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Determine graphically the solution set for each system of inequalities and indicate whether the solution set is bounded or unbounded. $$ \begin{array}{l} 2 x-y=4 \\ 4 x-2 y<-2 \end{array} $$

Short Answer

Expert verified
The boundary lines of the given inequalities are \(y = 2x - 4\) and \(y = 2x + 1\). When trying to find the intersection point by equating the right-hand sides, we find that there is no intersection. Thus, the solution set for the given system of inequalities is empty and unbounded.

Step by step solution

01

Graph the boundary lines of the inequalities

First, rewrite both inequalities as equalities in order to graph the boundary lines: $$ \begin{array}{l} 2x - y = 4 \\ 4x - 2y = -2 \end{array} $$ Express the equalities in the slope-intercept form (y = mx + b) to plot the lines easily: For inequality 1: $$ - y = -2x + 4 \\ y = 2x - 4 $$ For inequality 2: $$ -2y = -4x - 2 \\ y = 2x + 1 $$ Graph these boundary lines on the coordinate plane.
02

Shade the regions determined by the inequalities

We will now determine which sides of these boundary lines we need to shade. For inequality 1 (2x - y ≥ 4), test a point not on the line. The easiest point is the origin (0, 0): $$ 2(0) - (0) ≥ 4 \\ 0 ≥ 4 $$ This is false, so the region satisfying this inequality will be on the opposite side of the line. For inequality 2 (4x - 2y < -2), test the origin (0,0) again: $$ 4(0) - 2(0) < -2 \\ 0 < -2 $$ This is also false, so the region satisfying this inequality will also be on the opposite side of the line. Shade the regions that satisfy both inequalities on the graph.
03

Determine the intersection point

Now we will find the intersection point of these boundary lines. We know that their expressions are: $$ \begin{array}{l} y = 2x - 4 \\ y = 2x + 1 \end{array} $$ Since the y-values are equal at the intersection, set the right-hand sides of the equations equal to each other and solve for x: $$ 2x - 4 = 2x + 1 $$ In this case, both sides have the same coefficient for x, so we have no intersection. This indicates that the solution set is empty and, by definition, unbounded. Therefore, the solution set for the given system of inequalities is unbounded, and there is no region on the graph satisfying both inequalities simultaneously.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

System of Inequalities
A system of inequalities consists of multiple inequalities that are considered simultaneously. In the context of the problem, we are dealing with two linear inequalities:
  • \(2x - y \geq 4\)
  • \(4x - 2y < -2\)
Each inequality describes a region in the coordinate plane, and the solution to the system of inequalities is the region that satisfies all the inequalities at once. To solve such systems, we graph each inequality and find the overlapping area that satisfies all the conditions.
When working with systems of inequalities, it is crucial to interpret not just where individual solutions might lie, but also how they interact together on the graph. Sometimes, these systems have overlapping regions, and other times, as in this case, the solutions do not overlap, meaning the system has no solution.
Bounded and Unbounded Regions
When graphing inequalities, the solution can be either bounded or unbounded. A bounded region is a closed and finite area, meaning the solution set is entirely contained within some boundary. For example, picture a square or a rectangle on a graph.
  • Bounded Regions: These are often encountered when all the inequalities in the system intersect to form a closed shape.
  • Unbounded Regions: These appear when the inequalities do not confine the solution to a finite space.
In our specific system, when we graph and analyze the inequalities, we find that there is no intersection point within the feasible regions. Therefore, the solution is unbounded because there is no contained solution region; in fact, the system has no solution at all because the shaded areas do not overlap on the graph.
Graphical Solution Method
The graphical solution method involves plotting each inequality on the coordinate plane as a boundary line. Begin by turning inequalities into equations by replacing inequality signs with equal signs to graph their corresponding lines.
The process can be broken down as follows:
  • Plot the Boundaries: Convert the inequalities to equalities, find their slope-intercept form (\(y = mx + b\)), and draw the straight lines on the graph.
  • Shading Regions: After plotting, select a test point that is not on the line (commonly the origin (0,0) unless it lies on the line) to determine which side of each line is part of the solution. Shade the appropriate side that satisfies the inequality.
  • Find Overlaps: The final solution is where all shaded regions intersect on the graph.
In the given exercise, due to the nature of the inequalities, the shading did not yield an overlapping region for the intersection of both inequalities, resulting in no solution for the system.

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Most popular questions from this chapter

Solve each linear programming problem by the method of corners. $$ \begin{array}{ll} \text { Maximize } & P=3 x+4 y \\ \text { subject to } & x+2 y \leq 50 \\ & 5 x+4 y \leq 145 \\ & 2 x+y \geq 25 \\ & y \geq 5, x \geq 0 \end{array} $$

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