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$$ \begin{array}{ll} \text { Maximize } & p=2 x+y \\ \text { subject to } & x+2 y \leq 6 \\ & -x+y \leq 2 \\ & x \geq 0, y \geq 0 . \end{array} $$

Short Answer

Expert verified
The solution to the given linear programming problem is \((x, y) = (4, 1)\), with the maximum value of the objective function being \(p = 9\).

Step by step solution

01

Graph the feasible region

First, we will graph the constraints inequalities on the coordinate plane. To do this, change each inequality into an equation and plot it. For example, \(x + 2y \leq 6\) is equivalent to \(x + 2y = 6\). Plot this equation along with the other constraints, and shade the feasible region that satisfies all the inequalities.
02

Identify the vertices of the feasible region

Find the intersection points of the constraint lines; these will be the vertices of the feasible region. To do this, solve the systems of linear equations generated by the constraints, such as: 1. \(x + 2y = 6\) and \(-x + y = 2\) 2. \(x + 2y = 6\) and \(x = 0\) 3. \(-x + y = 2\) and \(x = 0\) 4. \(x = 0\) and \(y = 0\) By solving these systems of equations, we get the following vertices of the feasible region: \((0, 0)\), \((0, 2)\), \((2, 2)\), and \((4, 1)\).
03

Evaluate the objective function at the vertices

Now, calculate the value of the objective function \(p = 2x + y\) at each of the vertices obtained in Step 2: 1. At \((0,0)\): \(p = 2(0) + 0 = 0\) 2. At \((0,2)\): \(p = 2(0) + 2 = 2\) 3. At \((2,2)\): \(p = 2(2) + 2 = 6\) 4. At \((4,1)\): \(p = 2(4) + 1 = 9\)
04

Identify the maximum value for the objective function

Compare the values of the objective function at the vertices. Since we are maximizing the objective function in this problem, look for the largest value: 1. At \((0,0)\): \(p = 0\) 2. At \((0,2)\): \(p = 2\) 3. At \((2,2)\): \(p = 6\) 4. At \((4,1)\): \(p = 9\) The maximum value for the objective function is \(p = 9\), and it occurs at the vertex \((4, 1)\). Therefore, the solution to this problem is \((x, y) = (4, 1)\), with the maximum value of the objective function being \(p = 9\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Feasible Region Graphing
Linear programming involves finding the optimum value of a linear function, subject to a set of constraints. The first step to solving such problems is visualizing the constraints by graphing them on a coordinate plane. This process, known as feasible region graphing, transforms inequalities into equalities to obtain the boundary lines. Each line represents a constraint, and the shaded area, where all these constraints overlap, is the feasible region. It defines the set of all possible solutions that satisfy the given inequalities.

Graphing may seem simple, but it's a powerful way to quickly gain insights into the nature of the problem. It shows us where constraints limit us and guides us to the next step, identifying the vertices of this region. By plotting points such as \(0,0\), \(0,2\), \(2,2\), and \(4,1\), and shading the common area, students can visualize their solution space.
System of Linear Equations
A system of linear equations consists of two or more linear equations with the same set of variables. In linear programming, these systems arise from the intersection of the boundary lines of constraints. Solving these equations yields the vertices of the feasible region, which are crucial for determining the optimum solution.

In our exercise example, the intersection points \(x + 2y = 6\) and \( -x + y = 2\) are among those that need to be determined. Students can use various methods like substitution, elimination, or matrix operations to find solutions for such systems. Understanding the method of solving these systems strengthens the foundation and leads towards finding the optimal solution to the linear programming problem.
Objective Function Evaluation
After graphing the feasible region and identifying its vertices, the next critical step is the objective function evaluation. It involves computing the value of the objective function at each vertex to identify which one gives us the 'best' (in this case, the maximum) value. The objective function, usually denoted by \(z\), \(p\), or another variable, represents what we are trying to maximize or minimize.

