/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 Determine whether the statement ... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. Suppose you are given the following linear programming problem: Maximize \(P=a x+b y\), where \(a>0\) and \(b>0\), on the feasible set \(S\) shown in the accompanying figure. Explain, without using Theorem 1 , why the optimal solution of the linear programming problem cannot occur at the point \(Q\) unless the problem has infinitely many solutions lying along the line segment joining the vertices \(A\) and \(B\). Hint: Let \(A\left(x_{1}, y_{1}\right)\) and \(B\left(x_{2}, y_{2}\right)\). Then \(Q(\bar{x}, \bar{y})\), where \(\bar{x}=x_{1}+\) \(\left(x_{2}-x_{1}\right) t\) and \(\bar{y}=y_{1}+\left(y_{2}-y_{1}\right) t\) with \(0

Short Answer

Expert verified
The statement is true. The optimal solution of the given linear programming problem cannot occur at point Q unless the problem has infinitely many solutions along the line segment joining vertices A and B. This is because the value of the objective function P increases along the line segment, and if there is an optimal solution at either point A or B, Q cannot be optimal. However, if there are infinitely many solutions along the line segment, multiple points with maximized P can be found and Q can be one of the optimal solutions.

Step by step solution

01

Variables and objective function

Let's denote the given linear programming problem as follows: - Vertices A and B: \(A(x_1, y_1)\) and \(B(x_2, y_2)\) - The point Q: \(Q(\bar{x}, \bar{y})\) - Objective function: \(P = ax + by\), where \(a > 0\) and \(b > 0\) - Point Q is located in the line segment between A and B: \(\bar{x}=x_1+\left(x_2-x_1\right)t\) and \( \bar{y}=y_1+\left(y_2-y_1\right)t\) with \(0 < t < 1\)
02

Objective Function at Point Q

Calculate the value of the objective function (P) at point Q. \(P_Q = a\bar{x} + b\bar{y} = a(x_1 + (x_2 - x_1)t) + b(y_1 + (y_2 - y_1)t)\)
03

Compare P at A and Q

Now, let's see how the value of P changes as we move from point A to point Q. \(P_Q - P_A = a(x_1 + (x_2 - x_1)t - x_1) + b(y_1 + (y_2 - y_1)t - y_1)\) \( = at(x_2 - x_1) + bt(y_2 - y_1)\) Since \(a, b > 0\) and \(0 < t < 1\), if \((x_2 - x_1) > 0\) and/or \((y_2 - y_1) > 0\), then \(P_Q - P_A > 0\), which means that P increases from point A to point Q.
04

Analyzing the statement

If the problem does not have infinitely many solutions along the line segment joining A and B, then there exists an optimal solution C either at point A or B. As we have proved in step 3, the value of P increases from A to Q. Thus, Q cannot be an optimal solution, because we can always find a better solution by choosing a point closer to A or B. On the other hand, if the problem has infinitely many solutions along the line segment joining A and B, then since P increases along the line segment, we can find multiple points along the line segment where P is maximized. In this case, Q can be one of the optimal solutions.
05

Conclusion

The statement is true. The optimal solution of the given linear programming problem cannot occur at point Q unless the problem has infinitely many solutions along the line segment joining vertices A and B.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Objective Function
In linear programming, the objective function is a mathematical representation of the goal that needs to be achieved, typically optimizing a certain quantity of interest. In the context of our exercise, the objective formulates a relationship between two variables, represented by the equation \( P = ax + by \), where \( a \) and \( b \) are positive constants, and \( x \) and \( y \) are the variables whose values we want to optimize.

The values that the objective function can take are dictated by the constraints of the problem. The exercise demonstrates how the value of the function changes when evaluated at different points within the feasible set. A noteworthy point here is that the objective function, as the name suggests, should align with what is being maximized or minimized (e.g., profit, cost, distance). Understanding the objective function is crucial for solving linear programming problems as it directs the search for the optimal solution.
Feasible Set
In a linear programming problem, the feasible set is simply the collection of all possible points that satisfy the problem's constraints. Constraints can include inequalities or equations that the variables must abide by. These constraints graphically form a region, and any solution that falls within this region is considered feasible.

As indicated in the exercise, point \( Q \) is a part of the feasible set \( S \) situated on the line segment joining the vertices \( A \) and \( B \), within the bounds defined by the conditions \( 0 < t < 1 \). It is essential for students to realize that not all points within the feasible set are optimal; however, the feasible set provides the boundaries within which the search for an optimal solution is conducted. It is equally important to visualize or sketch this set to have a better understanding of where an optimal solution might lie.
Optimal Solution
An optimal solution to a linear programming problem is the point or set of points within the feasible set that yield the best possible value of the objective function, adhering to all the problem's constraints. Through the steps provided in the exercise, we can understand that unless the problem allows for infinitely many solutions lying along the line segment that includes \( Q \), then \( Q \) itself cannot be the optimal solution.

Moreover, if the optimal solution lies at a boundary of the feasible set, as is often the case, it is typically found at a vertex or along an edge. However, in some instances, there may be multiple or even infinite optimal solutions – which occurs when the objective function's contours run parallel to a constraint boundary within the feasible set. A deep understanding of the problem's feasible set and objective function shape the path towards identifying where the optimal solution can be located.

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