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Find the inverse of the matrix, if it exists. Verify your answer. $$ \left[\begin{array}{rr} 3 & -3 \\ -2 & 2 \end{array}\right] $$

Short Answer

Expert verified
The inverse of the given matrix doesn't exist as its determinant is 0: \(|A| = (3)(2) - (-3)(-2) = 6 - 6 = 0\).

Step by step solution

01

Find the determinant.

The determinant of a 2x2 matrix \(A = \begin{bmatrix} a & b \\ c & d \end{bmatrix}\) is given by \(|A| = ad - bc\). So, for the given matrix \(A = \begin{bmatrix} 3 & -3 \\ -2 & 2 \end{bmatrix}\), the determinant is \[|A| = (3)(2) - (-3)(-2) = 6 - 6. \]
02

Check if the matrix has an inverse.

If the determinant is non-zero, the matrix has an inverse. In our case, since the determinant is |A| = 0, the matrix doesn't have an inverse. We can stop here because there is no inverse for the given matrix.
03

Verification:

Since we found that the given matrix doesn't have an inverse, there's no need for further verification.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Determinant of a Matrix
In matrix algebra, the determinant is a scalar value that is a key factor in determining a variety of properties about the matrix, including whether it has an inverse. The determinant of a 2x2 matrix can be found using a simple formula: if you have a matrix \( A = \begin{bmatrix} a & b \ c & d \end{bmatrix} \), its determinant is calculated as \( |A| = ad - bc \).

This value reflects certain geometrical properties of the linear transformation described by the matrix. For example, in a two-dimensional space, the determinant provides information on the area scaling factor for geometric figures under the transformation related to \( A \). If the determinant is zero, as in the given exercise, it signifies that the matrix does not have full rank, leading to the collapse of the n-dimensional volume to a lower dimension, making the matrix non-invertible. This has critical implications in solving systems of linear equations, understanding stability in systems, and more.
2x2 Matrix Inversion
The inversion of a matrix is akin to finding the reciprocal of a number—the matrix equivalent of division. For a 2x2 matrix \( A \), its inverse \( A^{-1} \) can typically be calculated using the formula: \( A^{-1} = \frac{1}{|A|} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \), where \( |A| \) is the determinant of \( A \). It's crucial to remember that this formula is only valid when \( |A| \) does not equal zero.

When a matrix is inverted, it essentially provides a way to 'undo' the transformation that the matrix represents. In practical terms, if you've applied a transformation to an object in space with \( A \) and you want to revert to the original state, multiplying with its inverse \( A^{-1} \) will accomplish this. However, if a matrix is singular, thus yielding a determinant value of zero, there is no inverse — the operation cannot be reversed.
Non-Invertible Matrix
A non-invertible matrix, also known as a singular or degenerate matrix, is one that cannot be inverted. As illustrated in our exercise, a matrix with a determinant of zero does not have an inverse. A non-invertible matrix cannot be used to find a unique solution to a system of linear equations—any such system is either inconsistent, yielding no solutions, or it has an infinite number of solutions.

Understanding whether a matrix is invertible or not is a fundamental part of linear algebra and has important consequences in various fields such as computer graphics, where invertible matrices are required for transformations, or in control theory, where non-invertible matrices might indicate a system is not controllable.
Matrix Algebra
The term matrix algebra refers to the branch of mathematics that specializes in the study of matrices and their properties. It includes a range of operations such as addition, subtraction, multiplication, and inversion of matrices. In this discipline, concepts like the determinant and invertibility play critical roles. Matrix algebra is not only about performing operations on numbers but also about understanding and manipulating the linear transformations that these matrices represent.

Deeply embedded in matrix algebra are the theories that connect systems of linear equations, vector spaces, and linear transformations. Mastery of matrix algebra is crucial for advanced studies in fields such as physics, engineering, computer science, economics, and more, as it forms the backbone for solving many complex problems in these disciplines. Hence, understanding the core concepts, like those we have discussed, is essential for using matrices effectively to model and solve real-world problems.

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Most popular questions from this chapter

Let \(A=\left[\begin{array}{ll}2 & -5 \\ 1 & -3\end{array}\right] \quad B=\left[\begin{array}{ll}4 & 3 \\ 1 & 1\end{array}\right] \quad C=\left[\begin{array}{rr}2 & 3 \\ -2 & 1\end{array}\right]\) a. Find \(A B C, A^{-1}, B^{-1}\), and \(C^{-1}\). b. Show that \((A B C)^{-1}=C^{-1} B^{-1} A^{-1}\).

Solve the system of linear equations using the Gauss-Jordan elimination method. $$ \begin{array}{l} 2 x-3 y=-8 \\ 4 x+y=-2 \end{array} $$

(a) write each system of equations as a matrix equation and (b) solve the system of equations by using the inverse of the coefficient matrix. $$ \begin{array}{l} \begin{array}{r} x_{1}+x_{2}+x_{3}+x_{4}=b_{1} \\ x_{1}-x_{2}-x_{3}+x_{4}=b_{2} \\ x_{2}+2 x_{3}+2 x_{4}=b_{3} \\ x_{1}+2 x_{2}+x_{3}-2 x_{4}=b_{4} \end{array}\\\ \text { where (i) } b_{1}=1, b_{2}=-1, b_{3}=4, b_{4}=0\\\ \text { and } \quad \text { (ii) } b_{1}=2, b_{2}=8, b_{3}=4, b_{4}=-1 \end{array} $$

Let $$ A=\left[\begin{array}{rr} 6 & -4 \\ -4 & 3 \end{array}\right] \text { and } B=\left[\begin{array}{ll} 3 & -5 \\ 4 & -7 \end{array}\right] $$ a. Find \(A B, A^{-1}\), and \(B^{-1}\). b. Show that \((A B)^{-1}=B^{-1} A^{-1}\).

The problems in exercise correspond to those in exercises 15-27, Section 2.1. Use the results of your previous work to help you solve these problems. Cantwell Associates, a real estate developer, is planning to build a new apartment complex consisting of one-bedroom units and two- and three-bedroom townhouses. A total of 192 units is planned, and the number of family units (two- and three-bedroom townhouses) will equal the number of one-bedroom units. If the number of one-bedroom units will be 3 times the number of threebedroom units, find how many units of each type will be in the complex.

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