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Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. The solution set of a system of linear inequalities in two variables is bounded if it can be enclosed by a rectangle.

Short Answer

Expert verified
The given statement is true. The solution set of a system of linear inequalities in two variables is bounded if it can be enclosed by a rectangle because any solution set that can be enclosed by a rectangle will have at least two linear inequalities defining the horizontal boundaries and two defining the vertical boundaries, ensuring that the solution set is bounded within a finite region of the plane.

Step by step solution

01

Evaluating the given statement

Let's consider the given statement and try to interpret it in terms of linear inequalities: "The solution set of a system of linear inequalities in two variables is bounded if it can be enclosed by a rectangle." We can hypothesize that if the solution set can be enclosed by a rectangle, there are at least two linear inequalities defining the horizontal boundaries (top and bottom) and two defining the vertical boundaries (left and right).
02

Testing the statement with an example

Let's test the given statement with an example of a system of linear inequalities that can be enclosed by a rectangle: Inequality 1: \( y \leq x + 2 \) (top boundary) Inequality 2: \( y \geq x - 2 \) (bottom boundary) Inequality 3: \( y \leq -x + 4 \) (right boundary) Inequality 4: \( y \geq -x \) (left boundary) It is easy to see that the solution set satisfies all four inequalities and forms a parallelogram, which can be enclosed by a rectangle. In this case, the statement appears to be true.
03

Verifying the statement for a general case

However, we need to verify if the statement holds for any system of linear inequalities that can be enclosed by a rectangle. It can be proved that if there exists a rectangle enclosing the solution set for a system of linear inequalities, the solution set will always be bounded. Therefore, based on our analysis, the given statement is indeed true for any system of linear inequalities that can be enclosed by a rectangle. So, the statement is true.
04

Conclusion

In conclusion, the statement "The solution set of a system of linear inequalities in two variables is bounded if it can be enclosed by a rectangle" is true. This is because any solution set that can be enclosed by a rectangle will have at least two linear inequalities defining the horizontal boundaries and two defining the vertical boundaries, which ensure that the solution set is bounded within a finite region of the plane.

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