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Calculate the expected value, the variance, and the standard deviation of the given random variable \(X .\) You calculated the expected values in the last exercise set. Round all answers to two decimal places.) I Twenty darts are thrown at a dartboard. The probability of hitting a bull's-eye is .1. Let \(X\) be the number of bull's-eyes hit.

Short Answer

Expert verified
The expected value, variance, and standard deviation of the random variable \(X\) (number of bull's-eyes hit) are given by \(E(X) = 2\), \(Var(X) = 1.8\), and \(SD(X) \approx 1.34\), respectively.

Step by step solution

01

Find the expected value of the random variable \(X\) using the formula

For a binomial distribution, the expected value or mean, denoted as \(E(X)\), is given by: $$ E(X) = np $$ In this case, we have \(n=20\) and \(p=0.1\). So, we can calculate the expected value as: $$ E(X) = 20 \times 0.1 = 2 $$ Therefore, the expected value of the number of bull's-eyes hit is 2.
02

Find the variance of the random variable \(X\) using the formula

For a binomial distribution, the variance, denoted as \(Var(X)\), is given by: $$ Var(X) = np(1-p) $$ Using the given parameters, we have \(n=20\), \(p=0.1\), and \((1-p) = 0.9\). So, we can calculate the variance as: $$ Var(X) = 20 \times 0.1 \times 0.9= 1.8 $$ Therefore, the variance of the number of bull's-eyes hit is 1.8.
03

Find the standard deviation of the random variable \(X\) using the formula

The standard deviation, denoted as \(SD(X)\), is the square root of the variance. So, we can calculate the standard deviation as: $$ SD(X) = \sqrt{Var(X)} = \sqrt{1.8} $$ After calculation, we get: $$ SD(X) \approx 1.34 $$ Therefore, the standard deviation of the number of bull's-eyes hit is approximately 1.34 (rounded to two decimal places). In conclusion, the expected value, variance, and standard deviation of the random variable \(X\) (number of bull's-eyes hit) are given by \(E(X) = 2\), \(Var(X) = 1.8\), and \(SD(X) \approx 1.34\), respectively.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value Calculation
When studying the binomial distribution in statistics, the expected value is a keystone concept that represents the average outcome of a random variable over many trials. It essentially gives you the 'center' of the distribution for a particular binomial process. For example, if you fling darts at a board 20 times, the expected value tells you the average number of bull's-eyes you might hit if you repeat this experiment over and over again.

To calculate the expected value, denoted as \(E(X)\), for a binomial distribution, you multiply the total number of trials (\(n\)) by the probability of success on a single trial (\(p\)). In mathematical terms, the formula is expressed as \(E(X) = np\). So, if you have a 10% chance (0.1) to hit a bull's-eye each time and throw 20 darts, the expected value is \(20 \times 0.1 = 2\). This result means that on average, you can expect to hit the bull's-eye twice.
Variance Calculation
The concept of variance in a binomial distribution is crucial because it measures the spread of the distribution, or simply put, how much the number of bull's-eyes you hit is likely to fluctuate from the average expected value.

To calculate the variance, denoted as \(Var(X)\), you'll need the formula \(Var(X) = np(1-p)\). This formula incorporates both the likelihood of hitting and missing the target (expressed as \((1-p)\)). In our dart throwing example, with 20 darts and a 10% chance of hitting the bull's-eye, the variance calculation would be \(Var(X) = 20 \times 0.1 \times (1 - 0.1) = 1.8\). The outcome signifies that the number of successful hits will typically deviate from the average by a measure squared of 1.8 per series of 20 throws.
Standard Deviation Calculation
In the realm of binomial distribution, standard deviation is a more intuitive measure of variability than variance because it is in the same units as the original data. While variance tells you how squared results deviate from the expected value, standard deviation tells you more directly how much the actual count of bull's-eyes will likely deviate from the average.

The standard deviation, denoted as \(SD(X)\), is the square root of the variance. The formula to find standard deviation in a binomial distribution simplifies to \(SD(X) = \sqrt{Var(X)}\). With a variance of 1.8 in our example, the standard deviation calculates to \(SD(X) = \sqrt{1.8} \approx 1.34\). So, when you throw 20 darts, the number of bull's-eyes you hit will typically deviate from the average (2) by about 1.34 in either direction.

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Most popular questions from this chapter

Slim tells you that the population mean is just the mean of a suitably large sample. Is he correct? Explain.

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