/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 60 Moving Average of an Exponential... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Moving Average of an Exponential Function Find a formula for the \(a\) -unit moving average of a general exponential function \(f(x)=A e^{k x}\).

Short Answer

Expert verified
The a-unit moving average of a general exponential function \(f(x)=Ae^{kx}\) can be found using the formula: \[ \overline{f}(x) = \frac{A}{ak}\left( e^{k(x+a)} - e^{kx} \right). \]

Step by step solution

01

Define the moving average

We start by defining the moving average \(\overline{f}(x)\) of the function \(f(x)=Ae^{kx}\) by taking the average of the function over the interval \([x, x+a]\), \[ \overline{f}(x) = \frac{1}{a} \int_{x}^{x+a} f(t) dt. \]
02

Substitute the exponential function into the moving average formula

Now, we substitute the given function, \(f(x)=Ae^{kx}\), into the moving average formula and perform the definite integration, \[ \overline{f}(x) = \frac{1}{a} \int_{x}^{x+a} A e^{kt} dt. \]
03

Integrate the function

Integrate the exponential function with respect to t, \[ \overline{f}(x) = \frac{1}{a} \left[ \frac{A e^{kt}}{k} \right]_{x}^{x+a}. \]
04

Evaluate the definite integral

Evaluate the definite integral at the limits x and x+a, \[ \overline{f}(x) = \frac{1}{a} \left( \frac{A e^{k(x+a)}}{k} - \frac{A e^{kx}}{k} \right). \]
05

Simplify the expression

Simplify the expression by factoring out the common terms, \[ \overline{f}(x) = \frac{A}{a k} \left( e^{k(x+a)} - e^{kx} \right). \] Now, we have found a formula for the a-unit moving average of a general exponential function \(f(x)=Ae^{kx}\): \[ \overline{f}(x) = \frac{A}{ak}\left( e^{k(x+a)} - e^{kx} \right). \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Function
An exponential function is a mathematical expression in which a constant base is raised to a variable power. The general form is written as \( f(x) = A e^{kx} \) where:
  • \( A \) is a constant that represents the initial value or amplitude.
  • \( e \) is the base of the natural logarithm, approximately 2.718.
  • \( k \) is the growth (if positive) or decay (if negative) rate.
  • \( x \) is the variable or exponent.
Exponential functions are commonly used to model real-world situations where quantities grow or shrink at a constant rate, such as population growth, radioactive decay, and compound interest.
In the context of moving averages, understanding exponential functions is important as they help describe how values change over an interval.
The function \( f(x) = A e^{kx} \) depicts a consistently growing or shrinking process over time, providing a base for computing averages.
Definite Integration
Definite integration is a process used to calculate the accumulated area under a curve, from one point to another, on a graph. It is represented as \( \int_{a}^{b} f(x) \, dx \) where:
  • \( f(x) \) is the function being integrated.
  • \( a \) and \( b \) are the lower and upper limits of the interval of integration.
  • \( dx \) signifies that the integration is done with respect to \( x \).
Definite integrals are pivotal when computing moving averages as they sum up the total value of a function over a specific range. This is then divided by the interval to find the average value over that range.
In the case of the solution provided, we use definite integration to determine the average value of the exponential function \( f(x) = A e^{kx} \) over the interval \([x, x+a]\).
The formula \( \int_{x}^{x+a} A e^{kt} \, dt \) evaluates how the function behaves between these points, facilitating the calculation of its moving average.
Mathematical Formula
A mathematical formula is an equation that aims to describe a rule or relation between different mathematical expressions. In this exercise, the formula for the moving average of an exponential function is derived using these steps:
  • Start with defining the average over a specific interval.
  • Substitute the given function into the integration process to consider the behavior of the function over the interval.
  • Use integration to account for the continuous nature of exponential decay or growth.
  • Simplify the formula by factoring out common elements to reveal the final expression.
The resulting formula, \( \overline{f}(x) = \frac{A}{ak}\left( e^{k(x+a)} - e^{kx} \right) \), provides a concise way to compute the average value for any given interval, encapsulating the principles of exponential functions and integration.
Mathematical formulas like this are invaluable because they allow us to perform complex calculations efficiently and accurately, forming the backbone of mathematics in modeling and problem-solving.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of the following integrals are improper, and why? (Do not evaluate any of them.) a. \(\int_{-1}^{1} \frac{|x|}{x} d x \quad\) b. \(\int_{-1}^{1} x^{-1 / 3} d x \quad\) c. \(\int_{0}^{2} \frac{x-2}{x^{2}-4 x+4} d x\)

Ie Logistic Equation There are many examples of growth in which the rate of growth is slow at first, becomes faster, and then slows again as a limit is reached. This pattern can be described by the differential equation $$ \frac{d y}{d t}=a y(L-y) $$ where \(a\) is a constant and \(L\) is the limit of \(y\). Show by substitution that $$ y=\frac{C L}{e^{-a L t}+C} $$ is a solution of this equation, where \(C\) is an arbitrary constant.

Hair Mousse Sales The amount of extremely popular hair mousse sold online at your Web site can be approximated by \(N(t)=\frac{80(7)^{t}}{20+7^{t}}\) million gallons per year. \((t=0\) represents the current year.) Investigate the integrals \(\int_{0}^{+\infty} N(t) d t\) and \(\int_{-\infty}^{0} N(t) d t\) and interpret your answers.

Revenue from New Home Sales Revenue from the sale of new homes in the United States decreased dramatically from 2006 to 2008 as shown in the model \(r(t)=321 e^{-0.429 t}\) billion dollars per year \(\quad(0 \leq t \leq 2)\) where \(t\) is the year since \(2006 .{ }^{42}\) If this trend were to have continued into the indefinite future, estimate the total revenue from the sale of new homes in the United States from 2006 on. HINT [See Example 1.]

Your other study group friend says that the present value of a continuous stream of income can sometimes be greater than the total value, depending on the (positive) interest rate. Is he correct? Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.