/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 Weather Prediction There is a \(... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Weather Prediction There is a \(20 \%\) chance of snow today and a. \(20 \%\) chance of snow tomorrow. Assuming that the event that it snows today is independent of the event that it snows tomorrow, draw a tree diagram showing the probabilities of all outcomes. What is the probability that it will snow by the end of tomorrow?

Short Answer

Expert verified
The probability that it will snow by the end of tomorrow is \(36\%\), considering the tree diagram with the independent probabilities of snow today (\(20\%\)) and tomorrow (\(20\%\)). This is calculated by summing up the probabilities of each scenario where it snows at least once: snow today but not tomorrow (\(16\%\)), no snow today but tomorrow (\(16\%\)), and snow both today and tomorrow (\(4\%\)).

Step by step solution

01

Draw a tree diagram with the independent probabilities

To represent the possible scenarios and their corresponding probabilities, we draw a tree diagram. Each branch of the tree represents a snow (S) or no snow (NS) scenario, with the given probability at each level (day): 1st day 2nd day / \ S NS / \ / \ 0.20 0.80 S NS \ / \ 0.20 0.80 / \ 0.20 0.80
02

Compute probability of each scenario

Now, we'll calculate the probability of each possible snow scenario: 1. Probability of snow today but not tomorrow (S_NT): \(0.20 \times 0.80 = 0.16\) 2. Probability of no snow today but tomorrow (NS_T): \(0.80 \times 0.20 = 0.16\) 3. Probability of snow both today and tomorrow (S_T): \(0.20 \times 0.20 = 0.04\)
03

Determine probability of snow by the end of tomorrow

To compute the probability of it snowing by the end of tomorrow, we will sum the probabilities of each scenario where it snows at least once: Probability of snow by the end of tomorrow = P(S_NT) + P(NS_T) + P(S_T) = 0.16 + 0.16 + 0.04 = 0.36 Thus, the probability that it will snow by the end of tomorrow is \(36\%\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tree Diagram
A tree diagram is a visual representation used to explore all the possible outcomes of an event and their probabilities. It consists of branches that depict the outcomes of various decisions or random events. This type of diagram is particularly useful for understanding the combination of multiple independent events.

For the weather prediction example, the tree diagram starts with today and branches out to represent the possibility of snow (S) or no snow (NS). Each branch then splits again for tomorrow's outcomes, creating a comprehensive visual of all potential scenarios across both days. It's important to draw each branch with the corresponding probability. This helps students visualize the problem and understand that the same possibilities exist for each separate event, emphasizing the concept of independence.
Probability Calculation
Probability calculation involves determining the likelihood of one or more events occurring. When calculating the probabilities of independent events, one can simply multiply the probabilities of each individual event occurring to find the joint probability. For example, to compute the probability of snow on both days, we multiply the probability of snow on the first day by the probability of snow on the second day.

It's useful to note each multiplication vertically below the tree diagram's branches—this practice aids in keeping track of the calculations, which improves accuracy. We calculate the probability of each scenario: snowing only on the first day, only on the second day, on both days, and not at all. Adding together the probabilities of the scenarios where it snows at least once will give us the probability that it will snow by the end of tomorrow.
Independent Probability
Independent probability is the likelihood of two or more events occurring where the outcome of one event does not affect the other. For instance, in the context of weather prediction, the probability that it snows today has no impact on whether it will snow tomorrow - these events are independent. This property allows us to multiply the probability of snow on one day by the probability of snow on the other day to find the combined probability of those independent events.

Understanding independence is crucial because it simplifies complex problems. Without the assumption of independence, we would have to consider the complete range of possible interactions between events, complicating the probability calculation. However, when the events are independent, we can calculate the probability of their joint occurrence by multiplication, which is a fundamental aspect of solving probability problems involving independent events.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

According to a study conducted by the Harvard School of Public Health, a child seated in the front seat who was wearing a seatbelt was \(31 \%\) more likely to be killed in an accident if the car had an air bag that deployed than if it did not. \({ }^{50}\) Let the sample space \(S\) be the set of all accidents involving a child seated in the front seat wearing a seatbelt. Let \(K\) be the event that the child was killed and let \(D\) be the event that the airbag deployed. Fill in the missing terms and quantities: \(P(\longrightarrow \mid \longrightarrow)=\longrightarrow P(\longrightarrow \mid \longrightarrow)\). HINT [When we say "A is \(31 \%\) more likely than \(\mathrm{B}\) " we mean that the probability of \(\mathrm{A}\) is \(1.31\) times the probability of B.]

\(\nabla\) True or false? Every set \(S\) is the sample space for some experiment. Explain.

Pablo randomly picks three marbles from a bag of eight marbles (four red ones, two green ones, and two yellow ones). \- How many outcomes are there in the event that Pablo grabs three red marbles?

Pablo randomly picks three marbles from a bag of eight marbles (four red ones, two green ones, and two yellow ones). How many outcomes are there in the event that Pablo's marbles are not all the same color?

Based on the following table, which shows the performance of a selection of 100 stocks after one year. (Take S to be the set of all stocks represented in the table.) $$ \begin{array}{|r|c|c|c|c|} \hline & \multicolumn{3}{|c|} {\text { Companies }} & \\ \cline { 2 - 4 } & \begin{array}{c} \text { Pharmaceutical } \\ \boldsymbol{P} \end{array} & \begin{array}{c} \text { Electronic } \\ \boldsymbol{E} \end{array} & \begin{array}{c} \text { Internet } \\ \boldsymbol{I} \end{array} & \text { Total } \\ \hline \begin{array}{r} \text { Increased } \\ \boldsymbol{V} \end{array} & 10 & 5 & 15 & 30 \\ \hline \begin{array}{r} \text { Unchanged }^{*} \\ \boldsymbol{N} \end{array} & 30 & 0 & 10 & 40 \\ \hline \begin{array}{r} \text { Decreased } \\ \boldsymbol{D} \end{array} & 10 & 5 & 15 & 30 \\ \hline \text { Total } & 50 & 10 & 40 & 100 \\ \hline \end{array} $$ If a stock stayed within \(20 \%\) of its original value, it is classified as "unchanged." Use symbols to describe the event that an Internet stock did not increase. How many elements are in this event?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.