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Find the graphical solution of each inequality. $$ 3 x+4 y \leq-2 $$

Short Answer

Expert verified
The graphical solution of the inequality \(3x + 4y \le -2\) is represented by the line with equation \(y = -\frac{3}{4}x - \frac{1}{2}\) and the region above that line.

Step by step solution

01

Rewrite the inequality as an equation

To find the graphical solution, we need to first find the equation of the line that represents the boundary of the inequality. We can do this by turning the inequality into an equation: $$ 3x + 4y = -2 $$
02

Find the slope and y-intercept

Now, we will put the equation in the slope-intercept form (\(y = mx + b\)) to easily find the slope and y-intercept. $$ 4y = -3x - 2 \\ y = -\frac{3}{4}x - \frac{1}{2} $$ So, the slope of the line is \(m = -\frac{3}{4}\) and the y-intercept is \(b = -\frac{1}{2}\).
03

Graph the boundary line

Now, we will graph the line that represents the boundary of the inequality by plotting the y-intercept and using the slope to find another point on the line. - The y-intercept is \(-\frac{1}{2}\). Start plotting this point on the y-axis. - Next, use the slope, \(-\frac{3}{4}\) to find another point on the line. Starting from the y-intercept, we will go down 3 units (negative sign) and to the right 4 units (rise over run). Plot the new point. - Draw the line that goes through these two points.
04

Determine the region that satisfies the inequality

We know that the line represents the boundary of the inequality, so now we need to determine which region of the graph satisfies the original inequality: $$ 3x + 4y \le -2 $$ To do this, choose a test point that does not lie on the line, for example, the origin (0,0). Substitute the coordinates of the test point into the inequality: $$ 3(0) + 4(0) \le -2 \\ 0 \le -2 $$ Since the inequality is false for the test point, the region that satisfies the inequality must be the opposite side of the line. In this case, as the test point lies below the line, the region that satisfies the inequality should be above the line.
05

Shade the solution region

Finally, we'll shade the region that satisfies the inequality. In this case, we shade the region above the line we plotted in Step 3, which represents the graphical solution of the inequality: $$ 3x + 4y \le -2 $$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Slope-Intercept Form
The slope-intercept form is a very handy tool in graphing linear equations or inequalities. It's written as \(y = mx + b\). Here, \(m\) represents the slope of the line—showing how steep the line is—and \(b\) indicates where the line intersects the y-axis, known as the y-intercept.

The slope, \(m\), tells us just how much the line moves up or down as we move along the x-axis. If it's positive, the line tilts upward, and if it's negative, the line tilts downward. The y-intercept, \(b\), is the starting point on the y-axis.

For our exercise, the equation \(y = -\frac{3}{4}x - \frac{1}{2}\) simplifies everything. Here, \(m = -\frac{3}{4}\) means the line goes down 3 units for every 4 units it moves right, and \(b = -\frac{1}{2}\) tells us it crosses the y-axis below the origin.
The Role of the Boundary Line
In the context of inequalities, the boundary line acts as a sort of fence for the graphical solution. It tells us the dividing line between regions that do and do not satisfy the inequality.

In our exercise, we derived the equation \(3x + 4y = -2\) from the inequality \(3x + 4y \leq -2\). By graphing this boundary line, we sketch out the line that will help us decide where the solutions lie.

To draw it, start at the y-intercept which is \(-\frac{1}{2}\), then use the slope of \(-\frac{3}{4}\) to find another point. Draw a solid line through these points, indicating that points on the line are part of the solution set (because of the 'equal to' part of \(\leq\)).
Shading the Solution Region
After sketching the boundary line, the next step is determining which side of the line satisfies the inequality. This process involves shading the region.

In this example, because we used a \(\leq\) sign, we identify the area that includes and goes beyond the boundary line. Using a test point like the origin helps us. If the point doesn't satisfy the inequality, shade the opposite side.

Since our test point (0,0) suggested that the inequality doesn't hold true (as \(0 \leq -2\) is false), it means the area directly across the line holds the solutions. Therefore, you would shade above the line. This shaded region shows all the sets of \((x, y)\) pairs that satisfy the original inequality.
Using an Inequality Test Point
Test points are a simple yet essential method for confirming which region satisfies an inequality on a graph. The most common choice is the origin point (0,0), unless it lies on the boundary line itself.

Plugging the coordinates into the inequality helps to figure out where the solutions lie. If the inequality holds true, the region containing the test point is shaded. If false, the region opposite to the test point is the solution region.

In our example, substituting (0,0) into \(3x + 4y \le -2\) results in an incorrect statement (0 is not less than or equal to -2). Hence, the correct region to shade is not the one containing the origin, but its opposite side relative to the boundary line.

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Most popular questions from this chapter

Solve each linear programming problem by the method of corners. $$ \begin{array}{rr} \text { Minimize } & C=3 x+4 y \\ \text { subject to } & x+y \geq 3 \\ & x+2 y \geq 4 \\ & x \geq 0, y \geq 0 \end{array} $$

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Solve each linear programming problem by the method of corners. $$ \begin{array}{l} \text { Minimize } \quad C=2 x+5 y \\ \text { subject to } \quad \begin{array}{r} 4 x+y \geq 40 \\ 2 x+y \geq 30 \\ x+3 y \geq 30 \\ x \geq 0, y \geq 0 \end{array} \end{array} $$

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