/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Perform the indicated operations... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Perform the indicated operations. $$ \begin{array}{r} 0.5\left[\begin{array}{rrr} 1 & 3 & 5 \\ 5 & 2 & -1 \\ -2 & 0 & 1 \end{array}\right]-0.2\left[\begin{array}{rrr} 2 & 3 & 4 \\ -1 & 1 & -4 \\ 3 & 5 & -5 \end{array}\right] \\ +0.6\left[\begin{array}{rrr} 3 & 4 & -1 \\ 4 & 5 & 1 \\ 1 & 0 & 0 \end{array}\right] \end{array} $$

Short Answer

Expert verified
The short answer is: \(A = \left[\begin{array}{rrr} 1.9 & 3.3 & 1.7 \\ 5.1 & 3.8 & 0.9 \\ -1 & -1 & 1.5 \end{array}\right]\)

Step by step solution

01

Scalar Multiplication

Multiply each matrix by its corresponding scalar. For the first matrix, multiply by 0.5: $$ 0.5\left[\begin{array}{rrr} 1 & 3 & 5 \\ 5 & 2 & -1 \\ -2 & 0 & 1 \end{array}\right] = \left[\begin{array}{rrr} 0.5 & 1.5 & 2.5 \\ 2.5 & 1 & -0.5 \\ -1 & 0 & 0.5 \end{array}\right] $$For the second matrix, multiply by -0.2: $$ -0.2\left[\begin{array}{rrr} 2 & 3 & 4 \\ -1 & 1 & -4 \\ 3 & 5 & -5 \end{array}\right] = \left[\begin{array}{rrr} -0.4 & -0.6 & -0.8 \\ 0.2 & -0.2 & 0.8 \\ -0.6 & -1 & 1 \end{array}\right] $$For the third matrix, multiply by 0.6: $$ 0.6\left[\begin{array}{rrr} 3 & 4 & -1 \\ 4 & 5 & 1 \\ 1 & 0 & 0 \end{array}\right] = \left[\begin{array}{rrr} 1.8 & 2.4 & -0.6 \\ 2.4 & 3 & 0.6 \\ 0.6 & 0 & 0 \end{array}\right] $$
02

Matrix Addition

Add the resulting matrices from the scalar multiplication together: $$ \left[\begin{array}{rrr} 0.5 & 1.5 & 2.5 \\ 2.5 & 1 & -0.5 \\ -1 & 0 & 0.5 \end{array}\right] + \left[\begin{array}{rrr} -0.4 & -0.6 & -0.8 \\ 0.2 & -0.2 & 0.8 \\ -0.6 & -1 & 1 \end{array}\right] + \left[\begin{array}{rrr} 1.8 & 2.4 & -0.6 \\ 2.4 & 3 & 0.6 \\ 0.6 & 0 & 0 \end{array}\right] = \left[\begin{array}{rrr} 0.5-0.4+1.8 & 1.5-0.6+2.4 & 2.5-0.8-0.6 \\ 2.5+0.2+2.4 & 1-0.2+3 & -0.5+0.8+0.6 \\ -1-0.6+0.6 & 0-1+0 & 0.5+1+0 \end{array}\right] $$ Perform the addition in each component: $$ = \left[\begin{array}{rrr} 1.9 & 3.3 & 1.7 \\ 5.1 & 3.8 & 0.9 \\ -1 & -1 & 1.5 \end{array}\right] $$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Scalar Multiplication
When we talk about scalar multiplication in the context of matrices, we are diving into a fundamental concept in linear algebra. At its core, scalar multiplication involves multiplying every entry in a matrix by a fixed number, called a scalar.

This might seem straightforward, but it is a crucial operation because it scales the entire matrix by the scalar value.

For example, consider multiplying a matrix \( A \) by a scalar \( c \). Each element of the matrix is multiplied by \( c \) to produce a new matrix \( B \):
  • Matrix \( A = \left[\begin{array}{cc} a & b \ c & d \end{array}\right] \)
  • Scalar \( c \)
The result is
\( B = c \left[\begin{array}{cc} a & b \ c & d \end{array}\right] = \left[\begin{array}{cc} ca & cb \ cc & cd \end{array}\right] \).

In our exercise, each matrix was individually multiplied by their respective scalars (0.5, -0.2, and 0.6) to obtain new, resized matrices that could later be added together. This ensures that each change in size is proportionate across all elements of the matrix.
Matrix Addition
Matrix addition is another essential operation in linear algebra that allows us to combine matrices. The process of matrix addition involves taking two matrices of the same dimensions and adding their corresponding elements.

When we add matrices, each element from the first matrix is directly added to the corresponding element in the second matrix:
  • Matrix \( A = \left[\begin{array}{cc} a & b \ c & d \end{array}\right] \)
  • Matrix \( B = \left[\begin{array}{cc} e & f \ g & h \end{array}\right] \)
Then, the sum is found:
\( A + B = \left[\begin{array}{cc} a+e & b+f \ c+g & d+h \end{array}\right] \).

