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Compute the (sample) variance and standard deviation of the data samples given in Exercises \(1-8 .\) You calculated the means in the last exercise set. Round all answers to two decimal nlaces. $$ -\frac{3}{2}, \frac{3}{8},-1, \frac{5}{2} $$

Short Answer

Expert verified
The sample variance of the given data samples is 3.52, and the sample standard deviation is 1.88.

Step by step solution

01

Compute or Recall the Mean

The given data samples are: \[ -\frac{3}{2}, \frac{3}{8},-1, \frac{5}{2} \] Compute the mean (also called the sample mean) as the sum of the data samples divided by the number of samples: \[ \bar{x} = \frac{(-\frac{3}{2}) + (\frac{3}{8}) + (-1) + (\frac{5}{2})}{4} \] Calculate the mean value: \[ \bar{x} = \frac{1}{8} \]
02

Compute the Variance

The (sample) variance is given by the formula: \[ s^2 = \frac{\sum_{i=1}^n (x_i - \bar{x})^2}{n-1} \] Compute the square of the difference between each data sample and the mean: \[ (-\frac{3}{2} - \frac{1}{8})^2 = \frac{256}{64} \\ (\frac{3}{8} - \frac{1}{8})^2 = \frac{1}{16} \\ (-1 - \frac{1}{8})^2 = \frac{81}{64} \\ (\frac{5}{2} - \frac{1}{8})^2 = \frac{361}{64} \] Now substitute these values into the variance formula: \[ s^2 = \frac{\frac{256}{64} + \frac{1}{16} + \frac{81}{64} + \frac{361}{64}}{4-1} \] Compute the variance value: \[ s^2 = 3.52 \]
03

Compute the Standard Deviation

The (sample) standard deviation is the square root of the variance: \[ s = \sqrt{s^2} = \sqrt{3.52} \] Compute the standard deviation value and round to two decimal places: \[ s = 1.88 \]
04

Final Answer

The sample variance of the given data samples is 3.52, and the sample standard deviation is 1.88.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
Understanding the concept of mean is vital in statistics as it serves as a basis for calculating other statistical measures like variance and standard deviation. The **mean** of a dataset is the average value of all the data points. To calculate the mean, sum all the values and divide the total by the number of data points.

For example, in the dataset:
  • \(-\frac{3}{2}, \frac{3}{8}, -1, \frac{5}{2}\)
the mean is calculated by first summing up all numbers as shown: \[\text{Sum} = \left(-\frac{3}{2}\right) + \left(\frac{3}{8}\right) + (-1) + \left(\frac{5}{2}\right)\]Then, divide this sum by the number of data points (which is 4 in this case), leading to the mean: \[\bar{x} = \frac{1}{8}\]This simple arithmetic provides a central value, allowing us to understand where most of our data points lie in terms of size or magnitude. This foundation is key when progressing towards more complex statistical calculations.
Variance Formula
The **variance** measures how spread out data points in a dataset are around the mean.
It tells us whether the data points tend to cluster around the mean or are more dispersed. The formula for sample variance is:\[s^2 = \frac{\sum_{i=1}^n (x_i - \bar{x})^2}{n-1}\]To find the variance, follow these steps:
  • Subtract the mean from each data point, which measures how far each value is from the mean.
  • Square each of these differences. Squaring removes negative signs and gives more weight to values further from the mean.
  • Sum all squared differences.
  • Divide by \(n-1\), where \(n\) is the number of data points. This division accounts for the sample nature of the data, ensuring an unbiased estimate of the population variance.
For example, using our data points, the variance \(s^2\) came out to be 3.52.
This gives us a sense of how much variation or "spread" there is from the mean (\(\bar{x} = \frac{1}{8}\)).
Standard Deviation Formula
While variance is a useful measure, its units are squared, which can be difficult to interpret directly. That's where **standard deviation** comes in. It is the square root of the variance and carries the same units as the original data, making it more interpretable.

The formula for standard deviation is:\[s = \sqrt{s^2}\]For the data points given, the calculated standard deviation is 1.88.
This suggests that the typical distance from the mean for points in this dataset is 1.88 units.
Standard deviation thus conveys both the concept of "average spread" of the dataset and provides a way to appreciate the variability relative to other datasets on similar scales.
Data Analysis
**Analyzing data** is a fundamental aspect of statistics that helps us make informed decisions by interpreting numerical information. The calculated mean, variance, and standard deviation of any dataset can provide significant insights.
  • **Mean** offers a central value for the data, around which other data points can be described.
  • **Variance** tells us how spread out or close the data is to the mean. High variance signifies more spread while low variance indicates that data points are clustered close to the mean.
  • **Standard deviation** further simplifies understanding of spread by expressing it in the original data units, facilitating direct interpretation of data variability.
These statistical measures enable deeper exploration of data.
For instance, they can help assess the consistency of production processes, the risk of investments, or the performance variability in sports teams.
Understanding these simple but powerful tools empowers one to appreciate the hidden insights within numerical data and make evidence-based predictions or decisions.

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