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$$ \begin{aligned} \text { Minimize } & c=s+t+u \\ \text { subject to } & 3 s+2 t+u \geq 60 \\ & 2 s+t+3 u \geq 60 \\ & s+3 t+2 u \geq 60 \\ & s \geq 0, t \geq 0, u \geq 0 . \end{aligned} $$

Short Answer

Expert verified
The short answer to the given linear programming problem can be summarized as follows: 1. Graph the constraint inequalities: \(3s + 2t + u \geq 60\), \(2s + t + 3u \geq 60\), \(s + 3t + 2u \geq 60\), and \(s \geq 0\), \(t \geq 0\), \(u \geq 0\). 2. Identify the feasible region (the polyhedron where all constraint inequalities overlap). 3. Find the vertices of the feasible region by solving systems of linear equations formed by taking 3 constraints at a time. 4. Evaluate the objective function (\(c = s + t + u\)) at each vertex. 5. Compare the values of 'c' obtained for each vertex; the vertex with the smallest value of 'c' will be the optimal solution for the problem.

Step by step solution

01

Graph the constraint inequalities

: We need to graph the following constraint inequalities: 1. \(3s + 2t + u \geq 60\) 2. \(2s + t + 3u \geq 60\) 3. \(s + 3t + 2u \geq 60\) 4. \(s \geq 0, t \geq 0, u \geq 0\)
02

Identify the feasible region

: The feasible region is the set of points (s, t, u) that satisfy all constraints. Visually, this is the area of the graph where all constraint inequalities overlap. Remember that we are working in 3 dimensions, so this feasible region is likely to be a polyhedron.
03

Find the vertices of the feasible region

: Vertices are the points where constraint lines intersect. To find the vertices, we need to solve systems of linear equations formed by taking 3 constraint inequalities at a time (as we are dealing with 3 variables, we need 3 equations to solve for them). This can be done by the method of substitution, elimination, or by using matrix methods (Cramer's rule, for example).
04

Evaluate the objective function at each vertex

: Once the vertices of the feasible region have been determined, substitute the coordinates of each vertex into the objective function: \(c = s + t + u\) Calculate the value of 'c' for each vertex.
05

Choose the vertex with the minimum objective function value

: Finally, compare the values of 'c' obtained for each vertex. The vertex with the smallest value of 'c' will provide the minimum value of the objective function, thus giving the optimal solution for the problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constraint Inequalities
In linear programming, constraint inequalities are mathematical expressions that establish boundaries for the variables involved in an optimization problem.
These inequalities define conditions that the solutions must satisfy. In the given exercise, we have the following constraint inequalities:
  • \(3s + 2t + u \geq 60\)
  • \(2s + t + 3u \geq 60\)
  • \(s + 3t + 2u \geq 60\)
  • \(s \geq 0, t \geq 0, u \geq 0\)
These constraints essentially carve out a "space" in the solution domain that valid solutions must lie within.
In simpler terms, they tell us how the variables \(s\), \(t\), and \(u\) can interact with each other and the limits they are subject to. It is crucial to set the stage for feasible solutions which will be examined in the context of the Feasible Region.
Feasible Region
The feasible region in linear programming is the set of all points that satisfy the constraint inequalities simultaneously.
This area is formed by the intersection of all the geographies created by each individual constraint. For our problem, with the constraints expressed in three-dimensional space, the feasible region becomes more of a shape, like a polyhedron.
Any point inside or on the surface of this polyhedron represents a potential solution where all constraints are satisfied. Understanding this visual representation aids in seeing which combinations of \(s\), \(t\), and \(u\) form legal solutions.Intersections of the planes described by each inequality define this space and assessment of solutions takes place here. Thus, identifying this "area" is crucial for finding answers to our problem, as only within this region can we find optimal solutions in terms of resource allocation.
Objective Function Evaluation
In the context of linear programming, the objective function is the mathematical expression that we aim to optimize—either to maximize or minimize.
For this exercise, the given objective function is:\[c = s + t + u\]The goal is to minimize \(c\) under the constraints given. Objective function evaluation involves calculating this function for all significant points in our feasible region, mainly focusing on the vertices.
These calculations help determine how each combination of \(s\), \(t\), and \(u\) contributes to the function's value and subsequently guide us towards achieving the best possible outcome—here, the smallest total value of \(s + t + u\).
Let's move to see why vertices matter in this process next.
Vertices in Optimization
Vertices in optimization refer to the corner points of the feasible region. In linear programming problems, these points are critical.
They represent the combinations of \(s\), \(t\), and \(u\) where different planes (or constraint expressions) intersect.Since the objective function in a linear program changes linearly, it achieves its extremum values (maximum or minimum) at these vertices.
As such, we systematically identify them by solving simultaneous equations. Exploring these vertices tells us where exactly in the feasible region our sought-after minimum value of the objective function will occur.
It's often computational and visual efficiency in linear programs to move directly from one vertex to another to quickly find the optimal solution.

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Most popular questions from this chapter

Transportation Scheduling Your publishing company is about to start a promotional blitz for its new book, Physics for the Liberal Arts. You have 20 salespeople stationed in Chicago and 10 in Denver. You would like to fly at most 10 into Los Angeles and at most 15 into New York. A round-trip plane flight from Chicago to LA costs \(\$ 195 ;^{28}\) from Chicago to \(\mathrm{NY}\) costs \(\$ 182 ;\) from Denver to LA costs \(\$ 395 ;\) and from Denver to NY costs \(\$ 166\). You want to spend at most \(\$ 4,520\) on plane flights. How many salespeople should you fly from each of Chicago and Denver to each of \(\mathrm{LA}\) and \(\mathrm{NY}\) to have the most salespeople on the road?

Politics The political pollster Canter is preparing for a national election. It would like to poll at least 1,500 Democrats and 1,500 Republicans. Each mailing to the East Coast gets responses from 100 Democrats and 50 Republicans. Each mailing to the Midwest gets responses from 100 Democrats and 100 Republicans. And each mailing to the West Coast gets responses from 50 Democrats and 100 Republicans. Mailings to the East Coast cost \(\$ 40\) each to produce and mail, mailings to the Midwest cost \(\$ 60\) each, and mailings to the West Coast cost \(\$ 50\) each. How many mailings should Canter send to each area of the country to get the responses it needs at the least possible cost? What will it cost?

Create a linear programming problem in two variables that has more than one optimal solution.

(Compare with the preceding exercise.) You are thinking of making your mansion more energy efficient by replacing some of the light bulbs with compact fluorescent bulbs, and insulating part or all of your exterior walls. Each compact fluorescent light bulb costs \(\$ 4\) and saves you an average of \(\$ 2\) per year in energy costs, and each square foot of wall insulation costs \(\$ 1\) and saves you an average of \(\$ 0.20\) per year in energy costs. \(^{13}\) Your mansion has 200 light fittings and 3,000 sq. ft. of uninsulated exterior wall. To impress your friends, you would like to spend as much as possible, but save no more than \(\$ 800\) per year in energy costs (you are proud of your large utility bills). How many compact fluorescent light bulbs and how many square feet of insulation should you purchase? How much will you save in energy costs per year?

Solve the LP problems. If no optimal solution exists, indicate whether the feasible region is empty or the objective function is unbounded. \(\vee\) Minimize \(c=-x+2 y\) subject to \(\begin{aligned} y & \leq \frac{2 x}{3} \\\ x & \leq 3 y \\ y & \geq 4 \\ x & \geq 6 \\ x+y & \leq 16 . \end{aligned}\)

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