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Given that the augmented matrix in row-reduced form is equivalent to the augmented matrix of a system of linear equations, (a) determine whether the system has a solution and (b) find the solution or solutions to the system, if they exist. $$ \left[\begin{array}{ll|l} 1 & 0 & 2 \\ 0 & 1 & 4 \\ 0 & 0 & 0 \end{array}\right] $$

Short Answer

Expert verified
The given row-reduced augmented matrix is: $$ \left[\begin{array}{ll|l} 1 & 0 & 2 \\ 0 & 1 & 4 \\ 0 & 0 & 0 \end{array}\right] $$ (a) As there are no rows in the form \( [0 \ 0 | a] \) with \( a \ne 0 \), there is at least one solution to the system. (b) The matrix corresponds to the system of linear equations: $$ \begin{cases} x_1 = 2 \\ x_2 = 4 \\ \end{cases} $$ Therefore, the system has a unique solution \( (2, 4) \).

Step by step solution

01

Check for inconsistencies

Look at the row-reduced augmented matrix and see if there are any inconsistencies that could indicate there is no solution. $$ \left[\begin{array}{ll|l} 1 & 0 & 2 \\ 0 & 1 & 4 \\ 0 & 0 & 0 \end{array}\right] $$ There are no rows in the form \( [0 \ 0 | a] \) with \( a \ne 0 \), which would indicate that the system has no solution. So there is at least one solution.
02

Identify the solutions

Since there is a solution and the matrix is in row-reduced form, it is straightforward to identify its solutions. The matrix corresponds to the system of linear equations: $$ \begin{cases} x_1 = 2 \\ x_2 = 4 \\ \end{cases} $$ Thus, the system has a unique solution \( (2, 4) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Row-Reduced Form
When dealing with linear algebra, the row-reduced form of a matrix is an essential concept. It involves transforming a matrix into a simpler one using a series of elementary row operations. Ultimately, the goal is to achieve a state known as the Reduced Row Echelon Form (RREF). This form makes it easy to interpret the solutions of a system of linear equations related to the matrix.

The process involves:
  • Ensuring that each leading entry in a row is 1.
  • Having every leading 1 be the only non-zero number in its column.
  • Having each leading 1 be to the right of the leading 1 in the row above.
  • Ensuring that rows with all zero elements are at the bottom of the matrix.
By achieving row-reduced form, we simplify the system of equations, making it less complex to find solutions.
Augmented Matrix
In linear algebra, an augmented matrix is used to represent a system of linear equations compactly. An augmented matrix combines the coefficients of the variables and the constants from the equations into one matrix, separated by a symbol such as a vertical bar.

For example, the matrix:\[\left[\begin{array}{ll|l}1 & 0 & 2 \0 & 1 & 4 \0 & 0 & 0\end{array}\right]\]represents the system of equations:
  • \( x_1 = 2 \)
  • \( x_2 = 4 \)
The section to the left contains coefficients of variables, and the right side holds the constants from the equations. This format efficiently encapsulates the entire system, allowing for streamlined operations such as row reduction or solving.
System of Linear Equations
A system of linear equations is a collection of one or more linear equations involving the same set of variables. The main objective is to find values for these variables that satisfy all given equations simultaneously.

Consider a simple system represented by the equations derived from our augmented matrix:
  • \( x_1 = 2 \)
  • \( x_2 = 4 \)
In this example, the solution \((2, 4)\) easily satisfies each equation. Systems can be solved using various methods, including substitution, elimination, or matrix approaches, such as the use of row reduction.

The properties and structure of these systems allow us to derive insights into the possible number and type of solutions, whether they are unique, infinite, or nonexistent.
Unique Solution
A system of linear equations exhibits a unique solution when there is exactly one set of variable values that satisfies all the equations. This situation occurs when each variable is controlled by a pivot variable in its row-reduced form.

The given example:\[\left[\begin{array}{ll|l}1 & 0 & 2 \0 & 1 & 4 \0 & 0 & 0\end{array}\right]\]shows each row has a leading 1 with clear solutions \( x_1 = 2 \) and \( x_2 = 4 \). Hence, these equations affirm a unique solution from the matrix.

A solution can be termed unique if the system results in a straightforward, definitive answer without dependencies or contradictions across the equations.

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