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Popularity Ratings In your bid to be elected class representative, you have your election committee survey five randomly chosen students in your class and ask them to rank you on a scale of \(0-10\). Your rankings are \(3,2,0,9,1\). a. Find the sample mean and standard deviation. (Round your answers to two decimal places.) HINT [See Example 1 and Quick Examples on page 581.] b. Assuming the sample mean and standard deviation are indicative of the class as a whole, in what range does the empirical rule predict that approximately \(68 \%\) of the class

Short Answer

Expert verified
The sample mean of the popularity ratings is 3, and the sample standard deviation is approximately 3.57. According to the empirical rule, about \(68\%\) of the class should have a score within the range of \(0\) to \(6.57\).

Step by step solution

01

Calculate the sample mean

To calculate the sample mean, we need to add up all the ratings and divide by the number of ratings. In our case, that would be: Mean = \(\frac{3 + 2 + 0 + 9 + 1}{5}\)
02

Compute the sample mean

Mean = \(\frac{15}{5}\) = \(3\) The sample mean is 3.
03

Calculate the deviations from the mean

Now, we need to calculate the deviation of each rating from the mean. That is, we subtract the mean (3) from each rating: Deviations = \((-1, -1, -3, +6, -2)\)
04

Calculate the sum of squared deviations

Next, we square each deviation and sum them up: Sum of squared deviations = \((-1)^2 + (-1)^2 + (-3)^2 + (+6)^2 + (-2)^2\) = \(1 + 1 + 9 + 36 + 4\) = \(51\)
05

Compute the sample variance

Now we need to calculate the sample variance. To do this, divide the sum of squared deviations by one less than the number of ratings (5 - 1 = 4): Variance = \(\frac{51}{4}\) = \(12.75\)
06

Calculate the sample standard deviation

To find the sample standard deviation, we simply take the square root of the variance: Standard deviation = \(\sqrt{12.75}\) ≈ \(3.57\) The sample standard deviation is approximately 3.57.
07

Apply the empirical rule to find the range

According to the empirical rule, approximately \(68 \%\) of the class should have a score within one standard deviation from the mean: Range = Mean ± 1(Standard deviation) = \(3 \pm 3.57\) So, approximately \(68 \%\) of the class should have a score between \(-0.57\) and \(6.57\). Note that the lower limit (-0.57) is below the minimum rating possible (0). Thus, the range will be limited to the rating scale between \(0\) and \(6.57\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean Calculation
Understanding how to calculate the sample mean is fundamental in statistics. The sample mean, often referred to as the average, represents the central point of a data set. To find it, you simply add together all the values in your sample and then divide by the number of values.

For the class representative popularity ratings, we have five values which are: 3, 2, 0, 9, and 1. By adding these up, we get a total of 15. Since there are five values, we divide 15 by 5 to get a sample mean of 3. This suggests that, on average, the popularity rating is 3 on a scale from 0 to 10.

A correct calculation of the sample mean provides a solid foundation for further statistical analysis and gives us an initial idea of where our data is centered.
Sample Standard Deviation Calculation
The sample standard deviation is a measure of the amount of variation or dispersion in a set of values. A low standard deviation indicates that the values tend to be close to the mean, whereas a high standard deviation indicates that the values are spread out over a wider range.

The calculation involves several steps, beginning with finding the mean, as previously described. Next, we calculate the deviation of each value from the mean, which represents how far each value is from the mean. We then square these deviations to ensure they are positive, and sum them up. This sum is then divided by the number of values minus one to account for sample variance, which in our case gives us 12.75.

The final step is to take the square root of this result to return the units to their original, giving us a standard deviation of approximately 3.57. This tells us about the variability of our popularity ratings.
Variance Computation
Variance is another measure of dispersion in your data, similar to standard deviation but with a slight difference, as it is the average squared deviation from the mean. To compute the variance, follow the previous step and calculate each data point's deviation from the mean, square these deviations to get rid of any negative signs, and then average these squared numbers.

In our example, the sum of the squared deviations is 51. We divide this sum by the number of data points minus one (N-1), which is called the 'degrees of freedom.' This adjustment helps to correct the bias in the estimation of the population variance from a sample. The variance of our popularity ratings is 12.75, which offers significant insights when comparing datasets or understanding the data's spread.
Data Deviation Analysis
After you've computed the standard deviation and variance, you can analyze the deviations of data points from the mean to understand the distribution. This is where the Empirical Rule comes into play, which states that for a normal distribution, nearly 68% of the data will fall within plus or minus one standard deviation from the mean.

In our exercise, with a mean of 3 and a standard deviation of approximately 3.57, we would normally expect that most ratings would be between -0.57 and 6.57. However, since scores can't be negative, the practical range starts from 0. Therefore, we can say that around 68% of the scores from the class will be between 0 and 6.57, giving a more concrete understanding of how the ratings for the class representative are distributed. This empirical analysis is crucial when making predictions or hypotheses about our data's behavior.

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