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You are given a transition matrix \(P\) and initial distribution vector \(v\). Find (a) the two-step transition matrix and (b) the distribution vectors after one, two, and three steps. $$ P=\left[\begin{array}{cc} 1 / 2 & 1 / 2 \\ 1 & 0 \end{array}\right], v=\left[\begin{array}{ll} 2 / 3 & 1 / 3 \end{array}\right] $$

Short Answer

Expert verified
In conclusion: (a) The two-step transition matrix (P^2) is: \[ P^2 = \left[\begin{array}{cc} 3/4 & 1/4 \\\ 1/2 & 1/2 \end{array}\right] \] (b) Distribution vectors after one, two, and three steps are: 1. One-step distribution vector: \( \left[\begin{array}{cc} 1 & 1/3 \end{array}\right] \) 2. Two-step distribution vector: \( \left[\begin{array}{cc} 5/6 & 2/6 \end{array}\right] \) 3. Three-step distribution vector: \( \left[\begin{array}{cc} 13/24 & 11/24 \end{array}\right] \)

Step by step solution

01

(Step 1: Compute P^2 - Two-step transition matrix)

Begin by finding P^2, the two-step transition matrix. To do this, multiply P by itself: \[ P^2 = P×P = \left[\begin{array}{cc} 1/2 & 1/2 \\\ 1 & 0 \end{array}\right] × \left[\begin{array}{cc} 1/2 & 1/2 \\\ 1 & 0 \end{array}\right] \]
02

(Step 2: Calculate matrix product to obtain P^2)

Next, find the product of the two matrices: \[ P^2 = \left[\begin{array}{cc} (1/2)(1/2) + (1/2)(1) & (1/2)(1/2) + (1/2)(0) \\\ (1)(1/2) + (0)(1) & (1)(1/2) + (0)(0) \end{array}\right] = \left[\begin{array}{cc} 3/4 & 1/4 \\\ 1/2 & 1/2 \end{array}\right] \] So, the two-step transition matrix (P^2) is: \[ P^2 = \left[\begin{array}{cc} 3/4 & 1/4 \\\ 1/2 & 1/2 \end{array}\right] \]
03

(Step 3: Compute distribution vectors after one, two, and three steps)

Now, calculate the distribution vectors after one, two, and three steps using the powers of P and the initial distribution vector v: 1. One-step distribution vector: \( vP \) 2. Two-step distribution vector: \( vP^2 \) 3. Three-step distribution vector: \( vP^3 \) (compute P^3 first)
04

(Step 4: Calculate one-step distribution vector)

First, compute the one-step distribution vector: \[ vP = \left[\begin{array}{cc} 2/3 & 1/3 \end{array}\right] × \left[\begin{array}{cc} 1/2 & 1/2 \\\ 1 & 0 \end{array}\right] = \left[\begin{array}{cc} 1 & 1/3 \end{array}\right] \] So, the one-step distribution vector is: \( \left[\begin{array}{cc} 1 & 1/3 \end{array}\right] \)
05

(Step 5: Calculate two-step distribution vector)

Next, compute the two-step distribution vector: \[ vP^2 = \left[\begin{array}{cc} 2/3 & 1/3 \end{array}\right] × \left[\begin{array}{cc} 3/4 & 1/4 \\\ 1/2 & 1/2 \end{array}\right] = \left[\begin{array}{cc} 5/6 & 2/6 \end{array}\right] \] So, the two-step distribution vector is: \( \left[\begin{array}{cc} 5/6 & 2/6 \end{array}\right] \)
06

(Step 6: Calculate P^3 and three-step distribution vector)

