/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Pivot the system about the circl... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Pivot the system about the circled element. $$ \left[\begin{array}{rr|r} (-1) & 2 & 3 \\ 6 & 4 & 2 \end{array}\right] $$

Short Answer

Expert verified
The short answer based on the step-by-step solution is: After pivoting the system about the circled element (-1), we obtain the following matrix: $$ \left[\begin{array}{cc|c} 1 & -2 & -3 \\ 0 & 16 & 20 \end{array}\right] $$

Step by step solution

01

Make the pivot element, (-1), equal to 1

We can do this by dividing the entire first row by (-1). This will result in the following system: $$ \left[\begin{array}{cc|c} 1 & -2 & -3 \\ 6 & 4 & 2 \end{array}\right] $$
02

Make the other element in the pivot column, 6, equal to 0

To accomplish this, we will replace the second row with the result of (second row - 6 * first row). This will give us: $$ \left[\begin{array}{cc|c} 1 & -2 & -3 \\ 0 & 16 & 20 \end{array}\right] $$ Now, the system has been pivoted about the circled element resulting in the following: $$ \left[\begin{array}{cc|c} 1 & -2 & -3 \\ 0 & 16 & 20 \end{array}\right] $$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

System of Linear Equations
A system of linear equations is a collection of two or more linear equations involving the same set of variables. Each equation represents a line, and the solution to the system is the point or points where these lines intersect. Solving such a system means finding the values of the variables that satisfy all equations simultaneously.

For instance, consider two equations in two variables. The system can be solved graphically by plotting each equation on a coordinate plane and identifying the point of intersection. However, this method isn't efficient for complex or higher-dimensional systems. Thus, algebraic methods like substitution, elimination, and matrix approaches, such as Gaussian elimination, are preferred for their ability to handle multiple equations reliably.
Matrix Pivoting
Matrix pivoting is a technique used in Gaussian elimination to avoid numerical instability and to increase the accuracy of the solution. Pivoting involves swapping rows or columns in a matrix to move a non-zero element to the pivot position, which is generally on the diagonal.

It ensures that the largest, or a sufficiently large, element is used as the pivot to avoid division by small numbers, which can result in significant rounding errors. In the provided exercise, the element \( -1 \) was chosen as the pivot element, and the goal was to manipulate the other elements in the pivot's column to ease the process of solving the system.
Row Operations
Row operations are the tools used in matrix methods to solve systems of linear equations. They consist of three types of maneuvers: swapping two rows, multiplying a row by a non-zero constant, and adding or subtracting a multiple of one row to another row.

These operations are considered legal moves because they do not change the solution set of the system. Their purpose is to systematically transform the matrix into a simpler form, often aiming for a row-echelon or reduced row-echelon form, from which solutions are easily read off or determined through back-substitution.
Elementary Row Operations
Elementary row operations are the building blocks used in row operations. They are fundamental actions we can perform on the rows of a matrix, which correspond to algebraic operations on the equations of a system. The three types include:
  • Type 1: Swap the positions of two rows.
  • Type 2: Multiply a row by a non-zero scalar.
  • Type 3: Add or subtract the multiple of one row to another row.

These operations preserve the equivalence of the original system. In the context of the exercise, an elementary row operation of Type 2 was used to make the pivot element \( -1 \) into \( 1 \) by dividing the first row by \( -1 \) and a Type 3 operation was then used to eliminate the \( 6 \) in the second row to achieve a 0 below the pivot, helping to simplify the system into an upper triangular form.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A private investment club has a certain amount of money earmarked for investment in stocks. To arrive at an acceptable overall level of risk, the stocks that management is considering have been classified into three categories: high risk, medium risk, and low risk. Management estimates that high-risk stocks will have a rate of return of \(15 \% /\) year; medium-risk stocks, \(10 \% /\) year; and low-risk stocks, \(6 \%\) /year. The members have decided that the investment in low-risk stocks should be equal to the sum of the investments in the stocks of the other two categories. Determine how much the club should invest in each type of stock in each of the following scenarios. (In all cases, assume that the entire sum available for investment is invested.) a. The club has \(\$ 200,000\) to invest, and the investment goal is to have a return of \(\$ 20,000 /\) year on the total investment. b. The club has \(\$ 220,000\) to invest, and the investment goal is to have a return of \(\$ 22,000 /\) year on the total investment. c. The club has \(\$ 240,000\) to invest, and the investment goal is to have a return of \(\$ 22,000 /\) year on the total investment.

Let $$ A=\left[\begin{array}{rr} 1 & 3 \\ -2 & -1 \end{array}\right] \text { and } B=\left[\begin{array}{ll} 3 & -4 \\ 2 & -2 \end{array}\right] $$ a. Find \(A^{T}\) and show that \(\left(A^{T}\right)^{T}=A\). b. Show that \((A+B)^{T}=A^{T}+B^{T}\). c. Show that \((A B)^{T}=B^{T} A^{T}\).

K & R Builders build three models of houses, \(M_{1}, M_{2}\), and \(M_{3}\), in three subdivisions I, II, and III located in three different areas of a city. The prices of the houses (in thousands of dollars) are given in matrix \(A\) : K\& R Builders has decided to raise the price of each house by \(3 \%\) next year. Write a matrix \(B\) giving the new prices of the houses.

For the opening night at the Opera House, a total of 1000 tickets were sold. Front orchestra seats cost $$\$ 80$$ apiece, rear orchestra seats cost $$\$ 60$$ apiece, and front balcony seats cost $$\$ 50$$ apiece. The combined number of tickets sold for the front orchestra and rear orchestra exceeded twice the number of front balcony tickets sold by 400. The total receipts for the performance were $$\$ 62,800$$. Determine how many tickets of each type were sold.

A dietitian plans a meal around three foods. The number of units of vitamin A, vitamin \(\mathrm{C}\), and calcium in each ounce of these foods is represented by the matrix \(M\), where $$ \begin{array}{l} \text { Food I } & \text { Food II } & \text { Food III } \\ \text { Vitamin A } & {\left[\begin{array}{rrr} 400 & 1200 & 800 \\ M= & \text { Vitamin C } \\ \text { Calcium } \end{array}\right.} & \begin{array}{rr} 110 \\ 90 \end{array} & \begin{array}{r} 570 \\ 30 \end{array} & \left.\begin{array}{r} 340 \\ 60 \end{array}\right] \end{array} $$ The matrices \(A\) and \(B\) represent the amount of each food (in ounces) consumed by a girl at two different meals, where \(\begin{array}{lll}\text { Food I } & \text { Food II } & \text { Food III }\end{array}\) $$ A=\left[\begin{array}{lll} 7 & 1 & 6 \end{array}\right] $$ \(\begin{array}{lll}\text { Food I } & \text { Food II } & \text { Food III }\end{array}\) $$ B=\left[9 \quad \left[\begin{array}{ll} 9 & 3 \end{array}\right.\right. $$ $$ 2] $$ Calculate the following matrices and explain the meaning of the entries in each matrix. a. \(M A^{T}\) b. \(M B^{T}\) c. \(M(A+B)^{T}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.