/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Compute the indicated quantity. ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Compute the indicated quantity. $$ P(A \mid B)=.4, P(A \cap B)=.1 \text { . Find } P(B) \text { . } $$

Short Answer

Expert verified
The probability of event B is \(P(B) = 0.25\).

Step by step solution

01

Write down the given probabilities

We are given the following probabilities: \(P(A \mid B) = 0.4\) \(P(A \cap B) = 0.1\)
02

Write down the formula for conditional probability

We will use the formula for conditional probability which is: \(P(A \mid B) = \frac{P(A \cap B)}{P(B)}\)
03

Substitute the given probabilities into the formula

Plug in the given values of \(P(A \mid B)\) and \(P(A \cap B)\) into the formula: \(0.4 = \frac{0.1}{P(B)}\)
04

Solve for P(B)

To solve for \(P(B)\), we can multiply both sides of the equation by \(P(B)\): \(0.4 \times P(B) = 0.1\) Now, divide both sides by 0.4: \(P(B) = \frac{0.1}{0.4}\)
05

Compute the value of P(B)

Divide 0.1 by 0.4: \(P(B) = \frac{0.1}{0.4} = 0.25\) So, the probability of event B is 0.25.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
At its core, probability theory is the branch of mathematics that studies randomness and uncertainty. It provides the foundational framework for predicting the likelihood of various outcomes in experiments or events. In essence, probability quantifies the expectation that a certain event will occur and is usually expressed as a number between 0 and 1, where 0 indicates impossibility and 1 indicates certainty.

Within this framework, different types of probabilities can be discussed, such as marginal probability, which is the probability of a single event occurring, and joint probability, denoted as \(P(A \text{ and } B)\) or \(P(A \bigcap B)\), which is the probability of two events occurring together. Notably, understanding these basic concepts is vital to make sense of more complex ideas such as conditional probability, which forms the basis of the exercise in question.
Bayes Theorem
Bayes theorem is a powerful formula used in probability theory to update the probability of an event based on new information. This theorem is named after Thomas Bayes, an 18th-century statistician and theologian. It's especially useful in situations where the conditional probabilities are known, but the reverse is required.

The theorem is mathematically expressed as:\[P(A|B) = \frac{{P(B|A)P(A)}}{{P(B)}}\]
where \(P(A|B)\) is the probability of event A occurring given that B is true, \(P(B|A)\) is the probability of event B occurring given that A is true, \(P(A)\) is the probability of event A, and \(P(B)\) is the probability of event B. Bayes theorem hence allows us to reverse the conditionality - if we want to find \(P(B|A)\) but only know \(P(A|B)\), the theorem provides the means to do so. In the original exercise, the use of Bayes theorem is implicit in the manipulation of the conditional probability formula, illustrating the interconnected nature of these principles.
Finite Mathematics
Finite mathematics is a term that encompasses various topics in mathematics that deal with finite or discrete elements, as opposed to continuous, which would fall under calculus and real analysis. This field includes, but is not limited to, subjects like algebra, graph theory, combinatorics, and yes, elements of probability theory. In fact, much of the probability theory taught at high school and early college levels can be considered a part of finite mathematics.

In the context of finite mathematics, probabilities are typically studied in scenarios where there are a finite number of outcomes, such as the probability of drawing a certain card from a deck. The exercise we have tackled involves finite mathematics, as we are dealing with discrete and quantifiable events A and B. Understanding how to calculate probabilities in these scenarios is fundamental in finite mathematics and has practical applications in fields as diverse as insurance, finance, computer science, and even philosophy.

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Most popular questions from this chapter

Design an experiment based on rolling a fair die for which there are exactly three outcomes with the same probabilities.

Let \(E\) be the event that you meet a tall dark stranger. Which of the following could reasonably represent the experiment and sample space in question? (A) You go on vacation and lie in the sun; \(S\) is the set of cloudy days. (B) You go on vacation and spend an evening at the local dance club; \(S\) is the set of people you meet. (C) You go on vacation and spend an evening at the local dance club; \(S\) is the set of people you do not meet.

Other dice are constructed in such a way that deuce is six times as likely to come up as 4 and four times as likely to come up as each of \(1,3,5\), and 6 .

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Based on the following table, which shows the performance of a selection of 100 stocks after one year. (Take S to be the set of all stocks represented in the table.) $$ \begin{array}{|r|c|c|c|c|} \hline & \multicolumn{3}{|c|} {\text { Companies }} & \\ \cline { 2 - 4 } & \begin{array}{c} \text { Pharmaceutical } \\ \boldsymbol{P} \end{array} & \begin{array}{c} \text { Electronic } \\ \boldsymbol{E} \end{array} & \begin{array}{c} \text { Internet } \\ \boldsymbol{I} \end{array} & \text { Total } \\ \hline \begin{array}{r} \text { Increased } \\ \boldsymbol{V} \end{array} & 10 & 5 & 15 & 30 \\ \hline \begin{array}{r} \text { Unchanged }^{*} \\ \boldsymbol{N} \end{array} & 30 & 0 & 10 & 40 \\ \hline \begin{array}{r} \text { Decreased } \\ \boldsymbol{D} \end{array} & 10 & 5 & 15 & 30 \\ \hline \text { Total } & 50 & 10 & 40 & 100 \\ \hline \end{array} $$ If a stock stayed within \(20 \%\) of its original value, it is classified as "unchanged." Find all pairs of mutually exclusive events among the events \(P, E, I, V, N\), and \(D .\)

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