/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Sketch the region that correspon... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the region that corresponds to the given inequalities, say whether the region is bounded or unbounded, and find the coordinates of all corner points (if any). $$ 2 x+y<10 $$

Short Answer

Expert verified
The region corresponding to the inequality \(2x + y < 10\) is the area below the boundary line \(y = 10 - 2x\). This region is unbounded and there are no corner points for this specific problem.

Step by step solution

01

Rearrange the inequality to find the boundary line

We start solving the inequality by isolating y. We will also consider the inequality as an equation to find the boundary line which will help us in sketching the region. For the equation, we have: \(2x+y=10\) Now, let's isolate y: \(y = 10 - 2x\) This is the equation of the boundary line.
02

Sketch the boundary line

Next, we want to sketch the line \(y = 10 - 2x\). To do this, we will find the x and y-intercepts to help us draw the line. The x-intercept occurs when y = 0. So, we have: \(0 = 10 - 2x => x = 5\) Therefore, the x-intercept is (5, 0). The y-intercept occurs when x = 0. So, we have: \(y = 10 - 2(0) => y = 10\) Therefore, the y-intercept is (0, 10). Plot the x and y-intercepts and draw a straight line between them that extends to the edge of the graph.
03

Determine the region corresponding to the inequality

Now we need to determine which side of the line corresponds to the inequality \(2x + y < 10\). One technique to achieve this is to select a test point that doesn't lie on the line and see if the inequality is satisfied or not. If it is satisfied, then the region that the test point lies in corresponds to the inequality, and if it isn't, we need to consider the other region. Let's choose the test point (0, 0): \(2(0) + 0 < 10 => 0 < 10\) Since the inequality is satisfied, the region that corresponds to the inequality \(2x + y < 10\) is the area below the line. Shade this region.
04

Determine if the region is bounded or unbounded

Analyze the graph to determine if the region is bounded or unbounded. Since the region extends infinitely below the line, it is unbounded.
05

Identify the coordinates of the corner points

As there is only a single straight line, which divides the plane into two unbounded regions, there are no corner points in this case. To summarize: - The region corresponding to the inequality \(2x + y < 10\) is the area below the boundary line \(y = 10 - 2x\). - The region is unbounded. - There are no corner points for this specific problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boundary Line
The boundary line is a crucial component when sketching regions defined by inequalities. To derive a boundary line, one must first take the inequality and express it as an equation by replacing the inequality symbol with an equal sign. For the inequality \(2x + y < 10\), the boundary line equation becomes \(2x + y = 10\).
  • This line helps us divide the coordinate plane into distinct regions, with one region where the inequality holds true.
  • It's important to note that the boundary line itself is not included as part of the solution if the inequality is strict ("<" or ">"), meaning the line is normally drawn dashed to indicate this.
Next, determine the intercepts to sketch the line accurately. Here, the x-intercept is found by setting \(y = 0\), giving us the point \((5,0)\). The y-intercept is found by setting \(x = 0\), resulting in the point \((0,10)\). Using these points, you can create a straight line that forms the boundary between the regions.
Coordinate Plane
The coordinate plane is a two-dimensional surface on which we can plot equations and inequalities. It consists of two perpendicular lines, the x-axis (horizontal) and the y-axis (vertical), which intersect at the origin (0,0). This plane enables us to visualize solutions to equations or inequalities by marking points or shading regions.When plotting our inequality \(2x + y < 10\), the boundary line divides the plane into two half-planes. We must determine which side of this line satisfies the inequality. One effective strategy is using a test point, commonly \((0, 0)\), to verify which region should be shaded. In this instance, since \(0 < 10\), \((0, 0)\) satisfies the inequality, indicating that the region containing this point is the solution region. This visual depiction on the coordinate plane is invaluable for understanding relationships defined by inequalities.
Linear Inequalities
Linear inequalities extend the concept of linear equations by introducing inequality symbols like "<", "\>" along with "\(leq\)" and "\(geq\)". Instead of fixing on a line of solutions, they describe a region in the coordinate plane that represents all possible solutions.
  • For the inequality \(2x + y < 10\), it doesn't just describe a single path or line but a half-plane of solutions.
  • These solutions are the collection of points that satisfy the inequality's conditions.
To find out which portion of the plane satisfies the inequality: - Draw the boundary line for \(2x + y = 10\) as a dashed line (since the inequality does not include the boundary line itself).- Choose a test point not on the boundary, such as \((0, 0)\). If \((0, 0)\) satisfies the inequality, then shade the side of the line where \((0, 0)\) resides.By understanding these steps, you can effectively visualize any linear inequality's solution on the coordinate plane as a shaded region, showing an infinite number of potential solutions within a designated area.

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Most popular questions from this chapter

Explain the need for Phase I in a nonstandard LP problem.

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Explain the need for Phase II in a nonstandard LP problem.

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