To find the three-step distribution vector, begin by calculating P^3: \[ P^3 = P^2 × P = \left[\begin{array}{cc} 3/4 & 1/4 \\\ 1/2 & 1/2 \end{array}\right] × \left[\begin{array}{cc} 1/2 & 1/2 \\\ 1 & 0 \end{array}\right] = \left[\begin{array}{cc} 5/8 & 3/8 \\\ 3/4 & 1/4 \end{array}\right] \] Now, compute the three-step distribution vector: \[ vP^3 = \left[\begin{array}{cc} 2/3 & 1/3 \end{array}\right] × \left[\begin{array}{cc} 5/8 & 3/8 \\\ 3/4 & 1/4 \end{array}\right] = \left[\begin{array}{cc} 13/24 & 11/24 \end{array}\right] \] So, the three-step distribution vector is: \( \left[\begin{array}{cc} 13/24 & 11/24 \end{array}\right] \) In conclusion: (a) The two-step transition matrix (P^2) is: \[ P^2 = \left[\begin{array}{cc} 3/4 & 1/4 \\\ 1/2 & 1/2 \end{array}\right] \] (b) Distribution vectors after one, two, and three steps are: 1. One-step distribution vector: \( \left[\begin{array}{cc} 1 & 1/3 \end{array}\right] \) 2. Two-step distribution vector: \( \left[\begin{array}{cc} 5/6 & 2/6 \end{array}\right] \) 3. Three-step distribution vector: \( \left[\begin{array}{cc} 13/24 & 11/24 \end{array}\right] \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Multiplication
Matrix multiplication is a fundamental operation in linear algebra that allows us to compute the product of two matrices. This procedure is crucial when working with transition matrices in the context of Markov chains. To multiply two matrices, we take the dot product of the rows of the first matrix with the columns of the second matrix. For instance, if we have two matrices A and B, the element c_{ij} of the product matrix C is calculated by multiplying the elements of the iA with the corresponding elements of the jB, and adding the results together.

When applying matrix multiplication to a transition matrix P in a Markov chain, it's essential to ensure that the matrices are compatible; that is, the number of columns in the first matrix must equal the number of rows in the second matrix. Matrix multiplication is not commutative, meaning that the order in which you multiply matrices matters. In our exercise, we compute the two-step transition matrix by multiplying the transition matrix by itself, resulting in P2.

To avoid common mistakes, always check that you've aligned the rows and columns correctly, and remember that each element in the resulting matrix is the sum of products of corresponding elements, not just a single multiplication.
Distribution Vector
A distribution vector in a Markov chain represents the state of a system at a particular time step. It's a matrix, typically written in a row format, that gives the probabilities for each state. In the exercise, we were given an initial distribution vector v, which represents the system's state at the start. By multiplying the distribution vector by the transition matrix, we update the state for subsequent time steps.

For example, the one-step distribution vector is obtained by multiplying the initial vector v by the matrix P, representing the state after one step. Similarly, to find the distribution after two and three steps, we use matrix multiplication to calculate vP2 and vP3. It's crucial to apply matrix multiplication rules carefully to ensure the resulting vector maintains valid probabilities, meaning each element must be between 0 and 1, and the sum of all elements must equal 1.

Keep in mind that when you're interpreting the resulting distribution vector, you're looking at the probability distribution after each number of steps taken, which provides insight into the behavior of the system modeled by the Markov chain over time.
Markov Chains
Markov chains are a mathematical system that undergoes transitions from one state to another on a state space. They are a type of stochastic process with the property of memorylessness, which means that the probability of transitioning to any particular state depends only on the current state and not on the sequence of events that preceded it.

Markov chains are represented by transition matrices, where each entry p_{ij} signifies the probability of moving from state i to state j. These transition probabilities must all be non-negative and sum up to 1 in each row, reflecting the total probability of transitioning out of each state. By performing matrix multiplication, we can evaluate the probabilities of being in different states after multiple transitions -- a concept that we explored in the exercise by calculating one, two, and three-step distribution vectors.

To correctly apply the concept of Markov chains, remember that the state probabilities at each step are determined by the distribution vector, which evolves according to the rules defined by the transition matrix.

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Most popular questions from this chapter

\(\nabla\) Two distinguishable dice are rolled. Could there be two mutually exclusive events that both contain outcomes in which the numbers facing up add to 7 ?

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