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A fair die is rolled, and \(X\) is the square of the number facing up.

Short Answer

Expert verified
The possible values of \(X\) are 1, 4, 9, 16, 25, and 36 with a probability of \(\frac{1}{6}\) each. The expected value of \(X\) is \(E(X) = \frac{1+4+9+16+25+36}{6} = \frac{91}{6}\).

Step by step solution

01

Identify possible outcomes and corresponding probabilities

Since we have a fair die, there are 6 possible outcomes with an equal probability of \(\frac{1}{6}\) each. List down all the possible outcomes and their probabilities: 1. The number facing up is 1, so \(X=1^2=1\); probability: \(\frac{1}{6}\). 2. The number facing up is 2, so \(X=2^2=4\); probability: \(\frac{1}{6}\). 3. The number facing up is 3, so \(X=3^2=9\); probability: \(\frac{1}{6}\). 4. The number facing up is 4, so \(X=4^2=16\); probability: \(\frac{1}{6}\). 5. The number facing up is 5, so \(X=5^2=25\); probability: \(\frac{1}{6}\). 6. The number facing up is 6, so \(X=6^2=36\); probability: \(\frac{1}{6}\).
02

Compute the expected value of \(X\)

The expected value of a random variable is the sum of the possible values of the variable multiplied by their respective probabilities. For \(X\), this can be computed as follows: Expected Value, \(E(X) = \sum_{i=1}^{6}(X_i * P(X_i))\) Plugging in the value of \(X_i\) and \(P(X_i)\) from Step 1: \(E(X) = 1*\frac{1}{6} + 4*\frac{1}{6} + 9*\frac{1}{6} + 16*\frac{1}{6} + 25*\frac{1}{6} + 36*\frac{1}{6}\) Now, evaluate the sum: \(E(X) = \frac{1+4+9+16+25+36}{6}\)
03

Evaluate and simplify

Compute the sum and simplify: \(E(X) = \frac{91}{6}\) Hence, the expected value of the random variable \(X\), which represents the square of the number facing up on a fair die, is \(\frac{91}{6}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability and Its Role in Expected Value
Probability is a fundamental concept in mathematics, crucial for determining the likelihood of various outcomes. It offers a numerical value to the likelihood of an event, typically ranging from 0 to 1. A probability of 0 indicates that an event will not occur, while a probability of 1 indicates certainty. In our exercise of rolling a fair die, each face of the die has an equal probability of appearing:
  • Each number (1 through 6) has a probability of \( rac{1}{6}\).
This is because there are six faces, all equally likely to land facing up on a fair die.
When calculating the expected value of a random variable such as the square of the number on the die, understanding probabilities allows us to correctly weigh each outcome by its chance of occurrence. By combining probabilities with values, we compute important statistical properties that describe the distributions of random processes.
Understanding Random Variables
A random variable is a variable whose possible values are outcomes of a random phenomenon. It serves as a bridge between probabilistic concepts and real-world phenomena, often allowing us to apply mathematical rigor to situations with inherent uncertainty. In our context, the random variable \(X\) is defined as the square of the number rolled on a die. This turns a simple number into a squared outcome:
  • For instance, if we roll a 2, \(X\) becomes \(2^2=4\).
Random variables can be classified into discrete and continuous. Here, \(X\) is discrete because it takes on specific, distinct values based on the outcome of the die roll. Understanding this helps us determine how to approach calculations and predictions based on the random variable. Different outcomes result in different values of \(X\), each occurring with a certain probability, which we use to calculate things like the expected value.
Exploring Discrete Distribution
A discrete distribution is a probability distribution that shows the probabilities of outcomes with discrete values. These are specific and countable, like the outcomes of rolling a die. In our exercise, the values of the random variable \(X\) are distinct numbers: 1, 4, 9, 16, 25, 36. Each of these is the square of a number from the die roll.
The probabilities associated with each value are all \(\frac{1}{6}\) because the die is fair. This uniform probability across outcomes is a key feature of a discrete uniform distribution, where each outcome is just as likely as any other.
  • Discrete distributions are often represented using probability mass functions, which sum to 1 over all possible outcomes.
Applying discrete distribution theory allows us to compute expected values and other useful statistics that characterize the behavior of random variables like \(X\). Understanding this framework empowers us to make informed predictions and decisions based on probabilistic data.

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