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Let \(S=\\{\) Barnsley, Manchester United, Southend, Sheffield United, Liverpool, Maroka Swallows, Witbank Aces, Roval Tigers, Dundee United, Lyon' be a universal set, \(A=\\{\) Southend, Liverpool, Maroka Swallows, Royal Tigers\\}, and \(B=\\{\) Barnsley, Manchester United, Southend\\}. Find the numbers indicated. \(n\left((A \cap B)^{\prime}\right)\)

Short Answer

Expert verified
\(n\left((A \cap B)^{\prime}\right) = 9\)

Step by step solution

01

Find the intersection of sets A and B

We are given two sets A and B. To find their intersection, we need to find the elements common to both sets: Let's list the elements of both sets: \(A = \{\) Southend, Liverpool, Maroka Swallows, Royal Tigers \(\}\) \(B = \{\) Barnsley, Manchester United, Southend \(\}\) Now we look for common elements between A and B: \(A \cap B = \{\) Southend \(\}\)
02

Find the complement of the intersection with respect to set S

Since we have found the set \((A \cap B)\), now we need to find its complement with respect to the universal set S. This can be done by looking at all elements in S that are not in \((A \cap B)\). Let's list all elements of the universal set S: \(S = \{\) Barnsley, Manchester United, Southend, Sheffield United, Liverpool, Maroka Swallows, Witbank Aces, Royal Tigers, Dundee United, Lyon \(\}\) Given the set \((A \cap B) = \{\) Southend \(\}\), the complement of \((A \cap B)\) in S can be found as follows: \((A \cap B)^{\prime} = S - (A \cap B)\) \((A \cap B)^{\prime} = \{\) Barnsley, Manchester United, Sheffield United, Liverpool, Maroka Swallows, Witbank Aces, Royal Tigers, Dundee United, Lyon \(\}\)
03

Count the number of elements in the complement set

Now that we have the complement set \((A \cap B)^{\prime}\), we can count its number of elements to find its cardinality: \(n\left((A \cap B)^{\prime}\right) = 9\) So there are 9 elements in the set \((A \cap B)^{\prime}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Universal Set
In set theory, the universal set is the largest set under consideration. It contains all the possible elements relevant to a particular problem or context. For example, in our problem, the universal set, denoted as \(S\), is defined to include several football teams: Barnsley, Manchester United, Southend, Sheffield United, Liverpool, Maroka Swallows, Witbank Aces, Royal Tigers, Dundee United, and Lyon.

The concept of the universal set is crucial because it provides a reference for determining the complement of a set. Every other set being discussed is considered a subset of the universal set. For any problem involving set operations like intersection or complements, specifying the universal set ensures that we are clear about all possible elements we can choose from. This helps in various operations, including finding the complement of a set.
  • Universal sets define the boundary of discussion for set-related problems.
  • They encompass all subsets considered in a given context.
  • Knowing the universal set is essential for operations like finding complements.
Intersection of Sets
The intersection of sets is a fundamental operation in set theory. It involves finding elements that are common to two or more sets. When determining the intersection of two sets, we only consider the elements that appear in both sets.

For instance, in the given problem, we have two sets: \(A = \{\text{Southend, Liverpool, Maroka Swallows, Royal Tigers}\}\) and \(B = \{\text{Barnsley, Manchester United, Southend}\}\). To find \(A \cap B\), we list elements common to both sets. Here, Southend is the only element present in both \(A\) and \(B\). So, the intersection \(A \cap B = \{\text{Southend}\}\).

Intersection is useful to identify shared attributes or elements in different groups and is fundamental in operations spanning data analysis, probability, and logic.
Set Complement
The complement of a set, especially within the context of a universal set, includes all elements in the universal set that are not part of the specified set. To find the complement, we subtract the elements of the set from the universal set, leaving us with elements exclusive to the universal set.

In this problem, we already identified \(A \cap B = \{\text{Southend}\}\). To find the complement of \((A \cap B)\), denoted as \((A \cap B)'\), we consider all elements in \(S\) that are not in \(A \cap B\). Thus:

\[(A \cap B)' = \{\text{Barnsley, Manchester United, Sheffield United, Liverpool, Maroka Swallows, Witbank Aces, Royal Tigers, Dundee United, Lyon}\}\]

The complement is important in many areas such as probability and logic, as it denotes what is outside a particular focus or condition and complements include all entities not considered within a specific set.
Cardinality of Sets
Cardinality refers to the number of elements in a set. It gives us a way to measure the "size" of the set. Calculating the cardinality of a set involves simply counting its elements.

Once we determined \((A \cap B)'\), finding its cardinality, represented as \(n((A \cap B)')\), helps understand how many elements are included in the complementary space outside of the intersecting elements. Here, the elements in \((A \cap B)'\) encompass Barnsley, Manchester United, Sheffield United, Liverpool, Maroka Swallows, Witbank Aces, Royal Tigers, Dundee United, and Lyon, resulting in a total count of 9. Thus, \(n((A \cap B)') = 9\).

Understanding cardinality helps in comparison between sets and is fundamental in tasks involving data analysis and probabilistic calculations, because it provides a numeric representation of a set's contents.

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