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Recall from Section \(14.4\) that the total income received from time \(t=a\) to time \(t=b\) from a continuous income stream of \(R(t)\) dollars per year is $$\text { Total value }=T V=\int_{a}^{b} R(t) d t$$ Find the total value of the given income stream over the given period. \(R(t)=100,000-2,000 \pi \sin (\pi t), 0 \leq t \leq 1.5\)

Short Answer

Expert verified
The total value of the given income stream over the given time period is \(TV = 150,000\).

Step by step solution

01

Write down the given function and integral

The income stream function is given by: \(R(t) = 100,000 - 2,000\pi\sin(\pi t)\), and we need to find the total value over the interval \([0, 1.5]\). We will calculate the definite integral of this function over this interval: \[TV = \int_{0}^{1.5} (100,000 - 2,000\pi\sin(\pi t)) dt\]
02

Break the integral into separate parts

Now we break the integral into separate parts for each term in the function: \[TV = \int_{0}^{1.5} 100,000 dt - 2,000\pi\int_{0}^{1.5} \sin(\pi t) dt\]
03

Integrate each term

Next, we will integrate each term separately: For the first part, \(\int 100,000 dt = 100,000t\). For the second part, we use the substitution method. Let \(u = \pi t\), then \(du/dt = \pi\), and so \(dt = du/\pi\). The definite integral becomes: \[\int \sin(u) \frac{du}{\pi}\] Now, we integrate the sine function: \[\int \sin(u) du = -\cos(u)\] Now substitute back \(u = \pi t\), and we have: \[-\frac{1}{\pi}\cos(\pi t)\]
04

Apply the integration limits

Now we have the combined integral expression: \[TV = 100,000t - 2,000\pi(-\frac{1}{\pi}\cos(\pi t))\] Now, evaluate the expression at the limits \(t=0\) and \(t=1.5\), and find the difference: \(TV = (100,000(1.5) - 2,000\cos(\pi (1.5))) - (100,000(0) - 2,000\cos(\pi (0)))\)
05

Simplify and find the total value

Simplify this expression to obtain the total value: \(TV = (150,000 - 2,000\cos(1.5\pi)) - (0 - 2,000\cos(0))\) \(TV = 150,000 - 2,000\cos(1.5\pi) + 2,000\cos(0)\) Since the cosine of \(1.5\pi\) is 1 and the cosine of 0 is also 1, the expression becomes: \(TV = 150,000 - 2,000(1) + 2,000(1)\) \(TV = 150,000\) So, the total value of the given income stream over the given time period is $150,000.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Income Stream Function
In the world of finance and economics, understanding how money flows over time is crucial. An income stream function, like the one provided in our textbook exercise, represents how much revenue or money is being earned at any given moment. It is depicted as a function of time, denoted by the variable, usually expressed as R(t).

For instance, the provided exercise includes an income stream function defined as R(t) = 100,000 - 2,000πsin(πt). This indicates that the income at any time t can be determined by this particular mathematical expression. A flat income of 100,000 dollars is affected by a sinusoidal fluctuation, which represents seasonal or periodic changes in the income over time.

To assist in making these concepts more tangible, consider a business that has a base income but also sees a predictable rise and fall in revenue throughout the year due to seasonal effects - that's what the sine wave in our function could represent.
Integration Techniques
Calculus offers multiple integration techniques that allow us to solve complex equations, including the income stream function in our exercise. The most straightforward method is to integrate each term of a function independently, as seen in the second step of our solution.

The linear term is simple to integrate and yields 100,000t. However, when dealing with the trigonometric term, we leverage substitution integration, which is particularly effective for functions involving trigonometric expressions. The substitution method involves changing variables to simplify the integral. As in our solution, by setting u = πt, we transformed the problem into a basic trigonometric integral that's easier to solve.

To demystify this step for students, think of substitution as finding a simpler way to look at a problem. It's like translating a difficult word into layman's terms to understand its meaning before putting it back into the original context. By applying this approach, even the most complex integrals can become approachable.
Calculus in Economics
Calculus is an invaluable tool in economics, providing a way to model and analyze dynamic systems. Specifically, definite integrals, as demonstrated in our problem, enable economists to quantify total values over a period – these might represent total income, costs, or other economic measures.

By calculating the area under the curve of an income stream function over a specified interval, we obtain the total income generated during that period. This is essential in forecasting, budget planning, and financial analysis. The concrete example we have just analyzed represents a situation where a company has a predictable income pattern over 1.5 years, and calculus helps in calculating the total revenue generated in that period.

Therefore, calculus in economics isn't just about abstract equations; it's about practical application. It helps in making informed decisions based on the ebb and flow of economic variables and allows the understanding of trends and total effects that simple arithmetic cannot provide.

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Most popular questions from this chapter

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