/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Urban Community College is plann... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Urban Community College is planning to offer courses in Finite Math, Applied Calculus, and Computer Methods. Each section of Finite Math has 40 students and earns the college \(\$ 40,000\) in revenue. Each section of Applied Calculus has 40 students and earns the college \(\$ 60,000\), while each section of Computer Methods has 10 students and earns the college \(\$ 20,000\). Assuming the college wishes to offer a total of six sections, to accommodate 210 students, and to bring in \(\$ 260,000\) in revenues, how many sections of each course should it offer? HINT [See Example 2]

Short Answer

Expert verified
There is no possible solution to offer six sections accommodating 210 students and bring in $ \$ 260,000$ in revenues with the given constraints for Finite Math, Applied Calculus, and Computer Methods. The college should reevaluate their constraints or expectations.

Step by step solution

01

Assign variables

Let's assign variables to the number of sections for each course: - Let x be the number of sections of Finite Math - Let y be the number of sections of Applied Calculus - Let z be the number of sections of Computer Methods
02

Set up the system of equations

Now we can set up a system of linear equations based on the given information: 1. The total number of sections: x + y + z = 6 2. The total number of students: 40x + 40y + 10z = 210 3. The total amount of revenue: 40,000x + 60,000y + 20,000z = 260,000
03

Solve the system of equations

To solve this system of equations, we can use either substitution or elimination method. We'll use the elimination method: First, let's multiply equation (1) by 40,000 so that we can eliminate x variable from equations (3) and (1): 40,000x + 40,000y + 40,000z = 240,000 Now subtract equation (1) from equation (3): 20,000y - 20,000z = 20,000 So, we have: y - z = 1 (4) Next, we will multiply equation (1) by -40 to eliminate x from equation (2): -40x - 40y - 40z = -240 Now add equation (-2) to equation (2): -10z = 30 So, we have z = -3 Now as we have z, substitute it in equation (4): y - (-3) = 1 y = -2 Finally, substitute y and z values in equation (1): x - 2 - 3 = 6 x = 11 However, the number of sections cannot be negative. Thus, there's no solution to the problem if we have the given constraints. The college should reevaluate their constraints or expectations on the number of students and revenue since it's not possible to meet all of their constraints simultaneously with the given information.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Algebra
Linear algebra is a branch of mathematics that deals with vectors, matrices, and systems of linear equations. In real-world applications, such as the problem facing Urban Community College, it plays a crucial role in finding solutions that involve multiple variables and conditions.
For instance, we can represent the college's requirements in terms of mathematics. The number of sections, students, and revenue goals can be expressed as linear equations:
- The sum of course sections = total sections
- The sum of students in all courses = total students
- The sum of revenues from courses = total revenue
By using matrices, these complex relationships can be organized and solved efficiently. Detailing problems in linear equations lets us use certain methods, such as elimination, to solve them step by step. Solving with matrices involves aligning equations into orderly forms to apply techniques for finding answers.
  • A clear understanding of linear algebra provides tools to model problems efficiently.
  • It helps analyze systems with constraints represented by multiple equations.
  • Matrices serve as a straightforward way to perform and visualize operations easily.
This kind of problem-solving framework is indispensable in planning and optimizing real-world scenarios, as evident from the Urban Community College's problem setup.
Finite Mathematics
Finite mathematics includes topics that are incredibly useful for practical applications such as business, social sciences, and management. In this scenario, it applies to the planning of resources at Urban Community College.
This branch of mathematics deals with understanding the finite quantities available, such as the number of classes, students, and total revenue. With finite mathematics, calculations or models work within the constraints and limits provided, ensuring no assumptions go beyond realistic outcomes.
  • In the college scenario, finite mathematics allows the assessment of outcomes based on fixed numbers given for class sizes, revenues, and total course offerings.
  • This practical approach prevents overestimating resources, aligning expectations with realities like total students and funds available.
  • Enabling resource allocation in the context of limitations helps in making effective decisions.
Finite mathematics thus supports determining possible options when faced with limited resources, crucially identifying when options need reevaluation—just like the conflicting constraints in the college's situation.
Applied Calculus
Applied calculus extends beyond theoretical explorations to find real-world applications like optimizing systems or understanding changes over time. In settings like Urban Community College, it contributes by offering methods to understand complexities in planning and offerings.
Although not explicitly seen in the original exercise, applied calculus could be used to study functional relationships where changes in one factor might influence others. Changes in the number of sections or students could affect revenues in a non-linear fashion, a concept captured and handled by calculus.
  • It allows modeling growth or changes in variables dynamically.
  • Honing in on optimized results, like maximizing revenue given student numbers and section constraints.
  • Calibrating course arrangements over semesters using calculus can yield improved outcomes.
Thus, while systems of linear equations help identify current solutions, applied calculus equips planners with insights into maximizing effectiveness over time, potentially offering guidance in decision-making for future terms.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Your other friend Hans tells you that because he is solving a consistent system of five linear equations in six unknowns, he will get infinitely many solutions. Comment on his claim.

Things have not been going too well here at Accurate Accounting, Inc. since we hired Todd Smiley. He has a tendency to lose important documents, especially around April, when tax returns of our business clients are due. Today Smiley accidentally shredded Colossal Conglomerate Corp.'s investment records. We must therefore reconstruct them based on the information he can gather. Todd recalls that the company earned an \(\$ 8\) million return on investments totaling \(\$ 65\) million last year. After a few frantic telephone calls to sources in Colossal, he learned that Colossal had made investments in four companies last year: X, Y, Z, and W. (For reasons of confidentiality, we are withholding their names.) Investments in company X earned \(15 \%\) last year, investments in Y depreciated by \(20 \%\) last year, investments in \(Z\) neither appreciated nor depreciated last year,while investments in W earned \(20 \%\) last year. Smiley was also told that Colossal invested twice as much in company \(X\) as in company \(Z\), and three times as much in company \(\mathrm{W}\) as in company \(Z\). Does Smiley have sufficient information to piece together Colossal's investment portfolio before its tax return is due next week? If so, what does the investment portfolio look like?

Use Gauss-Jordan row reduction to solve the given systems of equation. We suggest doing some by hand, and others using technology. HINT [See Examples 1-6.] $$ \begin{aligned} 0.25 x-0.5 y &=0 \\ 0.2 x+0.2 y-0.2 z &=-0.6 \\ 0.5 x-1.5 y+\quad z &=0.5 \end{aligned} $$

Use Gauss-Jordan row reduction to solve the given systems of equation. We suggest doing some by hand, and others using technology. HINT [See Examples 1-6.] $$ \begin{aligned} x+y+5 z &=1 \\ y+2 z+w &=1 \\ x+y+5 z+w &=1 \\ x+2 y+7 z+2 w &=2 \end{aligned} $$

Use technology to solve the systems of equations. Express all solutions as fractions. $$ \begin{aligned} 4 x-2 y+z+w &=20 \\ 3 y+3 z-4 w &=2 \\ 2 x+4 y-w &=4 \\ x+3 y+3 z &=2 \end{aligned} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.