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Consider the following example of a nonlinear programming problem: Maximize \(p=x y\) subject to \(x \geq 0, y \geq 0\), \(x+y \leq 2\). Show that \(p\) is zero on every corner point, but is greater than zero at many noncorner points.

Short Answer

Expert verified
The function \(p = xy\) evaluates to zero at every corner point of the feasible region defined by the constraints \(x \geq 0, y \geq 0\), and \(x+y \leq 2\). These corner points are \((0, 0)\), \((2, 0)\), and \((0, 2)\). However, at non-corner points within the feasible region, such as \((1, 0.5)\) and \((0.5, 1)\), the function's value is greater than zero. This implies that the function may not be optimal at every corner point.

Step by step solution

01

Find the corner points

First, we need to find the corner points of the feasible region. The feasible region is a two-dimensional space with constraints: 1. \(x \geq 0\) 2. \(y \geq 0\) 3. \(x + y \leq 2\) The corner points lie at the intersections of these constraint boundaries. In this case, since we have two variables (\(x\) and \(y\)), we have 2D (x-y plane) corner points, which can be determined by plotting the constraints on a graph. The corner points are: 1. \((0, 0)\): This is the intersection of the coordinate system's origin with the \(x\) and \(y\) axes. 2. \((2, 0)\): This is the intersection of the \(x\)-axis and the line \(x+y=2\). 3. \((0, 2)\): This is the intersection of the \(y\)-axis and the line \(x+y=2\).
02

Evaluate the function p at the corner points

Now, we need to calculate the value of the function \(p(xy)\) for each corner point. [p(0, 0)]=0: Plugging \((x, y) = (0, 0)\), we get \(p(0, 0) = 0 * 0 = 0\). [p(2, 0)]=0: Plugging \((x, y) = (2, 0)\), we get \(p(2, 0) = 2 * 0 = 0\). [p(0, 2)]=0: Plugging \((x, y) = (0, 2)\), we get \(p(0, 2) = 0 * 2 = 0\). Thus, the function \(p\) evaluates to zero at each corner point of the feasible region.
03

Show that p is greater than zero at non-corner points

To show that the function's value is greater than zero at non-corner points, let's choose some arbitrary points inside the feasible region. Choose point \(A = (1, 0.5)\): Plugging \((x, y) = (1, 0.5)\), we get \(p(1, 0.5) = 1 * 0.5 = 0.5\). Choose point \(B = (0.5, 1)\): Plugging \((x, y) = (0.5, 1)\), we get \(p(0.5, 1) = 0.5 * 1 = 0.5\). In both of these examples, the chosen non-corner points yield a value of \(p>0\). We can continue testing other points within the feasible region and will find many non-corner points where the value of \(p\) is indeed greater than zero. In conclusion, we have shown that the function's value is zero at every corner point and greater than zero at many non-corner points within the feasible region. This implies that the function may not be optimal at every corner point.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Feasible Region
The concept of a feasible region is fundamental to understanding nonlinear programming problems. This region represents all possible values of the decision variables that meet the given constraints. In the context of our sample exercise, the feasible region is defined by the constraints: the variables must be non-negative, and their sum must not exceed 2.

This feasible region is graphically illustrated in a 2-dimensional space where each point corresponds to a potential solution — a pair of values for variables x and y. By plotting the equations and inequalities that represent our constraints, we can visualize this region explicitly. Typically, it appears as a geometric shape, where all the points inside and on the edges are potential solutions to the problem.

Understanding the feasible region is crucial for students, as it provides a clear visual representation of where to look for potential solutions and helps simplify the process of optimization. For instance, in our exercise, optimizing the function means finding the maximum product of x and y within this specified region.
Corner Points
In the realm of optimization, corner points — also known as extreme points or vertices — are of specific interest. These points are the locations on the boundary of the feasible region where the constraint lines intersect. In a 2-dimensional problem, these points are like the corners of a polygon.

To calculate the value of the objective function at the corner points, we simply substitute the values of x and y at each corner into the equation. For our nonlinear problem, doing so confirms that the function p = xy equals zero at all corner points, which are (0, 0), (2, 0), and (0, 2).

Students should recognize that the significance of these points lies in the fact that, for linear programming problems, the optimal solution often lies at a corner point. However, this exercise vividly demonstrates that for nonlinear problems, this may not always be the case, and values inside the feasible region can yield better solutions.
Optimization Constraints
Constraints are the conditions that must be satisfied for a solution to be considered valid within an optimization problem. They define the feasible region and eliminate impossible or undesired solutions. In our example, the constraints are x and y cannot be negative, and their sum must be less than or equal to 2. These are mathematical expressions of the physical or environmental limitations of the problem.

In simpler terms, these optimization constraints act as rules for the optimization game. Our goal is to score the highest possible value for the chosen objective function, p, while still playing within the boundaries set by these rules. Learning to identify and apply constraints correctly is crucial for students, as it enables them to narrow down the vast field of potential solutions to a manageable set of possibilities. By thoroughly understanding constraints, students will enhance their problem-solving strategies for a wide range of optimization issues.

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Most popular questions from this chapter

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