In our specific problem, we added the resultant matrices from the scalar multiplication step. This gave us a final matrix that integrates all transformations each matrix underwent. It is important to note that in matrix addition, the matrices being added must be of the same dimension. Otherwise, the operation is not defined.
Linear Algebra
Linear algebra encompasses the study of vectors, vector spaces, and their transformations. Matrix operations like scalar multiplication and matrix addition are fundamental building blocks in this field.

Linear algebra is not just about computations, but also about understanding the underlying structures such as solving systems of linear equations, performing transformations, and analyzing geometrical spaces through matrix manipulations.

Applications of linear algebra permeate through various fields, such as:
  • Computer graphics, where transformations of images are computed using matrices.
  • Machine learning, which heavily relies on matrix operations to handle large datasets efficiently.
  • Engineering, where systems of equations are modeled using matrices.
Learning the basics of matrix operations allows us to harness these tools effectively. By mastering operations like scalar multiplication and matrix addition, students are better equipped to delve into more complex linear algebra challenges and apply them to practical scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Fill in the missing entries by performing the indicated row operations to obtain the rowreduced matrices. $$ \begin{array}{l} \text { }\left[\begin{array}{rrr|r} 0 & 1 & 3 & -4 \\ 1 & 2 & 1 & 7 \\ 1 & -2 & 0 & 1 \end{array}\right] \stackrel{R_{1} \leftrightarrow R_{2}}{\longrightarrow}\left[\begin{array}{rrr|r} \cdot & \cdot & \cdot & \cdot \\ \cdot & \cdot & \cdot & \cdot \\ 1 & -2 & 0 & 1 \end{array}\right]\\\ \stackrel{R_{3}-R_{1}}{\longrightarrow}\left[\begin{array}{ccc|r} 1 & 2 & 1 & 7 \\ 0 & 1 & 3 & -4 \\ \cdot & \cdot & \cdot & \cdot \end{array}\right] \frac{R_{1}+\frac{1}{2} R_{3}}{R_{3}+4 R_{2}}\left[\begin{array}{ccc|c} \cdot & \cdot & \cdot & \cdot \\ 0 & 1 & 3 & -4 \\ \cdot & \cdot & \cdot & \cdot \end{array}\right]\\\ \stackrel{\frac{1}{11} R_{3}}{\longrightarrow}\left[\begin{array}{ccc|c} 1 & 0 & \frac{1}{2} & 4 \\ 0 & 1 & 3 & -4 \\ . & \cdot & . & . \end{array}\right] \frac{R_{1}-\frac{1}{2} R_{3}}{R_{2}-3 R_{3}}\left[\begin{array}{ccc|r} 1 & 0 & 0 & 5 \\ 0 & 1 & 0 & 2 \\ 0 & 0 & 1 & -2 \end{array}\right] \end{array} $$

Jackson Farms has allotted a certain amount of land for cultivating soybeans, corn, and wheat. Cultivating 1 acre of soybeans requires 2 labor-hours, and cultivating 1 acre of corn or wheat requires 6 labor-hours. The cost of seeds for 1 acre of soybeans is \(\$ 12\), for 1 acre of corn is \(\$ 20\), and for 1 acre of wheat is \(\$ 8\). If all resources are to be used, how many acres of each crop should be cultivated if the following hold? a. 1000 acres of land are allotted, 4400 labor-hours are available, and \(\$ 13,200\) is available for seeds. b. 1200 acres of land are allotted, 5200 labor-hours are available, and \(\$ 16,400\) is available for seeds.

Let $$ A=\left[\begin{array}{rr} 6 & -4 \\ -4 & 3 \end{array}\right] \text { and } B=\left[\begin{array}{ll} 3 & -5 \\ 4 & -7 \end{array}\right] $$ a. Find \(A B, A^{-1}\), and \(B^{-1}\). b. Show that \((A B)^{-1}=B^{-1} A^{-1}\).

The amount of money raised by charity I, charity II, and charity III (in millions of dollars) in each of the years 2006,2007, and 2008 is represented by the matrix \(A\) : $$ A=\begin{array}{cccc} & \mathrm{I} & \mathrm{II} & \mathrm{III} \\ 2006 & {\left[\begin{array}{ccc} 18.2 & 28.2 & 40.5 \\ 19.6 & 28.6 & 42.6 \\ 20.8 & 30.4 & 46.4 \end{array}\right]} \\ 2007 & 2008 \end{array} $$ On average, charity I puts \(78 \%\) toward program cost, charity II puts \(88 \%\) toward program cost, and charity III puts \(80 \%\) toward program cost. Write a \(3 \times 1\) matrix \(B\) reflecting the percentage put toward program cost by the charities. Then use matrix multiplication to find the total amount of money put toward program cost in each of the 3 yr by the charities under consideration.

Write the given system of linear equations in matrix form. $$ \begin{array}{rr} x-2 y+3 z= & -1 \\ 3 x+4 y-2 z= & 1 \\ 2 x-3 y+7 z= & 6 \end{array} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.