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Use Gauss-Jordan row reduction to solve the given systems of equation. We suggest doing some by hand, and others using technology. HINT [See Examples 1-6.] $$ \begin{aligned} &2 x-3 y=2 \\ &6 x-9 y=3 \end{aligned} $$

Short Answer

Expert verified
The short answer to the given system of equations using Gauss-Jordan row reduction is: \( \begin{aligned} x &= \frac{3}{2}y \\ z &= 1 \end{aligned} \) where \(y\) can be any real number, while \(x\) and \(z\) depend on \(y\).

Step by step solution

01

Write the given system of equations in augmented matrix form

We can represent the given system of equations as an augmented matrix: \[ \left(\begin{array}{ccc} 2 & -3 & 2 \\ 6 & -9 & 3 \end{array}\right) \]
02

Perform Elementary Row Operations (EROs) to reach the Reduced Row Echelon Form (RREF)

Let's start by dividing the first row by 2 to get a leading 1 in the first row: \[ \left(\begin{array}{ccc} 1 & -\frac{3}{2} & 1 \\ 6 & -9 & 3 \end{array}\right) \] Now, our goal is to eliminate the 6 in the second row, first column. We can do this by subtracting 6 times the first row from the second row: \[ \left(\begin{array}{ccc} 1 & -\frac{3}{2} & 1 \\ 0 & 0 & -3 \end{array}\right) \] Next, we divide the second row by -3 to get a 1 in the second row, last column: \[ \left(\begin{array}{ccc} 1 & -\frac{3}{2} & 1 \\ 0 & 0 & 1 \end{array}\right) \] Finally, we add the second row to the first row in order to have a 0 in the last column of the first row: \[ \left(\begin{array}{ccc} 1 & -\frac{3}{2} & 0 \\ 0 & 0 & 1 \end{array}\right) \]
03

Interpret the Reduced Row Echelon Form (RREF)

Our RREF augmented matrix corresponds to the following system of equations: \( \begin{aligned} x - \frac{3}{2}y &= 0 \\ z &= 1 \end{aligned} \) From this system, we can see that the only variable that has a unique solution is \(z=1\). The variable \(x\) depends on the variable \(y\), so we can express \(x\) in terms of \(y\). Rearrange the first equation and express \(x\) as a function of \(y\): $$ x = \frac{3}{2}y. $$ To summarize the solution, we have: \( \begin{aligned} x &= \frac{3}{2}y \\ z &= 1 \end{aligned} \) Here, \(y\) can be any real number, while \(x\) and \(z\) depend on \(y\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

System of Linear Equations
When faced with a system of linear equations, like the pair \(2x - 3y = 2\) and \(6x - 9y = 3\), we're essentially looking at multiple linear equations that we are aiming to solve together. Each equation represents a straight line, and the solutions to the system are the points where the lines intersect.

In our case, the two equations have the same ratio for the coefficients of \(x\) and \(y\), which suggests that the lines may either be parallel (no intersection) or coincident (infinite intersections). To determine which scenario they present, we typically manipulate the equations in a way that allows us to either isolate one variable in terms of the others or identify if there's an inconsistency or dependency.
Elementary Row Operations
Elementary row operations are the bread and butter of solving systems of equations with matrices. They involve three types of moves we can perform:
  • Swapping two rows
  • Multiplying a row by a non-zero constant
  • Adding or subtracting multiples of one row to another
These operations won't change the solution set of the system but will help to simplify the matrix into a form where the solutions can be read off directly.

In the given problem, dividing the first row by 2 and then using a multiple of the first row to eliminate the leading coefficient in the second row are excellent examples of elementary row operations. They tactfully transform the matrix into a simpler form that will ultimately lead us to the solution.
Reduced Row Echelon Form
To get to the answers of our system, we aim for the Reduced Row Echelon Form (RREF). This special matrix format has certain characteristics:
  • Each leading entry in a row is 1 (also known as a pivot).
  • Each pivot is to the right of the pivots in the above row.
  • All entries above and below each pivot are zeros.
  • If there are rows of all zeros, they are at the bottom.
The Gauss-Jordan elimination method is a process we use to get to RREF, and once we're there, each equation represented by the matrix points directly to a solution.

However, in some cases, like the one in the exercise, reaching RREF reveals that we can't find a unique solution for each variable, indicating either a dependent system or a system with no solution at all.
Augmented Matrix Representation
An augmented matrix is a powerful tool to represent our system of linear equations compactly as a single matrix, which includes both the coefficients of the variables and the constants from the right-hand sides of the equations. Here's how it looks for our initial system:\[\left(\begin{array}{ccc}2 & -3 & 2 \6 & -9 & 3\end{array}\right)\]

This visual simplification allows us to apply elementary row operations across the entire matrix and focus on transforming it into RREF. The final step—interpreting the RREF—can effortlessly tell us the nature of the solutions. In some situations, as we've seen, the augmented matrix helps to highlight that some equations in the system are actually multiples of each other and therefore don't contribute additional information, revealing dependencies between the variables.

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Most popular questions from this chapter

Equilibrium Price The demand and supply functions for your college newspaper are, respectively, \(q=-10,000 p+2,000\) and \(q=4,000 p+600\), where \(p\) is the price in dollars. At what price should the newspapers be sold so that there is neither a surplus nor a shortage of papers? HINT [See Example 7.]

Use Gauss-Jordan row reduction to solve the given systems of equation. We suggest doing some by hand, and others using technology. HINT [See Examples 1-6.] $$ \begin{aligned} x-\frac{1}{2} y &=0 \\ \frac{1}{2} x-\quad \frac{1}{2} z &=-1 \\ 3 x-y-z &=-2 \end{aligned} $$

Use technology to obtain approximate solutions graphically. All solutions should be accurate to one decimal place. Find the intersection of the line through \((0,1)\) and \((4.2,2)\) and the line through \((2.1,3)\) and \((5.2,0)\).

I n ~ t h e ~ \(1990 \mathrm{~s}\), significant numbers of tourists traveled from North America and Europe to Australia and South Africa. In 1998 , a total of \(1,390,000\) of these tourists visited Australia, while \(1,140,000\) of them visited South Africa. Further, 630,000 of them came from North America and \(1,900,000\) of them came from Europe. \({ }^{21}\) (Assume no single tourist visited both destinations or traveled from both North America and Europe.) a. The given information is not sufficient to determine the number of tourists from each region to each destination. Why? b. If you were given the additional information that a total of \(2,530,000\) tourists traveled from these two regions to these two destinations, would you now be able to determine the number of tourists from each region to each destination? If so, what are these numbers? c. If you were given the additional information that the same number of people from Europe visited South Africa as visited Australia, would you now be able to determine the number of tourists from each region to each destination? If so, what are these numbers?

A bagel store orders cream cheese from three suppliers, Cheesy Cream Corp. (CCC), Super Smooth \& Sons (SSS), and Bagel's Best Friend Co. (BBF). One month, the total order of cheese came to 100 tons (they do a booming trade). The costs were \(\$ 80, \$ 50\), and \(\$ 65\) per ton from the three suppliers respectively, with total cost amounting to \(\$ 5,990\). Given that the store ordered the same amount from \(\mathrm{CCC}\) and \(\mathrm{BBF}\), how many tons of cream cheese were ordered from each supplier?

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