In our example, \(p = 2x + y\) is the objective function, and we calculate its value for all the vertices such as \( (0,0), (0,2), (2,2),\) and \( (4,1) \). The objective function evaluation is fundamentally about translating the problem from geometrical interpretation back to numerical to pinpoint the exact optimal solution.
Maximization Problem
The ultimate goal we are trying to achieve in a linear programming problem can be a maximization problem or a minimization problem. Our example features a maximization problem, where we seek the highest possible value of the given objective function. After calculating the objective function's value at each feasible region's vertex, we compare these values to find the highest one, which will be the optimal solution.

Understanding maximization in linear programming is pivotal as it has numerous applications in real-world scenarios such as profit maximization, resource allocation, and operational efficiency. The highest value of \(p = 9\) occurs at the vertex \( (4,1)\), meaning to achieve the maximum profit (or any other measure addressed by the function \(p\)), we should choose the strategy corresponding to this vertex.

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Most popular questions from this chapter

Agriculture \(^{30}\) Your farm encompasses 900 acres, and you are planning to grow soybeans, corn, and wheat in the coming planting season. Fertilizer costs per acre are: \(\$ 5\) for soybeans, \(\$ 2\) for corn, and \(\$ 1\) for wheat. You estimate that each acre of soybeans will require an average of 5 hours of labor per week, while tending to corn and wheat will each require an average of 2 hours per week. Based on past yields and current market prices, you estimate a profit of \(\$ 3,000\) for each acre of soybeans, \(\$ 2,000\) for each acre of corn, and \(\$ 1,000\) for each acre of wheat. You can afford to spend no more than \(\$ 3,000\) on fertilizer, but your labor union contract stipulates at least 2,000 hours per week of labor. How many acres of each crop should you plant to maximize total profits? In this event, will you be using more than 2,000 hours of labor?

Solve the LP problems. If no optimal solution exists, indicate whether the feasible region is empty or the objective function is unbounded. \(\nabla\) Maximize \(p=x+y\) subject to \(\begin{aligned} x+2 y & \geq 10 \\ 2 x+2 y & \leq 10 \\ 2 x+y & \geq 10 \\ x \geq 0, y & \geq 0 . \end{aligned}\)

\(\nabla\) Transportation Scheduling Your publishing company is about to start a promotional blitz for its new book, Physics for the Liberal Arts. You have 20 salespeople stationed in Chicago and 10 in Denver. You would like to fly at least 10 into Los Angeles and at least 15 into New York. A round-trip plane flight from Chicago to LA costs \(\$ 195 ;{ }^{.37}\) from Chicago to \(\mathrm{NY}\) costs \(\$ 182 ;\) from Denver to LA costs \(\$ 395\); and from Denver to NY costs \(\$ 166\). How many salespeople should you fly from each of Chicago and Denver to each of LA and NY to spend the least amount on plane flights?

$$ P=\left[\begin{array}{rrrr} -1 & 1 & 2 & -1 \\ 2 & -1 & -2 & -3 \\ 1 & 2 & 0 & 1 \\ 0 & 2 & 3 & 3 \end{array}\right] $$

Transportation Scheduling (This exercise is almost identical to Exercise 26 in Section \(2.3\) but is more realistic; one cannot always expect to fill all orders exactly, and keep all plants operating at 100 percent capacity.) The Tubular Ride Boogie Board Company has manufacturing plants in Tucson, Arizona, and Toronto, Ontario. You have been given the job of coordinating distribution of the latest model, the Gladiator, to their outlets in Honolulu and Venice Beach. The Tucson plant, when operating at full capacity, can manufacture 620 Gladiator boards per week, while the Toronto plant, beset by labor disputes, can produce only 410 boards per week. The outlet in Honolulu orders 500 Gladiator boards per week, while Venice Beach orders 530 boards per week. Transportation costs are as follows: Tucson to Honolulu: \(\$ 10\) per board; Tucson to Venice Beach: \(\$ 5\) per board; Toronto to Honolulu: \(\$ 20\) per board; Toronto to Venice Beach: \(\$ 10\) per board. Your manager has informed you that the company's total transportation budget is \(\$ 6,550\). You realize that it may not be possible to fill all the orders, but you would like the total number of boogie boards shipped to be as large as possible. Given this, how many Gladiator boards should you order shipped from each manufacturing plant to each distribution outlet?

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