.

Solve each linear programming problem by the simplex method. $$ \begin{array}{ll} \text { Maximize } & P=4 x+6 y \\ \text { subject to } & 3 x+y \leq 24 \\ & 2 x+y \leq 18 \\ & x+3 y \leq 24 \\ & x \geq 0, y \geq 0 \end{array} $$

Solve each linear programming problem by the simplex method. $$ \begin{array}{ll} \text { Maximize } & P=5 x+4 y \\ \text { subject to } & 3 x+5 y \leq 78 \\ & 4 x+y \leq 36 \\ & x \geq 0, y \geq 0 \end{array} $$

Solve each linear programming problem by the simplex method. $$ \begin{array}{lc} \text { Maximize } & P=3 x+3 y+4 z \\ \text { subject to } & x+y+3 z \leq 15 \\ & 4 x+4 y+3 z \leq 65 \\ & x \geq 0, y \geq 0, z \geq 0 \end{array} $$

Use the method of this section to solve each linear programming problem. $$ \begin{array}{ll} \text { Maximize } & P=5 x+4 y+2 z \\ \text { subject to } & x+2 y+3 z \leq 24 \\ & x-y+z \geq 6 \\ x & \geq 0, y \geq 0, z \geq 0 \end{array} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.