/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Find an equation of the circle t... [FREE SOLUTION] | 91Ó°ÊÓ

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Find an equation of the circle that satisfies the given conditions. Center \((2,-3)\) and passes through \((5,2)\)

Short Answer

Expert verified
The equation of the circle with center \((2, -3)\) and passing through the point \((5, 2)\) is \((x - 2)^2 + (y + 3)^2 = 34\).

Step by step solution

01

Find the radius

To find the radius, we will use the distance formula to find the distance between the center of the circle and the point \((5, 2)\): \[r = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]Substitute the coordinates of the center and the point into the distance formula.
02

Substitute the coordinates

Substitute the coordinates of the center \((2, -3)\) and the point \((5, 2)\): \[r = \sqrt{((5 - 2)^2 + (2 - (-3))^2)}\]
03

Solve for the radius

Simplify the expression within the square root: \[r = \sqrt{(3^2 + (5)^2)} = \sqrt{(9 + 25)} = \sqrt{34}\]So, the radius is \(\sqrt{34}\).
04

Write the equation of the circle

Now that we have the center \((2, -3)\) and the radius \(\sqrt{34}\), we can write the equation of the circle using the formula \((x - h)^2 + (y - k)^2 = r^2\). Substitute the coordinates of the center and the radius into the formula: \[(x - 2)^2 + (y + 3)^2 = (\sqrt{34})^2\]
05

Simplify the equation

Simplify the equation by squaring the radius: \[(x - 2)^2 + (y + 3)^2 = 34\] So, the equation of the circle with center \((2, -3)\) and passing through the point \((5, 2)\) is \((x - 2)^2 + (y + 3)^2 = 34\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distance Formula
Understanding the distance formula is crucial when it comes to finding the size of a circle's radius or the distance between two points in coordinate geometry. The distance between any two points \( (x_1, y_1) \) and \( (x_2, y_2) \) in a Cartesian plane can be found using the distance formula:

c\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]ce formula.

This formula is derived from the Pythagorean theorem, which describes the relation between the sides of a right triangle. In terms of geometry, if you imagine a horizontal line from \( x_1 \) to \( x_2 \) and a vertical line from \( y_1 \) to \( y_2 \) forming a right triangle, the distance \( d \) between these two points is the hypotenuse of that triangle. By using this formula, we can accurately calculate the straight-line distance between the center of the circle and any point on its periphery, which is essential in determining the circle's radius.
Radius Calculation
A circle's radius is the distance from the center to any point on the circle's edge, and calculating it is a fundamental aspect of working with circles in geometry. Once we have the center and any point on the circle, the radius can be calculated using the distance formula. The exercise provided required finding the radius using the center \( (2, -3) \) and a given point on the circle \( (5, 2) \).Using the previously mentioned distance formula, one can deduce the radius through substitution and simplification:
\[ r = \sqrt{(5 - 2)^2 + (2 - (-3))^2)} \]which simplifies to \( r = \sqrt{34} \).That determination of the radius is a common stumbling block for students, but with practice and careful substitution into the distance formula, becoming comfortable with radius calculation in these contexts can be achieved.
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, involves the study of geometry using the coordinate plane. The basic idea is to use numbers (coordinates) to represent geometric shapes and analyze their properties. When writing the equation of a circle, as in our exercise example, we use the standard form which is:\[ (x - h)^2 + (y - k)^2 = r^2 \]In this equation, \( (h, k) \) represents the coordinates of the circle's center, and \( r \) is the radius. By plugging in the center's coordinates and the radius value into this formula, you get the specific equation for the circle in question.

In our example with the circle centered at \( (2, -3) \) and radius \( \sqrt{34} \) the equation becomes:\[ (x - 2)^2 + (y + 3)^2 = 34 \]This final equation provides a way to check if any given point lies on the circle, just by inserting its coordinates into the equation. Coordinate geometry is a vital tool in various applications, including computer graphics, navigation systems, and designing geometric objects.

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Most popular questions from this chapter

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